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fate probability

fate probability

Journey of the Fate Destroying Emperor

Journey of the Fate Destroying Emperor

After being reincarnated in a world of Gods, Demons, and Great Emperors, Wang Wei embarks on a journey to bear Heaven Mandate, proves the Dao, and proclaims himself a Great Emperor--a Supreme Being that overlooked Myriad World and Races. However, his Dao involves despising fate and its encompassing glory. So what awaits our protagonist on his journey full of vicissitudes to defy and even control fate? While he controls the fate of countless races and worlds, is fate playing with him? Can he escape the very shackles of fate that he controls? Better Synopsys: After an unknown cosmic accident that enveloped the Earth, Wang Wei was reincarnated into a magical world of spiritual cultivation. This world was composed of powerful Demons, cunning and brutal Devils, ruthless and indifferent Gods, detached and ethereal Immortals. More Importantly, Great Emperors--Supreme Beings that stand above everyone and everything, even life and death itself. Despite being born in one of the most powerful sects in the world, Wang Wei was placed under tremendous pressure when so many expectations were placed on him by his sect due to the fact they have not cultivated a Great Emperor for countless millennia--an act which threatened the fundamental status of his family, friends, and sect. On top of that, Wang Wei was not one of the chosen few of this world that was granted special gifts by Heaven, thus further aggravating his circumstances. However, he did not retreat in the face of adversity. With the mindset that “If Heaven does not give me, I shall take it for myself”, Wang Wei begins to plan his rise to the top with a brilliant tactical mind and the help of his mysterious soul so that one day he will become a Great Emperor that not only control his fate but the fate of all lives in existence. This story has a similar setting as Emperor Dominion, I am a True Villain, and Scoring the Sacred Body of the Ancients from the Get-go. If you enjoy this type of story, then you will enjoy my story. The first 30 chapters or so have many problems story-wise, so please bear with it as I was just beginning as a writer. However, I promise the story gets better afterward. Discord:https://discord.gg/bnsezTApeY Go check out my Pa.tr.eon: .https://www.patréon.com/LazySageDao Or just go into the site and search for my author name (LazySageDao). So, go and support me if you can. Warnings: No Young Master and Face Slapping. Disclaimer: The image on the cover does not belong to me. If the original author wants me to take it down, just leave a comment in one of the new chapters of the book.
Eastern
1953 Chs
Chosen by Fate, Rejected by the Alpha

Chosen by Fate, Rejected by the Alpha

Eighteen-year-old Trinity is unlike any other werewolf in her pack. For one, there were unusual circumstances surrounding her birth, for another, she is the only pack member to never shift into a wolf form. So now she doesn't quite belong anywhere. Not quite human and not quite wolf. She thought she would be able to live her life how she wanted when she had turned eighteen. Go to college, make some friends, have some fun. But what is she to do when the dangerously sexy Alpha literally falls right into her lap? "I am not human, and I am not a wolf. I don't belong anywhere..." "...we both know that no one is going to mate with me, and even if they did, they would just reject me anyway." What is the sexy, brooding Alpha going to do? The elders are making him hold these ridiculous parties to search for a mate. He doesn't want a mate, but he knows he needs a mate to finish the Alpha Circle. Without a mate, a Luna for the pack, his people would suffer. And what is he going to do when he stumbles across the girl that fate has chosen for him and he finds out she has no wolf? "This cannot be!" I roared. "There is no way that I can mate with a girl that does not even have a wolf. She will be too weak. She will be inferior. She will not be strong enough to be a Luna." "I simply could not accept her as my mate. Not fully. It wasn't safe for her. She would get herself killed. And she would bring my pack down with her." When these two meet, sparks will surely fly. But will it be from passion, or their constant fighting? Neither of them wanted a mate. Neither of them wants the mate that fate chose for them. And neither of them can make that mate bond go away. What are they going to do now that they're literally stuck with each other? ***Rating Warning*** Adult Language Violence Strong Sexual Content THIS BOOK IS UNDERDER AN EXCLUSIVE CONTRACT AND IT IS NOT TO BE POSTED OR PUBLISHED ANYWHERE ELSE. Follow me to find my other books or ask me question, thanks for reading!!! FOLLOW ME AND LET ME KNOW WHAT YOU THINK https://discord.gg/8wrYgHqemB https://twitter.com/DCinMI https://www.facebook.com/deni.chance.71 https://www.instagram.com/dcinmi87/ ***COVER ART IS THE SOLE PROPERTY OF THE AUTHOR AND WAS ILLUSTRATED BY VICTORIA DAYEN OF MSPUGLUVER'S ART***
Fantasy
1197 Chs
She is the Side Character! — Watch Her Change her fate!

