The following is a summary of the content related to biology in the first volume of the 7th grade of the 54 system. There was the Luke edition of the 7th grade biology electronic textbook (May 4th academic system). You could log in to the account on the National Primary and Secondary School Wisdom Education Platform website (
The following are the answers to some of the questions in the Jiangsu version of the high school biology compulsory textbook: Chapter 1: The molecular composition of cells The Elements and Inorganic Compound in the Cell - ** Speculation Questions ** - Among the chemical elements that made up living things, C, H, O, and N were the most abundant. - Free water was a good solution for many ions, not bound water. - If muscle weakness occurs, the substance that may be lacking is calcium. - ** Usage Questions ** - The trace elements were iron, mn, zn, copper, b, al, co, and se. - The carbon exists in the form of carbon dioxide, oxygen in the form of water, hydrogen in the form of water, calcium in the form of carbon dioxide, phosphorus in the form of dipotassium hydrogen orthhosphate, and potassium in the form of kci. They are involved in the composition of substances in the body; Na ions maintain the stability of the osmonic pressure of the extra-cellular fluid; K ions participate in the activation of more than 60 kinds of membranes during plant growth and development; Ferrous ions are the components of many membranes; and Magnesium ions are an important component of the phylls. - Legume plants such as alfalfas and soybeans had a nitrogen fixing bacteria at the roots, which could help them survive the winter. - Free water was a good solute. The ions and molecules needed for cell life could be dissolved in it and flow with the water to participate in the reaction. Metabolic waste could also be discharged from the body through water. ** Section Two: Carboids and Lipids in the Cell ** - ** Speculation Questions ** - Glycogen and glucose were the main energy substances, fat was an important energy storage substance, and Cellulose was a plant cell structure substance that could not be used as an energy substance. - Lipids were divided into fats, lysomes, and steroids, but lysomes did not belong to steroids. - It was not advisable to reduce overweight weight only by reducing the intake of sugar and fatty foods. It was also necessary to combine it with moderate physical exercise. - ** Usage Questions ** - Plant cells contained starch and starch, and the process of making syrup was similar to the biological method. - The second biological method was used to utilize the raw material of the Cellulosic. - Celluloses and other glycans were important structural substances in plant cells, while glucose was the main energy source for life activities. - Ferlin's reagent could only identify reducing sugar. Sweet potatoes mainly contained non-reducing sugar such as starch, so it could not be used to identify them. However, Sultan III staining solution could be used to detect the fat in sweet potatoes. ** Section Three: The Nucleic Acid and Nucleic Acid in the Cell ** - ** Speculation Questions ** - Nucleic acid in the human body was composed of eight kinds of nuclei (adenine deoxy, guanine deoxy, cystine deoxy, thymine deoxy, adenine Ribo, guanine Ribo, cystine Ribo, and uracil Ribo). Uridine Ribo was composed of uracil, Ribo, and Phosphoryl. - The seeds of wheat, sorghums, and other plants are rich in starch, while animals such as cattle and sheep are rich in protein and fat. - ** Usage Questions ** - In contrast to the "food pyramid", if you eat too much dessert and meat, you may be obese, and if you eat too little vegetables and fruits, you may lack vitamins. - Mung beans may contain more starch; it is not possible to judge whether they are nutritious based on the content of protein; the cell composition of beans cannot be separated from protein. Cell structure and life activities (Part) - In the content related to organic matter in cells, there were various statements: - Not all kinds of sugar could be used as a plant energy material. Ribose and deoxy sugar formed the genetic material, and the plant cell wall made of Cellulose could not be used as an energy material. Therefore, it was wrong to say that all kinds of sugar could be used as a plant energy material. - The basic framework of the cell membrane was composed of a double-layer consisting of lysomes. Choline was an important component of animal cell membranes and was involved in the transport of fats in the blood. Therefore, it was correct to say that both lysomes and Choline were components of animal cell membranes. - The main reason for protein degeneration was the destruction of the spatial structure rather than the cleavage of the bond. Deoxy acids were connected to each other by the bond of the ester. Therefore, it was wrong to say that the high temperature degeneration of the protein was due to the cleavage of the bond, and the single chain was formed by the bond of the deoxy acids. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
