Reading a 40-page story book, on the first day, you read three-eighths of the book, and on the second day, you read two-fifths of the book.
On the first day, he read three-eighths of the book, which was 40 × 3/8 = 15 pages. The next day, he read two-fifths of the book, which was 40 × 2/5 = 8 pages. Therefore, the answer was that he read eight pages the next day.
If you read a book, you can read a quarter of the book on the first day, and two-fifths of the book on the second day. There are still 14 pages left. How many pages are there in this book?
Suppose the book has x pages. On the first day, he read a quarter of the book, which was 1/4 * x page of the book. The next day, he read two-fifths of the book, which was 1/4 * x pages, 2/5 = 5/16 * x pages. There were still 14 pages left, so: 14 ÷ (5/16 * x - 1/4 * x) = 14/(1/4 * x - 1/4 * x) = 14/(1/16 * x - 1/16 * x) = 14/(5/8 * x) = 14/(1/8 * x) To simplify it: 14/(1/8 * x) = 14 So 8 * 14 = x Solution:x = 96 So this book had a total of 96 pages.
Xiao Xiao was reading a book. On the first day, she had read three-eighths of the book. On the second day, she had read the remaining two-fifths. There were still 36 pages left. She asked if there were any pages in the book.
The book had a total of 36 pages. On the first day, he read three-eighths of the book, which was 36 pages/8 = 4 pages/day. The next day, he read the remaining two-fifths, which was 36 pages/(2 + 5) = 4 pages/day. Since there were 36 pages left, the book had a total of 36 pages + 4 pages/day = 36 pages + 8 pages/day = 44 pages. Therefore, this book had a total of 44 pages.
When you read a book, you read one-fifth of the book on the first day, and you read one-fourth of the book on the second day, and you read 30 more pages on the first day than the second day.
Assuming that the book has $x$pages, reading one-fifth of the book on the first day means reading $/frac{1}{5}x$pages, then reading one-quarter of the book on the second day means reading $/frac{1}{4}x$pages. According to the fact that we read 30 more pages on the first day than the second day, we can write the equation: $$ \frac{1}{5}x - \frac{1}{4}x = 30 $$ By solving this equation, one could obtain: $$ x = 150 $$ So this book has 150 pages.
Ling Ling read a book. On the first day, she read one-fourth of the book. On the second day, she read three-sevenths of the book. On the second day, she finished reading the book in three days.
Ling Ling read a book on the first day, a quarter of the book, the next day, three-sevenths of the book, and the next day: The next day, Ling Ling spent about four-sevenths of the time reading the book. In other words, she had read 4/7 of the book and still had 3/7 left. Since she only had three days, she needed to finish the book as soon as possible. Therefore, she decided to read 7/8 of the book on the second day, which was the remaining 1/8. Therefore, Ling Ling spent about 1/8 of her time reading the book the next day, leaving 7/8 - 1/8 = 6/8. She could continue reading until she finished reading in the remaining 1/8 of the time.
Xiao Hong read a book. On the first day, she read 25% of the total pages of the book. On the second day, she read two-fifths of the total pages of the book. There were still 35 nights left.
On the first day, Xiao Hong read 25% of the total number of pages in the book, which was 1/4. The next day, Xiao Hong read half of the book's pages, which was 1/8. The remaining pages were 35% of the total number of pages in the book, which was 1/4 * 35% = 75%. Thus, the book had a total of 160 pages.
Xiao Ming read a story book. On the first day, he read 30 pages, which was three-fifths of the total number of pages in the book. On the second day, he read one-tenth of the whole book.