She is the Side Character! — Watch Her Change her fate!

997 signed a contract with a newbie host named Ah Chen, and even coaxed (strikethrough) them into a permanent bind. Soon, it was discovered that the seemingly obedient and honest new host had two faces. The 1st World: She transmigrated into a Princely Heir disguised as a man, with her father, a different-surnamed king, about to rebel. In the end, their family failed and was annihilated. At the critical moment, Ah Chen decisively knocked her father unconscious with a karate chop. Rebellion? Not possible. To prevent her father from causing trouble and implicating the family, she brewed a delicious mushroom soup, allowing him to spend the rest of his life capturing small men to pass the time. The Emperor: I heard someone was rebelling. I set up an inescapable net and waited all night. May I ask where the rebels are? The 2nd World: A big star used her resources to support a scumbag, only to be ruined by him in the end? Ah Chen stated that with her presence, there was no way the ungrateful scumbag could ever make a name for himself. The one to lose reputation and status could only be him. The 3rd World: On the wedding night, the groom ran away, leaving behind an entire family for her to serve? Ah Chen smiled with curved brows, "Meet the fierce daughter-in-law!" …… 997 gradually accepted his fate until one day he discovered another secret of the host, and he was greatly shocked! 997: Host, you're making me feel very unfamiliar. Ah Chen: You'll get more familiar with time. 997: …… [1v1, male lead fragment, ultimate romance, some worlds might not appear due to settings]
Sci-fi
800 Chs
Increases the probability of 10 to 11
The probability of a normal non-safe buff was between 10% and 30%, depending on the equipment's quality, level, enchantment, and strengthening level. The probability of a safe buff was between 3% and 10%, but there was no separate probability of a 10 to 11 buff.
1 answer
2026-07-06 08:20
2 dice probability
For two dice, there were several possibilities: 1. ** Single number probability **: - Each die had six sides, and the numbers were 1, 2, 3, 4, 5, and 6. When a die is rolled, the probability of each number appearing is 1/6. When two dice were thrown, for example, the probability of both dice rolling a 1 was 1/6. Therefore, the probability of both dice rolling a 1 (the combination of 1 and 1) was (1/6)×(1/6)=1/36. Similarly, any particular combination of numbers (such as 3 and 5) has a probability of 1/36. 2. ** Point sum probability **: - The sum of the points was 2 (1 + 1), and there was only one possibility. The probability was (1/6)×(1/6)=1/36. - The sum of the points is 3 (1+2 or 2 + 1). There are two possibilities, and the probability is 2/36. - The sum of the points was 4 (1+3, 2+2, 3+1). There were 3 possibilities, and the probability was 3/36. - The sum of the points is 5 (1+4, 2+3, 3+2, 4+1). There are 4 possibilities, and the probability is 4/36. 3. ** Dice size probability (1 - 6 is small, 7 - 12 is big)**: - There were a total of 6x6 = 36 combinations of the two dice. Among them, there were 15 situations where the sum of points was 1 - 6 (small), and 21 situations where the sum of points was 7 - 12 (large). However, since it was impossible for two dice to have a point, the probability of a small point appearing was 5/11 (about 45.45%), and the probability of a big point appearing was 6/11 (about 54.55%). 4. ** The probability that the sum of the two dice numbers is odd (assuming the first die numbers are 1, 2, 3, 3, 5, 6, and the second die numbers are 1, 2, 4, 4, 5, 6)**: - For the first die, the probability of an odd number appearing was 4/6 = 2/3, and the probability of an even number appearing was 1/3. For the second die, the probability of an odd number appearing was 2/6 = 1/3, and the probability of an even number appearing was 2/3. To get the odd sum, there are two situations: if the first die is odd and the second die is even, the probability is 2/3×2/3 = 4/9; if the first die is even and the second die is odd, the probability is 1/3×1/3 = 1/9. Therefore, the total probability was 4/9+1/9 = 5/9. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
1 answer
2026-07-31 04:05
Destiny, 2000 words probability
I'm not sure what exactly you mean by the '2,000-word probability of fate' you mentioned. If you can provide more context or detailed information, I will try my best to help you. While waiting for the anime, you can also click on the link below to read the classic original work of The King's Avatar!
1 answer
2024-10-21 11:43
Hegemony reward probability
