The reaction of sulfuric acid with different solutions was different: - During the reaction between the solution of sulfuric acid and the solution of the solution of - The acid reacted with rust (mainly composed of iron dioxide), dissolving and removing the rust. After the reaction, the solution turned yellow. - When sulfuric acid reacted with iron trioxid, reddish-brown floccule precipitations were dissolved to form a yellow solution; when sulfuric acid reacted with copper trioxid, blue precipitations were dissolved to form a yellow-green solution; when sulfuric acid reacted with copper dioxide, black solid was dissolved to form a yellow-green solution. - Gas was formed when the acid reacted with the metal, and it reacted with the metal. When the acid reacted with iron, the solution turned light green and released gas. When the acid reacted with aluminum, gas was formed. - When the solution is dropped into a solution (not specified) and vibrated while dropping, it may start to drop without any phenomenon. When a certain substance in the solution is basically transformed into another substance, gas will start to escape continuously (because the composition of the solution is not specified, only one possibility is provided). Read more exciting novels for free
When the iron reacted with the copper sulfuric acid solution, the surface of the iron layer would release a red substance, and the solution would turn from blue to light green and finally brown. This was because the copper sulfuric acid solution was blue and weakly acidic, so the reaction first corroded the iron and formed the iron ions. The iron ions solution was light green, causing the solution to change from blue to light green. At the same time, because the metal activity of iron was stronger than copper, a replacement reaction occurred. The copper ions in the solution were replaced and reduced to copper. The copper was red, and red substances were separated from the surface of the iron. Subsequently, the iron ions in the solution were unstable and would continue to be oxided into iron ions. The iron ions in the solution were brown, so the solution would turn from light green to brown. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The quality of the solution did not change when the diluted sulfuric acid reacted with the solution. There were two reactions between dilute sulfuric acid and NaOx. The reaction equations were: H_{2} SO4 + 2NaOx = Na_{2} SO4 + 2H2}O and H_{2} SO4 + NaOx = NaHSO4 +H_{2}O. The substances before and after the reaction followed the law of conservation of mass, and the mass of the solution remained unchanged. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the two substances would produce a mixture of carbon dioxide and water. This reaction helped maintain the stability of the blood's pH. It had little effect on the blood's pH. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between lithium sulfuric acid solution and soda ash will produce lithium dioxide and soda ash. The reaction equation is: Li Chi SO2 + 2NaOx--> 2LiOx + Na Chi SO2. The lithium dioxide was a white deposit, and due to its low dissolution, it was easy to separate out, which would cause the reaction to move forward. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There were different opinions on whether or not the reaction between the two substances occurred. One view was that silver chloride-soda would react to produce silver-white silver silver precipitations and NaCl2, and the silver-white precipitations could easily be converted to brown silver oxide-soda. The other view was that the reaction could not be carried out because the reaction between base and salt required the salt to be dissolved, while AgCl2 was difficult to dissolve. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Cyclohexene was added to the acidic solution of sulfuric acid, which would undergo an oxidization reaction. The carbon-carbon double bond would be broken and then be oxided into a starch group. During the reaction, the purple color of the solution of sulfuric acid would disappear. This was because cyclohexene was an aromatic, which had a reducing property. The carbon-carbon double bond in it was easily oxided by the strongly oxidisable, acidic, and acidic potassium Permanganate. When the potassium Permanganate was reduced in the reaction, the Mn (7) ion was reduced to Mn (7) ions of other valences, so the color of the solution became lighter until it disappeared. The reaction equation was: 5C6H10 + 8KMnO4 + 12H2SO4 =5 (HOCC (CH2) 4COON)+4K2SO4 + 8MnSO4 + 12H2O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between acid and indicator: KHIn/(H+)=(In-)/(HIn)=a/(a-c). Using litmus as an example, the equilibrium of the ions was HIn = In- + H+. However, it should be noted that the acid and base indicator will change color when it meets an acidic or basic solution. The actual color change is the acid and base indicator, not the solution itself. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the solution of the two metals would result in the formation of the two metals, namely, the sulfuric acid and the sulfuric acid. The color of the solution gradually changed from green to bright blue. The reaction equation was: Mn +2CrCl2 = Mn +2CrCl2, and the ion equation of the reaction was: Mn +2Cr3 === Mn +2Cr2 (because of the order of metal activity: Mn> Mn). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Cyclohexyl-benz-lene reacted with acidic potassium permanganate. Cyclohexylbenzen was a homolog of benzen. When the carbon atom on the benzen ring had hydrogen, it could be oxided by the solution of potassium permanganate. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between Ba(Ce) 2 and sulfuric acid (HQ) will produce hydrogen cyanide (HQ) gas. The reaction equation is Ba(Ce) 2 + 2HQ = BaCl2 + 2HQ. Barium cyanide is an extremely toxic substance. When exposed to high heat or acid, it will produce a highly toxic cyanide gas. When operating a reaction involving potassium cyanide, safety regulations must be strictly adhered to. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>