小明看一本故事书第一天看了30页是全书总页数的五分之三那么第一天看了全书的 $\frac{30}{5}$ 页. 第二天看了全书的十分之一即第二天看了 $\frac{1}{10}$ 页. 因此第二天看了 $\frac{30}{5} \cdot \frac{1}{10} = \frac{3}{5}$ 页. 所以小明在第二天看了 $\frac{3}{5}$ 页也就是全书的 $\frac{3}{5}$ 页.
The information you provided is not detailed enough to determine the total number of pages in this book. Please provide more information so that I can answer your questions.
The total number of pages in this book is x. On the first day, I read three-fifths of the total number of pages, which is 3/5x pages on the first day. Reading 20% the next day meant reading 20% x 3/5 x = 2/5 x pages. Because he read 2/5x pages the next day, the remaining pages were 1 - 2/5x = 3/5x pages. Because Kobayashi read 3/5x pages, the total number of pages Kobayashi read was 3/5x + 2/5x = 5/5x pages. And because there were still 20 pages left in Kobayashi's book, 20 = 3/5x + 2/5x solved the equation to get x = 120. So this book has 120 pages.
Let the total number of pages in this book be x pages: - I read 3/5x pages on the first day. -20% read the next day =02x pages. According to the meaning of the question, the remaining pages were x-(3/5x+02x)=20 pages. Substituting x=50 pages gives: - I read 3/5 x 50 pages =30 pages on the first day. - The next day, I read 02 x 50 pages =10 pages. Therefore, the book had a total of 50 pages.
Your question is a little unclear. Can you provide more context information? For example, what is the "book" that you are referring to and why did Xiaoxiao read it? This way, I can better help you answer your questions.
If a book had 180 pages and two-fifths of the total number had been read, then there would be 180 × 2/5 = 72 pages left. The next day, he read one-third of the total, so he had 180 × 3/10 = 24 pages left. Therefore, there were 72 + 24 = 106 pages left in the book.
Xiao Ming read a book on the first day, he read 1/6 of the whole book, the second day, he read 24 pages, the third day, he read the total number of pages in the previous two days If he read 24 pages the next day, he would read (24 div6) = 4 pages the next day. The rest of the books had 5/6 pages. Xiaoming read 1/6 pages on the first day, so he read (5/6 div1/6) = 30 pages on the first day. Xiao Ming's remaining book had 1/6 pages. The number of pages he read the next day was 4 + 30 = 34. Xiao Ming's remaining book had 1/6 pages. The number of pages he read on the third day was 34 + 24 = 58. Therefore, on the third day, Xiao Ming read the entire book's 58 + 6 = 9 pages.
Xiao Ming read two-fifths of the page on the first day. The next day, he read 15%, which was page 015. Therefore, the remaining pages were 200 - (2/5 + 015) = 200 - 045 = 19545 pages. Therefore, Little Ming still had 19545 pages left.
According to the information provided, if Xiaoming read 35 pages a day, he would need eight days to finish reading. The book had a total of 315 pages, so he needed to read 39 pages a day to finish it by date. On the last day, he needed to read 42 pages to finish reading.
According to the information provided, if Xiaoming read 35 pages a day, he would need eight days to finish reading. The book had a total of 315 pages, so he needed to read 39 pages a day to finish it by date. On the last day, he needed to read 42 pages to finish reading.