"We can come to the following conclusion: the probability of an orange card appearing in the Hegemony Card Pack is 5.6%. However, the exact number of orange card draws was not certain, because different card packs had different guarantee mechanisms. Some card packs guaranteed an orange card after a certain number of draws, while others did not have a minimum number of draws. According to the information provided, the probability of obtaining other Hegemony rewards cannot be known.
1 answer
2024-12-25 00:09
10,000 words signing probability
The signing rate of Zongheng was less than 0.8%. Some authors had received more than 10,000 words of short messages, but this did not accurately indicate the probability of signing a contract for 10,000 words. Although there were cases of successful signing, the overall signing rate was relatively low. There were also cases where the signing threshold was lowered but the quality was not strictly controlled. There were many novels signed on the website but the general quality was not high. Therefore, it was difficult to determine the specific signing probability at 10,000 words.
1 answer
2026-06-23 11:44
Mythical equipment probability
The probability of obtaining mythical equipment in different games was different: - In the games that had daily dungeons (which would be opened when the character reached level 35, and each person would have three chances a day, and the number of chances would increase at a specific time) and team dungeons (which would be opened when the character reached level 50), the specific probability of obtaining Mythical equipment was not clearly stated. It only meant that there was a certain chance of obtaining Mythical equipment after completing the stages in the dungeon. Mythical equipment had a high drop rate in team dungeons, but the class was random. - In the DNF: - Nether Tower Jar (From the Nether Tower Instance Dungeon, Level 100. You can exchange coins for jars after clearing each level, including weapon jars, armor jars, jewelry jars, etc.) The probability of obtaining Mythical equipment is about 1%. - Path of the Strong (Source: Path of the Strong Instance Dungeon. Exchanged with Trial Proof materials). Mythical equipment is a random event. - [Cirlock Jar (Originated from Cirlock's dungeon, exchanged with 500 Eternal Aria). Can randomly unlock all Level 100 Epic (excluding work clothes) and Level 100 Mythical equipment. Chance is low.] - In the Epic Road event, the Mythical drop buff would increase the Mythical drop rate as the number of passes increased. Each character would be calculated separately. After the current character dropped Mythical equipment, the Mythical drop rate would return to normal. - In the Legend of Wonderland mobile game: - There was a chance of obtaining Level 20 Mythical Equipment after clearing the Lonely Desert Abyss difficulty dungeon, and there was a chance of obtaining Level 40 Mythical Equipment after clearing the Yellow Springs difficulty dungeon, but the specific probability value was not given. - Killing mini-monsters can obtain the God's Bless Secret Box, which can drop mythical equipment. There is no mention of the probability. - Daily Instance Dungeons can be entered at level 35, 3 chances per day (3 additional chances for activating special privileges). After clearing the dungeon, there is a chance to obtain Mythical equipment, but the specific probability value is not given. - The Tower of Pride Shop could use Pride Silver Coins obtained from clearing the tower to exchange for Mythical equipment. There was no mention of the probability.
1 answer
2026-07-08 19:33
Hearthstone painting probability
Under normal circumstances, an average of 181 normal packs would give out a mutant orange. However, on December 7, 2022, after Hearthstone's patch 25.0 was released, players found that the probability of the game's standard packs giving out mutant orange cards was extremely high. Therefore, Blizzard temporarily closed the opening function of the standard packs to investigate. The special drawing card can be opened through the package.(Use in-game gold coins or real money to buy card packs to activate), participate in activities (You can get a special drawing card bag or get it through the event reward route), participate in the competition (Official Stairway or Single Player Challenge), Combination (There is a certain chance of getting a special drawing version from the normal version), joining the guild (through the guild treasure chest and missions), pre-ordering the super collection (such as the "Lich King's March" super collection can get two special drawing cards), completing the Death Knight Prologue (can unlock the Death Knight profession and get 32 core series cards including 6 special drawing cards for free), etc., but these methods did not mention the specific probability of getting special drawing. "The Legend of the Three Dragon Scales in the Milky Way Continent" is equally exciting. Everyone is welcome to click and read it!
1 answer