小明看一本故事书第一天看了30页是全书总页数的五分之三那么第一天看了全书的 $\frac{30}{5}$ 页。 第二天看了全书的十分之一即第二天看了 $\frac{1}{10}$ 页。 因此第二天看了 $\frac{30}{5} \cdot \frac{1}{10} = \frac{3}{5}$ 页。 所以小明在第二天看了 $\frac{3}{5}$ 页也就是全书的 $\frac{3}{5}$ 页。
Xiao Ming read a book. On the first day, he read 10% of the book, the second day, he read 35%, and the third day, he read 44 pages. This book…
How many pages are there in this book? According to the title, Xiaoming read 10% of the book on the first day, which was 10% of the book divided by 100% = 1/10 pages. Xiao Ming read 35% of the book the next day, which was 35% of the book divided by 100% = 035 pages. Xiao Ming read 44 pages of the book on the third day, so the number of pages in the book can be calculated by the following formula: 1 ÷ (1/10 + 035 + 1/10) = 44 Solve the equation: Number of pages in the book = 44 × 100%/(1 + 035 + 1) = 3520 Therefore, this book had a total of 3520 pages.
Little Light read a story book. On the first day, he read a quarter of the book, and on the second day, he read a fifth of the book. On the first day, he read 10 more pages than the second day.
If the total number of pages in the storybook was X, then Little Light would read a quarter of the book on the first day, which was X/4 pages, and a fifth of the book on the second day, which was X/5 pages. According to the topic, the first day was 10 pages more than the second day, so there were: (X/4 - X/5) = 10 To simplify it: X/10 = 10 X = 100 Therefore, the total number of pages in the storybook was 100. Little Light read 100/4 = 25 pages on the first day and 100/5 = 20 pages on the second day. He read 45 pages in total.
Xiao Gang read a story book. On the first day, he read one-fifth of the book, and on the second day, he read 40% of the book.
As a fan of online literature, I can provide you with the following information about this book: Reading one-fifth of the book on the first day and then reading 40% of the book on the second day meant reading 40% of the book on the second day instead of 5/1 = 20% of 40%. Therefore, Xiao Gang had read 15% and 20% of the book on the first and second day. He still had 75% of the book left. If Xiao Gang wanted to finish reading the book, he would need to continue reading until he reached 75% of the book.
Lin Yun read a 156-page literary work. On the first day, he read 4/9 of the book. On the second day, he read 15/16 of the first day. On the second day, Lin Yun read...
Lin Yun read a 156-page literary work. On the first day, he read 4/9 of the book. On the second day, he read 15/16 of the first day. Lin Yun read it on the second day. Assuming that the book had a total of n pages, Lin Yun read 4/9 of the book on the first day (i.e. 4/9 * n), which meant that he read page n of the book. Next, Lin Yun read 15/16 of the number of pages he read on the first day (4/9 * n * 15/16), which meant that he read page n+1. Thus, the number of pages Lin Yun read on the second day was:(15/16) * (4/9 * n + 1) = 15/16 * (n + 4/9 * n). Since n+4/9*n is an integral number, 15/16 * (n + 4/9*n) must be a multiple of 15. Thus, when n was a multiple of 15, the number of pages Lin Yun read on the second day was 15/16 * (n + 4/9*n), which was a multiple of 15. For example, when n is 30, the number of pages Lin Yun reads on the second day is 15/16 *(30 + 4/9 * 25) = 15/16 *(30 + 10/9 * 25) = 15/16 * (35 + 5/18) = 15/16 * (35 + 25/18) = 15/16 * (375 + 125/18) = 15/16 * (375 + 625) = 15/16 * 37 = 45 When n was 15, the number of pages Lin Yun read on the second day was 15/16 * (15 + 4/9 * 15) = 15/16 * (15 + 10/18) = 15/16 * (15 + 5/6) = 15/16 * 20 = 375. When n was 20, the number of pages Lin Yun read on the second day was 15/16 * (20 + 4/9 * 20) = 15/16 * (20 + 10/18) = 15/16 * (20 + 5/6) = 15/16 * 375 = 45. Thus, Lin Yun read a 156-page literary work on the first day and read 4/9 of the book (4/9 * 156). On the second day, he read 15/16 of the first day (4/9 * 156 * 16/15). On the second day, he read 15/16 * (156 + 4/9 * 156).