If you were to take notes from the listening comprehension of the new high school English textbook published by the People's Education Press, you could refer to the following methods: - ** vocabulary preparation **: Learn vocabulary before listening and remove vocabulary barriers in listening. This part of the vocabulary can be sorted out and recorded separately. It is clear about the pronunciation and meaning of the words, which is helpful for listening comprehension. - ** Listening to the Listening test questions **: When listening to the listening materials that contain the vocabulary of the teaching materials, record the key content related to the vocabulary of the teaching materials, such as some habitual collocations, special usages, etc. - ** Post-listening feedback segment **: In-depth study of the listening text, combining listening, reading, and dictation. Dictation of key sentences and hard-to-understand parts of the listening text could deepen the mastery of vocabulary, grammar, and other knowledge. At the same time, he took detailed notes on the grammar phenomena and key vocabulary usage in the listening text to build his own knowledge system. - ** Follow-up Reading Stage **: Follow the listening text, imitate the standard English pronunciation, and consolidate the vocabulary of the teaching material again. If there were words that were difficult to pronounce, or words that were linked or weak, they could also be recorded for review. Take Bubugao's study notes as an example, focus on the topic, stick to the goal, and explore the listening content independently; In the process of group discussion, presentation and communication, and solving doubts and correcting errors, the knowledge points and questions related to listening will be sorted into notes; In the training test, summary review, reflection and improvement stage, listening skills, common listening vocabulary and expressions can be summarized in the notes, so as to harmonize the teaching material knowledge and consolidate the foundation. In addition, he could also use the table note-taking method. He could write down phrases in the left column, example sentences in the middle column, and his own experience in the right column (including questions and conclusions about knowledge points) to make his notes more organized. For example, record the phrase "be different from" or the example sentence "My school is different from yours." The notes could be written about questions about the usage of the phrase or a summary of its usage in listening. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. ** Base calculation for double-stranded DNA and messenger acid ** - **DNA single and double-strand pairing base relationship ** - In double-stranded DNA, the number of A (adenine) in one strand is equal to the number of T (thymine) in the other strand, namely,<A1=T2>,<T1 = A2>;; in the entire double-stranded DNA,<A=T>, and <A=T=A1 + A2=T1+T2>;; similarly,<C = G>,<C=G=C1 + C2=G1+G2>. Double-stranded DNA [A + C=G + T],[A+G=C + T], they are equal to half of the total number of double-stranded DNA bases, that is,[1/2] of [(A + G + C+T)], and [(A + G)],[(C + T)],[(A + C)], and [(G + T)] are all [50%], which shows that the total number of purine bases in double-stranded DNA is equal to the total number of prismatic bases. - ** Calculation of DNA Single and Double-Stranded Base Levels ** - In double-stranded DNA,<(A + T)> %+(C + G)> % = 1>. ((C+ G)< %>= 1-(A + T)< %>, at the same time <(C + G)< %>= 2C < %>=2G < %>,<(A + T)< %>= 1 - 2C < %>=1 - 2G < %>,<(A1+T1)< %>= 1-(C1 + G1)< %>,<(A2+T2)< %>= 1-(C2 + G2)< %>). - ** Relationship between the number of bases in a single strand of DNA ** - \(A1+T1+C1+G1=T2+A2+G2+C2), the sum of which is equal to the total number of double-stranded DNA bases (1/2);(A1+T1=A2+T2=A3 + U3)(Here,<<A3 + U3>> is the corresponding relationship between <<A1+T1>> and <<A2+T2>> when the DNA is transcribed into mR A), and it is equal to <(1/2> of <(A + T)>);<C1+G1=C2+G2=C3+G3>>, which is equal to <(1/2> of <(G + C)>). - ** The ratio of DNA single-strand and double-strand pairing bases ** - If <(A1+T1)/(C1+G1)=M>, then <(A2+T2)/(C2+G2)=M>,<(A + T)/(C + G)=M>, this ratio could represent the DNA molecular's specific property. - ** The ratio of the sum of single and double-stranded non-paired bases in DNA ** - If (A1+G1)/(C1+T1)=N, then (A2+G2)/(C2+T2)=1/N, and (A + G)/(C + T)=1; If (A1+C1)/(G1+T1)=N, then (A2+C2)/(G2+T2)=1/N, and (A + C)/(G + T)=1. - ** The relationship between the base content of two single-strands and double-strands ** - \(2A\%=2T\%=(A + T)\%=(A1+T1)\%=(A2+T2)\%=(A3+U3)\%=T1\%+T2\%=A1\%+A2\%\);\(2C\%=2G\%=(G + C)\%=(C1+G1)\%=(C2+G2)\%=(C3+G3)\%=C1\%+C2\%=G1\%+G2\%\)。 