2026-03-15 11:34
The probability of dice rolling
Rolling dice was a classic example of probability. For a single standard die, because it had six sides, each marked with the six numbers 1, 2, 3, 4, 5, and 6, the chances of each number appearing were equal. Therefore, when throwing a single die, the probability of any number appearing in the result was 1/6. When there were multiple dice involved, the probability calculation would be more complicated. Take two dice as an example, if you consider the size of the dice,(1 - 6 is small, 7 - 12 is big), because there are a total of 6×6 = 36 combinations of the number of points on the two dice. Among them, there are 15 cases where the sum is 1 - 6 (small), and there are 21 cases where the sum is 7 - 12 (big). However, since it is impossible for the two dice to appear, the actual probability of small appearing is 5/11 (about 45.45%), and the probability of big appearing is 6/11 (about 54.55%). If there were three dice, each die would have six situations, and there would be a total of 6x6x6 = 216 combinations. For example, if one calculated the probability of rolling a big die, there would be three kinds of big situations (namely, 4, 5, and 6 points) for each die. There were a total of 3×3×3 = 27 kinds. Therefore, the probability of a big situation appearing was 27 × 216 = 1/8. Similarly, the probability of a small situation appearing was also 1/8. The probability of a leopard appearing (three dice with the same number of points, such as 111, 222, etc.) was 6 × 216 = 1/36. In addition, in theory, if the structure of the die was uneven, for example, the dots were hollowed out, and the six small round pits on the six dots were lighter than the one on the opposite side, then the probability of the six appearing would be greater than the one. However, in the ideal standard die situation, the probability of each number was 1/6. At the same time, there were many other situations in the probability calculation of dice rolling, such as the probability calculation of the sum of two dice numbers being odd, which could be solved by different probability methods (such as the step-by-step probability calculation method in junior high school or the combination knowledge method in high school). Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
1 answer
2026-07-30 18:15
dice-rolling probability
The condition probability refers to the probability of event A happening under the condition that event B has already happened. It is recorded as P(A| B)。The following is an example analysis of the probability of dice rolling. Suppose we have two dice. Event A is that the sum of the two dice is 8, and Event B is that the first die rolls a 3. First, calculate the probability of event A without any conditions. There were a total of 6×6 = 36 possibilities for the outcome of the two dice. There are five cases where the sum of points is 8:(2,6),(3,5),(4,4),(5,3), and (6,2), so P(A)=5/36. Then, the probability of event B is calculated. The probability of the first die rolling a 3 is 1/6, which is P(B)=1/6. The only situation where both events A and B occur at the same time is (3,5), so P(A Empyrean B)=1/36. According to the formula P(A| B)=P(A Empyrean B)/P(B). Under the condition that the first die rolls a 3, the probability of the sum of the two dice points being 8 is P(A| B)=(1/36)/(1/6)=1/6。 For example, Event C was the difference between the two dice being 1, and Event D was the second die rolling a 4. Similarly, P(C) was first found. There were 10 cases where the difference between the points was 1:(1,2),(2,3),(3,4),(4,5),(5,6),(2,1),(3,2),(4,3),(5,4), and (6,5), so P(C)=10/36. The probability of event D is P(D)=1/6. There are two cases where events C and D occur at the same time: (3,4) and (5,4), so P(C Empyrean D)=2/36. Under the condition that the second die rolls a 4, the probability of the difference between the two dice being 1 is P(C| D)=(2/36)/(1/6)=1/3。 In short, when calculating the conditioned probability of rolling the dice, the key was to clarify the relationship between the events, separately calculate the probability of the event occurring alone and the probability of them occurring at the same time, and then use the conditioned probability formula to calculate. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
1 answer
2026-07-31 18:05
How can 'Surprises in Probability Seventeen Short Stories' help in learning probability?
By reading this book, you get to see probability in action. The stories might show different types of probability distributions, like the binomial or normal distribution, in a more accessible way. They can also show how probability is used in decision - making, which is a very practical aspect of probability theory.
1 answer
2024-11-21 13:13
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