flame keeper reaction
Determination of Phosphorus in Flame Reaction
The flame reaction test for the determination of the potassium ion mainly had the following steps: First, the platinum wire was dipped in concentrated sulfuric acid and burned on a colorless flame until it was colorless. Then, the sample was dipped in the colorless flame and burned. Then, the color of the flame was observed through the blue Cobalt Glass. If the flame was purple, it meant that the sample contained the potassium ion. Otherwise, it did not. After the experiment, the platinum wire was dipped in concentrated sulfuric acid and burned until it was colorless. In the flame reaction, because the yellow color of the Na flame might cover up the color of the K flame, it had to be observed with blue Cobalt Glass. This method originated from Bunsen's experiment.
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2026-07-04 04:36
How to distinguish the flame reaction
The flame reaction was a reaction in which certain metals or their compounds caused the flame to show a special color when burned in a colorless flame. It could be distinguished by observing the color of the flame. The flame reaction colors of common metals were: Na yellow, Li purple, K purple, rubidium light purple, calcium brick, Stronghold red, copper green, Ba yellow green. When conducting a flame reaction experiment, a clean platinum wire (or iron wire) was usually used to burn the flame outside the alcohol lamp until the color was the same as before (to prevent impurities on the platinum wire from interfering with the test). Then, the metal wire was dipped in the solution to be tested and burned to observe the color of the flame. Because of the possible use of Na in the production of potash, the solution of potash ions often contained Na ions, and the flame reaction of Na was yellow, which was difficult to distinguish from a small amount of purple. Therefore, when observing the flame color of potash, it was necessary to observe it through a blue-colored glass to eliminate the interference of the flame color of Na. In chemistry, the flame reaction was often used to identify whether a certain metal existed in a compound, such as identifying a solution of NaCl2 and a solution of KCl2. The flame color was yellow for the NaCl2 solution, and the flame color was purple for the KCl2 solution.
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2026-07-04 11:23
Flame reaction experiment of chemical iron
There was no flame reaction on iron, or the frequency of the photon emitted by the iron after being excited had fallen outside the visible light, so the flame reaction experiment on iron could not be carried out.
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2026-07-01 10:06
Materials needed for the flame reaction of potassium
The materials needed for the flame reaction of potassium were as follows:
1. Platinum wire: used to dip the sample.
2. "Acid: Before the flame reaction, dip the platinum wire in acid and burn it on a colorless flame until it is colorless to remove the interference of impurities on the experiment.
3. Test sample (the solid can be directly dipped in, and the solution of the potassium ion can also be dipped in).
4. Blue Cobalt Glass: Because most of the time, the production of potassium requires the use of Na, and the solution of potassium ions often contains Na ions, and the flame reaction of Na is yellow. Yellow and a small amount of purple cannot be distinguished, so the flame reaction of potassium needs to be observed through blue Cobalt Glass. Blue Cobalt Glass can filter out the yellow light.
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2026-07-01 20:53
Flame Reaction Experiment of Na Salt
The flame reaction of the salt should not be difficult to do, but it was actually more troublesome because the flame color of the salt was yellow, and the flame of the alcohol lamp was mostly yellow due to the unclean wick of the lamp and the impure alcohol. Even if the flame was almost colorless (light blue), when a new iron wire (or a nickel-based wire, platinum-based wire) was placed on the outer flame, the flame would still be yellow at the beginning. It was difficult to tell whether the flame color was the color of the original alcohol lamp or the color of the salt ion. To clearly see the yellow flame of Na, you can use the following method:
1. Forceps-cotton-alcohol method: Take a small ball of cotton (cotton wool) with a pair of tweezers and absorb a little alcohol (95% alcohol). Squeeze the alcohol on the cotton dry, then dip the cotton in some salt or waterless soda powder (grind it into fine powder) and ignite it.
2. Iron wire method:
- He took a thin iron wire, wiped one end with sandpaper, and burned it on the flame of the alcohol lamp until there was no yellow flame.
- Dip the end of the wire in water and then dip it in some salt or powder of the Na2CO3.
- Light up a new spirit lamp (the wick of the lamp is clean and the spirit is pure).