2. ** Calculating cell division, ontogeny, DNA, Chromatids, Chromatids, Homological Chroomes, and Quarters ** - ** Type of genetic information stored in DNA **: It is a type of DNA (4 ^n)(n is the base pair of DNA). - ** Cell division ** - The number of nuclei is equal to the number of kinetochore. The number of mitosis anaphase is [N], the number of somatic cells is [2N], minus the number of mitosis anaphase I is [2N], minus the number of mitosis anaphase II is [2N]. The number of sperm or egg cells or polar nuclei <br><br><br> The number of somatic cells <br> The number of fertilized eggs <br> The number of fertilized eggs An oogonia formed an egg cell and three polar bodies, and a sperm cell formed four sperm. If the DNA number of gametes (sperm or egg cells) is <M>, then the number of DNA in the body cell is <M>;;; the number of DNA in the gonogonia is <M>(= 2M>)(before DNA replication) or <4M>(after DNA replication); the number of DNA in the primary gonelle is <M>;;;; and the number of DNA in the secondary gonelle is <M>. When the number of DNA molecules in a single <br><br> 1, the number of chromatids is 0; when the number of DNA molecules in a single <br> 2, the number of chromatids is 2. The number of quadrants was equal to the number of pairs of homolog genes (syndesis and minus the middle stage I), and the number of quadrants after the middle stage I minus the late stage I was 0. - ** Ontogeny of the flowering plants ** - Embryo Cell Chromatic Number (2N = 1/3) Nucleus of the Polarity of Fertility (3N = 1/3') The number of embryos in the embryo cell is equal to the number of embryos in the fertilized egg, equal to the number of embryos in the sperm cell and the number of embryos in the egg cell (distant crossing). The number of embryos in the embryo cell is equal to the number of embryos in the fertilized polar nucleus, equal to the number of embryos in the sperm cell and the number of embryos in the egg cell and the number of embryos in the polar nucleus.<1> ovule (double fertilisation)<1> egg cell><+2> polar nucleus><+2> sperm><1> seed;<1> ovaries><1> fruit. 3. ** Calculation of protein and nuclei (Note: Number of Peptides (m); Total Number of Acid (n); Average Weight of Acid (a); Average Weight of Acid (b); Total Number of Nucleic Acid (c); Average Weight of Nucleic Acid (d))** - ** Genes (and Peptides)** - ** Calculation of the number of atoms of the different atoms of the ammo acid **: the number of atoms in the base of the [C] atom in the base of the [H] atom in the base of the [H] atom in the base of the [C] atom in the base of the [H] atom in the base of the [C] atom in the base of the [H] atom in - ** Each chain has at least **: each has 1 free amine and each has at least 1 free amine and each has at least m free amine and each has at least m free amine. - ** Number of Peptide Bond **: Number of Peptide Bond <>/>/>=<> Number of Dehydrating Water>/>=<<>=>=<=<=>=>=<=& - ** The protein is composed of [m] number of protein chains **:[N] number of atoms [=] number of peptidic bonds [+m] number of amino groups (end)[+R] number of amino groups [=] number of peptidic bonds [+] number of amino groups [+m] number of peptidic bonds [end];<<O>> Total number of atoms><=>> Total number of bond bonds><+2(m>)<<+R>><+ Carboxy groups><=><Total number of bond bonds><+2><Carboxy groups><<+2m>><Carboxy groups></> - ** protein molecular weight **: molecular weight of protein/(=/) total molecular weight of ammo acid-total molecular weight of dehydration (total atomic weight of dehydration)/(=na-18(n-m)/). - ** The calculation of the number of the number of the bases in the double-stranded DNA (gene), and the number of the bases in the messenger acid in the protein ** - The number of bases in the gene (at least): the number of bases in the gene (at least): the number of the protein's aa (=6:3:1); the number of peptidic bonds (number of water gain and loss); the number of peptidic chains; the number of aa; the number of bases in the gene; the number of bases in the gene; the number of bases in the gene. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology compulsory 1 had the following difficulties: 1. Cell structure and function: - The distinction between procaryotic cells and eukaryotic cells involved the differences in the cell structure such as the nucleus (with or without the nuclear membrane as the boundary), the organelle, and so on. It was necessary to accurately remember the unique structure and functions of different cell types. For example, in procaryotic cells, fungi were the smallest and simplest cells without special structures such as cell walls. - The structure and function of the cell membrane, such as Irvington's conclusion that it was easier for lipid-based substances to pass through the cell membrane through experiments, and Robert's observation of the dark-light-dark three-layer structure of the cell membrane under the electron microscope and his speculation of its composition, as well as the role of the protein on the cell membrane, such as the protection, smoothness, and cell recognition functions of the protein on the surface of the respiratory and digestive tract, all involved a variety of experimental evidence and complex functional explanations. It was difficult to understand. - The functions of the organelle and the relationship between them, such as mitochondria was the main place for oxygen breathing, the plastids were the place for photosynthesis, the plastids were the workshop for protein synthesis and processing, and the Golgi apparatus processed and packaged the protein, etc., and they were interconnected through the synthesis and secretion of secreted protein. For example, the synthesis of secreted protein involved many organelle such as the Ribosome, the plastids, and the Golgi apparatus. These processes were more complicated and closely related. 