Lin Yun read a 156-page literary work. On the first day, he read 4/9 of the book. On the second day, he read 15/16 of the first day. On the second day, Lin Yun read...

2024-09-06 00:03

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2024-09-06 00:10

Lin Yun read a 156-page literary work. On the first day, he read 4/9 of the book. On the second day, he read 15/16 of the first day. Lin Yun read it on the second day. Assuming that the book had a total of n pages, Lin Yun read 4/9 of the book on the first day (i.e. 4/9 * n), which meant that he read page n of the book. Next, Lin Yun read 15/16 of the number of pages he read on the first day (4/9 * n * 15/16), which meant that he read page n+1. Thus, the number of pages Lin Yun read on the second day was:(15/16) * (4/9 * n + 1) = 15/16 * (n + 4/9 * n). Since n+4/9*n is an integral number, 15/16 * (n + 4/9*n) must be a multiple of 15. Thus, when n was a multiple of 15, the number of pages Lin Yun read on the second day was 15/16 * (n + 4/9*n), which was a multiple of 15. For example, when n is 30, the number of pages Lin Yun reads on the second day is 15/16 *(30 + 4/9 * 25) = 15/16 *(30 + 10/9 * 25) = 15/16 * (35 + 5/18) = 15/16 * (35 + 25/18) = 15/16 * (375 + 125/18) = 15/16 * (375 + 625) = 15/16 * 37 = 45 When n was 15, the number of pages Lin Yun read on the second day was 15/16 * (15 + 4/9 * 15) = 15/16 * (15 + 10/18) = 15/16 * (15 + 5/6) = 15/16 * 20 = 375. When n was 20, the number of pages Lin Yun read on the second day was 15/16 * (20 + 4/9 * 20) = 15/16 * (20 + 10/18) = 15/16 * (20 + 5/6) = 15/16 * 375 = 45. Thus, Lin Yun read a 156-page literary work on the first day and read 4/9 of the book (4/9 * 156). On the second day, he read 15/16 of the first day (4/9 * 156 * 16/15). On the second day, he read 15/16 * (156 + 4/9 * 156).

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2024-09-13 12:42

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2024-09-15 17:07

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1 answer

2024-09-12 14:54

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2024-09-15 15:50

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2024-09-12 15:03

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1 answer

2024-09-10 19:44

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2024-09-19 00:25

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2024-09-16 11:10

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2024-09-12 15:06

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1 answer

2024-09-15 16:40

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