- The iron wire dipped in the powder of the salt was placed on the tip of the outer flame to burn. At this time, there was a small yellow flame on the tip of the outer flame, which was the salt flame. For students 'experiments, since most alcohol lamps were not clean, it was difficult to see the tip of the flame. Instead, a steel wire stained with salt could be placed in any part of the outer flame where there was a blue flame to burn. If the yellow flame covered the blue flame, it could be considered that the yellow flame was the salt flame.
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2026-07-05 05:08
Does the flame reaction follow blackbody radiation?
The flame reaction had nothing to do with black body radiation and did not obey black body radiation.
Blackbody radiation refers to the electromagnetic waves emitted by an object when it is subjected to heat. Its characteristic is that the spectral density is proportional to the temperature of the object. It is a random process produced by particles such as electrons and atoms on the surface of the object when they are subjected to heat.
The flame color reaction was to burn a metal or compound in a high-temperature flame. The electrons of the metal atom or compound were excited by the high-temperature flame to jump to the high-energy level orbit. When the electrons returned from the high-energy level orbit to the low-energy level orbit, they released a certain wave length of light according to the energy level difference between different orbits, so that the metal burning flame showed a characteristic color.
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2026-07-05 02:34
Flame reaction between metal and its compound
Many metals or their compounds would produce a special color when burned. This phenomenon was called the flame color reaction. The flame reaction was a special property of the alkali-earth metals. It was a kind of physical change.
In principle, the high-temperature flame caused these substances to be vaporized. The electrons of the metal atoms or compounds were excited by the high-temperature flame to jump to the high-energy level orbit. When the electrons returned from the high-energy level orbit to the low-energy level orbit, they emitted a certain wave length of light according to the energy level difference between the different orbits, so that the metal burning flame presented a characteristic color.
During the flame reaction experiment, a clean platinum wire (or iron wire) could be used to burn the color of the metal in the alcohol lamp until the color was the same as before (to avoid the impurities on the platinum wire interfering with the test). Then, the metal wire was dipped in the solution to be tested and burned to observe the characteristic color of the metal in the solution to be tested. To observe the flame color of the potassium element, it had to be observed through a blue-colored tungsten glass to eliminate the interference of the flame color of the potassium element.
The flame reaction colors of common metals were: Na yellow, Li purple, K purple, rubidium light purple, calcium brick, Stronghold red, copper green, Ba yellow green. The flame reaction was a property of metal elements, whether it was atoms or ions, but not all elements had a special color. In chemistry, the flame reaction was often used to identify metal elements or metal ions. Based on the principle of the flame reaction, it was applied to fireworks, light lamps, and other aspects of life. Spectral analysis developed from the flame reaction was also used to determine various elements and substances.
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2026-09-23 00:58
What kind of substance has a green flame reaction?
The flame reaction of copper and helium was green. In the flame reaction experiment, the flame reaction of copper salt (such as copper sulfuric acid solution dipped in platinum wire) was emerald green or blue-green, and the flame reaction of the element of Ba was yellow-green.
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2026-07-05 21:43
Why can't we use copper for flame reaction?
Copper could be used for flame reaction. The flame reaction of copper was green. During the flame reaction, a sample of copper could be held in a clean and less active metal wire (such as platinum or nickel-ichrome alloy) and placed in a blue flame. The green flame could be observed. This characteristic was also used in the production of fireworks to increase the gorgeous color of fireworks. However, due to the color of copper, in some specific testing situations, if there were multiple elements and the testing requirements were high, the flame color of copper might interfere. However, this did not mean that copper could not be used in the flame color reaction.
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2026-09-14 20:08
Why can't the flame reaction of platinum be done with sulfuric acid?
On the one hand, sulfuric acid was not as volatile as sulfuric acid. When sulfuric acid was heated, it could evaporate quickly without affecting the experimental results, while sulfuric acid was not easy to evaporate, which would affect the experimental results. On the other hand, although platinum was a passive metal, it would still have a certain degree of oxidization in the face of a strong oxidiser such as sulfuric acid. Therefore, it could not be used in the flame reaction of platinum.
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2026-07-02 20:10
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