When the fermentation reaction between alcohol and concentrated sulfuric acid takes place, the reaction equation is: CH CH2-Ox + HO-NO <2>(concentrated H <2> SO2 <2>, heating) → CH CH2-O-NO <2>+ H <2> O. During the reaction, the alcohol degenerates the alcohol and the sulfuric acid dehydrogenates to form the ester of nitrates. Read more exciting novels for free
1. ** Reaction law of nitrates and metals ** - ** Passivation phenomenon **: Metal such as iron, aluminum, and aluminum are easily dissolved in dilute sulfuric acid, but they are not dissolved in cold concentrated sulfuric acid. This is due to the occurrence of a passive phenomenon. - ** Reaction with non-active metals ** - When the metal activity order table showed that the metal reacted with the metal after hydrogen, it could be seen that the metal was first oxided by the acid, and then the metal reacted with the acid to form nitrates. The main reduction product of concentrated sulfuric acid was NO2, and the main reduction product of diluted sulfuric acid was NO. For example, the reaction of silver with concentrated sulfuric acid: <2Ag +2HNO3 (concentrated)= Ag2O +2NO2 + H2O>,<Ag2O +2HNO3 = 2AgNO3 + H2O>, the total reaction is <2Ag +2HNO3 (concentrated)= AgNO3 + NO2 + H2O>; The reaction of silver with diluted sulfuric acid: <3Ag +4HNO3 (diluted)= 3AgNO3 +NO +2H2O>. - ** Reaction with active metals **: When sulfuric acid acts with the metal before hydrogen in the metal activity order table, in addition to the corresponding nitrates, the sulfuric acid may be further reduced to substances such as <anno data-annotation-id ="00000000 - 4000 - 4000 - 4000 - 8000 - 9000000000"></anno>,</anno>, and </anno>. In general, active metals react with concentrated sulfuric acid to form <anno data-annotation-id ="00000000 - 4000 - 4000 - 8000 - 8000 - 90000000000"> NO2 </anno>, dilute sulfuric acid to form <anno data-annotation-id ="0000000 - 4000 - 4000 - 9000 - 900000000000"> NO </anno>, and extremely dilute sulfuric acid to form <anno data-annotation-id ="20000a000000 - 90000000000"></anno></anno></anno>. For example, the reaction of calcium with different concentration of sulfuric acid: - \(Mg + 4HNO_3(16mol/L)=Mg(NO_3)_2+2NO_2↑+2H_2O\) - \(3Mg + 8HNO_3(6mol/L)=3Mg(NO_3)_2+2NO↑+4H_2O\) - \(4Mg + 10HNO_3(2mol/L)=4Mg(NO_3)_2+N_2O↑+5H_2O\) - \(4Mg + 10HNO_3(1mol/L)=4Mg(NO_3)_2+NH_4NO_3+3H_2O\) - \(5Mg + 12HNO_3(0.5mol/L)=5Mg(NO_3)_2+N_2↑+6H_2O\)。Moreover, the thinner the sulfuric acid was, the lower the valency of the nitrogen in the reduction product. However, it could not be mistaken that the dilute sulfuric acid had a stronger oxidisation ability than the concentrated sulfuric acid. In fact, the more concentrated the sulfuric acid was, the stronger the oxidisation ability was. - ** Special Metal Reaction **: Metal such as tin, stibine, and tungsten do not have much effect on nitrates. They may form an oxide-like substance that is not dissolved in nitrates, but they cannot form nitrates. 2. ** Reaction law of sulfuric acid and non-metals **: When sulfuric acid and non-metals react, it only shows the oxidisation property. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between lithium and dilute sulfuric acid is: 3MG + 8HNO (dilute)== 3MG (NO) 2 + 2NO ^+4H2O; there is another reaction equation: MG +2HNO → MG(NO) 2 + H2O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Sulfuric acid and alcohol ester reaction product is sulfuric acid ester. Its name varies according to the type of sulfuric acid ester. If only one of the hydrogen atoms of sulfuric acid is replaced by a hydrogen radical, it is an acidic alkyi hydrogen sulfuric acid ester (O-alkyi sulfuric acid), for example, the washing agent, sodium-laurel sulfuric acid, which is derived from laurel alcohol and chloridic acid. If the two hydrogen atoms of sulfuric acid are all replaced by alkyls, it is a dialkyi sulfuric acid ester, such as diethyi sulfuric acid and dimethyi sulfuric acid. The molecular structure of sulfuric acid ester was R-O-SO2-O-R', where R and R'represented the alkyls or aromatic groups, respectively. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The products of the fermentation reaction between the two were water and ether. The reaction equation is: <br><br> CH3COON + C2H50H <br> CH3COOC2H5 + H2O. This reaction was irreversible. During the reaction, the acidic group ($-COON $) combined with the alcoholic group ($-Oh$), removing a water atom to form the ester. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the two substances would produce a mixture of carbon dioxide and water. This reaction helped maintain the stability of the blood's pH. It had little effect on the blood's pH. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