2. Cell Theory: - There were three points in the cell theory proposed by Schwann and Slyden, including that the cell was an organism, all animals and plants were developed from cells and composed of cells and cell products, the cell was a relatively independent unit, which had its own life and played a role in the overall life, and the cell was a relatively independent unit. New cells were produced from old cells (Virshaw's supplementary cells produced new cells through division). This part required a deep understanding of the importance of cell theory in the development of biology and its fundamental role in modern biological research. 3. Biofilm System: - The membrane system consisted of cell membranes, organelle membranes, nuclear membranes, and other structures. It was difficult to understand its functional characteristics. For example, the decisive role of the cell membrane in the process of material transport, energy conversion, and information transmission. The chemical reaction on the membrane required the participation of the reagent. The wide membrane area provided the attachment site for the reagent. The membrane separated the organelle to ensure that various chemical reactions were carried out efficiently and orderly. 4. The material foundation of cells: - As the main bearer of life activities, the structural variety of the protein (different types, numbers, sequence, and spatial structure of the chain) determined the functional variety. To understand it, one needed a certain amount of spatial imagination and logical thinking ability. - The functions of sugar, fat, mineral salt, and water in cells, such as the important component of the cell membrane that was involved in the transport of fat, and the existence of water in the cell in the form of free water and bound water with different functions, needed to be accurately memorized. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The following are some aspects to consider when writing compulsory education feedback: ** I. Balance of education resources ** 1. ** hardware resources ** - School infrastructure: If you find that some schools have insufficient or excessive teaching and auxiliary rooms, such as some schools have overcrowded classrooms that affect the teaching effect, or some schools have idle space that has not been properly used, you can point out and make suggestions for improvement, such as rationally planning the classroom layout or reallocating idle space for the construction of functional rooms. - Sports venues: observe the school's playground and sports facilities. If some schools lack sufficient sports grounds, affecting the physical education curriculum and extra-cursory activities of students, it should be mentioned. For example, it was suggested to add some small multi-functional sports facilities in schools with limited space, such as mobile basketball stands. - Teaching instruments and equipment: In terms of teaching instruments and equipment value, if it is found that the instruments and equipment are old, insufficient, or unbalanced, such as some school laboratory instruments aging and unable to be used normally, while other schools have newer equipment idle, it is recommended to check and allocate the equipment regularly, and update the equipment according to teaching needs. - Book resources: If the number of books per student is not up to standard or the type of books is single, you can propose to increase the purchase funds of books and enrich the types of books, including books on science, literature, art, and other aspects. At the same time, establish a book sharing mechanism to allow the reasonable flow of book resources among schools. 2. ** Teachers ** - Teacher to student ratio: If there is an imbalance in the teacher-student ratio, such as the number of teachers in some schools is too small, resulting in the teacher's teaching tasks being too heavy, affecting the quality of teaching and the health of teachers, it can be suggested to adjust the teacher establishment reasonably according to the number of students and recruit more teachers. - Teachers 'academic qualifications and professional titles: When it is found that the number of teachers with higher academic qualifications or the number of teachers with intermediate and above professional and technical positions per student varies greatly among different schools, such as the number of teachers with high academic qualifications and high professional titles in remote schools, it can be proposed to encourage teachers with high academic qualifications and high professional titles to teach or communicate in schools with weak teachers through policy guidance. At the same time, it is necessary to strengthen on-the-job training for teachers in weak schools to improve their academic qualifications and professional titles. ** 2. Education policy implementation ** 1. ** Entrance opportunity ** - Admissions policy: Check if there