Kobayashi read one-tenth of the book on the first day. On the second day, he saw four-fifths of the first day, which was 4/5 × 1/10 = 8/10. Therefore, the remaining pages were 1-8/10 = 2/10 of the entire book. There were 123 pages left. Therefore, this book had a total of 123 + 2/10 = 123 + 2 × 1/10 = 123 + 2/5 = 125 pages.
Xiao Hua reads a book on the first day, reads six pages, then reads four more pages every day, and on the third day, he reads two-fifths of the book. According to the question description, Little Light read four more pages every day than the previous day, so the total number of pages per day was the total number of pages on the previous day plus four pages. Therefore, after Little Light read six pages on the first day, the number of pages he read every day was the number of pages from the previous day plus four pages, which was six pages + four pages = ten pages. From the second day onwards, Little Light read four more pages a day than the previous day. Therefore, the number of pages he read every day was the number of pages from the previous day plus four pages, which was 10 pages + 4 pages + 4 pages = 16 pages. By analogy, we can find that when Little Light reads to the n-th day, the number of pages Little Light reads every day is the number of pages from the previous day plus 4 pages, which is n-pages + 4 pages. Therefore, by the third day, Little Light had read 2/5 of the book, which was 32 pages + 4 pages = 36 pages. Therefore, after the third day, Little Light still had 16 pages left to read. The total number of pages in the book was 36, so Little Light needed to read another 16 pages to finish reading.
小明看一本故事书第一天看了30页是全书总页数的五分之三那么第一天看了全书的 $\frac{30}{5}$ 页. 第二天看了全书的十分之一即第二天看了 $\frac{1}{10}$ 页. 因此第二天看了 $\frac{30}{5} \cdot \frac{1}{10} = \frac{3}{5}$ 页. 所以小明在第二天看了 $\frac{3}{5}$ 页也就是全书的 $\frac{3}{5}$ 页.
The information you provided is not detailed enough to determine the total number of pages in this book. Please provide more information so that I can answer your questions.
On the first day, he read three-eighths of the book, which was 40 × 3/8 = 15 pages. The next day, he read two-fifths of the book, which was 40 × 2/5 = 8 pages. Therefore, the answer was that he read eight pages the next day.
The total number of pages in this book is x. On the first day, I read three-fifths of the total number of pages, which is 3/5x pages on the first day. Reading 20% the next day meant reading 20% x 3/5 x = 2/5 x pages. Because he read 2/5x pages the next day, the remaining pages were 1 - 2/5x = 3/5x pages. Because Kobayashi read 3/5x pages, the total number of pages Kobayashi read was 3/5x + 2/5x = 5/5x pages. And because there were still 20 pages left in Kobayashi's book, 20 = 3/5x + 2/5x solved the equation to get x = 120. So this book has 120 pages.
Let the total number of pages in this book be x pages: - I read 3/5x pages on the first day. -20% read the next day =02x pages. According to the meaning of the question, the remaining pages were x-(3/5x+02x)=20 pages. Substituting x=50 pages gives: - I read 3/5 x 50 pages =30 pages on the first day. - The next day, I read 02 x 50 pages =10 pages. Therefore, the book had a total of 50 pages.
Suppose the book has x pages: Little Cong read 15 pages a day for four days, a total of 4×15=60 pages. The total number of pages in the book is x, so: 60÷(1+3/5)=x÷5 The solution was:x=60×5 div3 =600 div3 =200 pages. Therefore, the book had a total of 200 pages.
Little Red reads 15 pages a day for 4 days and still has 3/5 of the book left. She can write the following equation: Remaining pages/pages per day = 3/5 of the book Solve the equation: Remaining pages = 3/5 x pages of the book Substituting the remaining pages into the original book's page count, he obtained: 3/5 x pages of the book = 15 pages Therefore, this book had: 15 pages × 3/5 = 15 pages/3/5 = 150 pages
I'm not sure exactly. It could vary depending on the context or the specific collection of stories. Maybe it's a mystery or a heartwarming tale.