In the reaction of preparing bromic ether, the first reaction was the reaction between concentrated sulfuric acid and the solution of the acid.(It can only produce bisulfuric acid, which can be referred to the reaction with NaCl2). The reaction equation is [H_{2} SO4}+ NaBr2 = NaHSO4 + Brr]. Then the formed [Brr] will react with alcohol. Under the conditions of concentrated sulfuric acid absorbing water and heating, the bromoether will be vaporized. The reaction equation is [Brr + CH3} CH2} 0H = CH3} CH2} Br2 + H2}O]. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Cyclohexene was added to the acidic solution of sulfuric acid, which would undergo an oxidization reaction. The carbon-carbon double bond would be broken and then be oxided into a starch group. During the reaction, the purple color of the solution of sulfuric acid would disappear. This was because cyclohexene was an aromatic, which had a reducing property. The carbon-carbon double bond in it was easily oxided by the strongly oxidisable, acidic, and acidic potassium Permanganate. When the potassium Permanganate was reduced in the reaction, the Mn (7) ion was reduced to Mn (7) ions of other valences, so the color of the solution became lighter until it disappeared. The reaction equation was: 5C6H10 + 8KMnO4 + 12H2SO4 =5 (HOCC (CH2) 4COON)+4K2SO4 + 8MnSO4 + 12H2O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction of sulfuric acid with different solutions was different: - During the reaction between the solution of sulfuric acid and the solution of the solution of - The acid reacted with rust (mainly composed of iron dioxide), dissolving and removing the rust. After the reaction, the solution turned yellow. - When sulfuric acid reacted with iron trioxid, reddish-brown floccule precipitations were dissolved to form a yellow solution; when sulfuric acid reacted with copper trioxid, blue precipitations were dissolved to form a yellow-green solution; when sulfuric acid reacted with copper dioxide, black solid was dissolved to form a yellow-green solution. - Gas was formed when the acid reacted with the metal, and it reacted with the metal. When the acid reacted with iron, the solution turned light green and released gas. When the acid reacted with aluminum, gas was formed. - When the solution is dropped into a solution (not specified) and vibrated while dropping, it may start to drop without any phenomenon. When a certain substance in the solution is basically transformed into another substance, gas will start to escape continuously (because the composition of the solution is not specified, only one possibility is provided). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Based on context alone The reaction between sulfuric acid ester and alcohol was usually a nuclophile substitution reaction. During the reaction, the oxygen atom in the alcohol acted as a nuclophile to attack the partially positively charged central atom in the sulfuric acid ester (usually the carbon atom or sulfur atom attached to the sulfuric acid radical, depending on the specific structure of the sulfuric acid ester). For example, when a common sulfuric acid ester reacted with an alcohol, the alcohol's oxygen would replace one of the methyls in the sulfuric acid to form ether compounds and the negative ion of the methyls. The reaction conditions may vary depending on the structure of the sulfuric acid ester and the alcohol. It is usually carried out in an appropriate solution (such as an organic solution). Sometimes, a certain temperature or catalyst may be needed to promote the reaction. However, he had to be extra careful when operating reactions involving sulfuric acid ester because many sulfuric acid ester were highly toxic. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between acid and indicator: KHIn/(H+)=(In-)/(HIn)=a/(a-c). Using litmus as an example, the equilibrium of the ions was HIn = In- + H+. However, it should be noted that the acid and base indicator will change color when it meets an acidic or basic solution. The actual color change is the acid and base indicator, not the solution itself. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>