is any unequal access to school, such as school selection in some areas, and some schools use improper means to select students. The feedback could request to strengthen the supervision of the enrollment policy to ensure the implementation of fair enrollment principles such as the use of computer random allocation to ensure equal admission opportunities. - Special Groups Enrolling: Pay attention to the enrollment of special groups such as disabled children, children from poor families, and children of migrant workers. If there were any obstacles to school admission, such as insufficient special education resources, which made it difficult for disabled children to enter school, or the admission procedures for children of migrant workers were cumbersome, suggestions could be made to simplify the admission procedures and increase investment in special education. 2. ** Security mechanism ** - Capital investment: If it is found that the government's investment in compulsory education is insufficient, resulting in difficulties in the school's operation, such as inability to update equipment and repair school buildings in time, it can be suggested to increase financial investment and rationally plan the allocation of funds to ensure that the funds are used effectively. - << Education Resource Assignment >>: Check whether the distribution of education resources in different regions and schools is fair and reasonable.>For example, there was a big gap between urban and rural schools in terms of funding and teachers. It was suggested that a more scientific resource allocation system should be established to favor weak areas and schools. 3. ** Education Quality and Management ** - " Course design: If you find that the course design is unreasonable, such as some schools paying too much attention to the main subject teaching and neglecting the arts, sports, labor and other courses, you can request to strictly follow the national curriculum standards to open all kinds of courses and strengthen the supervision of the implementation of the courses. - Teaching quality monitoring: If the teaching quality monitoring system is not perfect, such as only focusing on examination results and lacking a comprehensive evaluation of students 'comprehensive quality, it can be suggested to establish a pluralistic teaching quality monitoring system, including the evaluation of students' moral character, practical ability, innovative thinking, etc. - School management: For school management, if you find that the school management system is not perfect, such as the lack of an effective assessment mechanism for teachers 'teaching quality, or the daily management of students is too loose, you can put forward suggestions to improve the management system, establish a scientific teacher evaluation system, and strengthen the management of students' daily behavior norms. ** 3. Overall development of students ** 1. ** Status of the implementation of the five elements of education ** - Moral education: If you find that the school's moral education work is monotonous and lacks depth and effectiveness, such as moral education only through the ideology and morality class, lacking practical activities and the infiltration of campus culture, you can suggest to carry out colorful moral education activities, such as theme class meetings, social practice, campus culture festivals, etc., to integrate moral education into daily learning and life. - " Intelligent education: Pay attention to whether the teaching method is too traditional, which is not conducive to the cultivation of students 'innovative thinking and independent learning ability. If teachers mainly teach by instilling, they can recommend the promotion of elicitation and inquiry-based teaching methods to encourage students to actively participate in classroom discussions and research learning. - Physical education: If the physical education curriculum and extra-cursory activities are not guaranteed and the students 'physical fitness is declining, the school can be required to strictly implement the physical education curriculum standards, increase the time for extra-cursory sports activities, and hold a variety of sports competitions. - " Esthetic education: If the school is found to be lacking in aesthetic education resources, such as art teachers and art activity venues, it can be suggested to strengthen the construction of aesthetic education teachers, equip them with necessary art teaching equipment, and carry out art exhibition, concert, and other aesthetic education activities. - Labor education: When labor education is neglected, such as the lack of specialized labor courses or labor practice bases, it can be proposed to set up labor courses and establish labor practice bases in schools to cultivate students 'labor awareness and skills. 2. ** Students are physically and mentally healthy ** - Mental health: If it is found that the school lacks mental health education teachers and coaching facilities, and the students 'psychological problems cannot be paid attention to and solved in time, it can be suggested to allocate professional psychological teachers, establish psychological consultation rooms, and carry out mental health education courses and psychological consultation activities. - Physical health: In addition to physical education courses, pay attention to the school's diet, hygiene and other aspects of the impact on the health of students. For example, if there were problems with the food safety and nutrition of the school canteen, or if the school's environmental hygiene was poor, they could request to strengthen the management of the canteen, improve the quality of the food, and strengthen the improvement of the school's environmental hygiene. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The following is the general framework of the cell life process mind map: ** 1. Cell reproduction ** 1. cell growth - Cell size increases - The efficiency of substance exchange would change with the growth of cells. The larger the volume, the smaller the relative surface area, and the lower the efficiency of substance exchange. This limited the unlimited growth of cells. 2. cell division - mitosis - Cell cycle: It includes interphase (G1 phase-preparatory work such as protein synthesis, S phase- DNA replication, G2 phase-further preparation) and division phase (prophase-appearance of the nuclei, formation of the spindles, etc.; Metaphase-arrangement of the nuclei on the equator; anaphase-division of the nuclei, separation of the sister chromatids into the nuclei and migration to the poles; telophase-disappearance of the nuclei and the nuclei, reappearance of the nuclear membrane and the nuclei, etc.). - [Meaning: Maintain the stability of the genetic material of the parent-child generation.] - Amitosis: There are no changes in the spindle-like fibers and the nuclei of the nuclei, just like the division of the frog's red blood cells. ** 2. Cell Division ** 1. [Concept: The process in which cells undergo changes in their form, structure, and function.] 2. characteristic - Durability: occurs throughout the life of an organism, but reaches its maximum during the embryonic stage. - [Stable: The differentiated cells will not return to their undifferentiated state.] 3. [Meaning: It can specialize the cells in multicellularized organisms and help improve the efficiency of various physiological functions.] ** 3. Cell aging ** 1. The characteristics of cell aging - The cell membrane's penetrability changed, and the material transport function decreased. - The water content in the cells decreased, the cells shrank, and their size became smaller. - The activity of many kinds of cellular zymes decreased. - Pigments in the cells would gradually accumulate as the cells aged. - The size of the nucleus increased, the nuclear membrane folded inward, the chromatin contracted, and the staining deepened. 2. The relationship between cell aging and individual aging: The cell aging of a single-celled organism is the aging of an individual; the cell aging of a multicellularized organism is not equal to the aging of an individual, but the aging process of an individual is also the aging process of the cells that make up an individual. ** 4. Cell Death ** 1. apoptosis - [Concept: The process of cells automatically ending their lives is a normal physiological phenomenon.] - [For example, the disappearance of the tail and the formation of fingers during the development of a human embryo.] - [Meaning: It plays a key role in the normal development of organisms, maintaining the stability of the internal environment, and resisting external interference.] 2. cell necrosis - [Concept: Under the influence of various adverse factors, cell damage and death caused by the damage or interruption of normal cell metabolism.] - [Characteristic: It is a passive, pathological death, such as tissue cell death caused by regional hemorrhage.] <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Here are some recommendations for high school biology textbooks: 1. "The new curriculum standard thoroughly explains the teaching materials for high school biology compulsory 1 (companion teaching edition)", which was helpful for the study of compulsory 1. 2. You can pay attention to the headline of "High School Biology Teaching and Learning" and obtain the "2022 College Entrance Examination Review 'Return to Teaching Materials to Win the College Entrance Examination' Series of Materials: Required One" according to the free method provided by it. It will help you review and prepare for the required one. 3. As for teaching assistants,"handwritten notes or a book" was also a good choice. It would help to further learn biological knowledge after mastering the content of the textbook. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The following are some examples of the words in the second volume of the compulsory high school English textbook: - Unit1: Heritage, creative, creative, temple, relic, mount, former, clue, preserve, promote, etc. - Unit2: compete, take part in, stand for, admit, etc. - Unit3: solve, from…on from time to time), as a result, etc. - Unit4: die out, hunt, in peace, etc. - Unit5: roll, dream of, to be honest, etc. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>