When hydrogen (H <2>) and iodo (I <2>) react, both hydrogen and iodo are gaseous, and the reaction equation is H <2>(g)+I <2>(g)= 2Hi (g). The gaseous state of hydrogen iodinate (Hi) was also gaseous. Moreover, the reaction was a irreversible reaction. When heated to 500 degrees Celsius or above, hydrogen iodinate would decompose into hydrogen and iodine-like vapor. Read more exciting novels for free
The chemical equation for the reaction of a halo gas (such as Cl2 <anno data-annotation-id ="cdf3c12 - 4c10 - 4c10 - 4c10 - 9c1111111124"> Cl2 </anno>) with a solution of NaClO </anno> is: The chemical equation for the reaction of Bromine and Iodine at room temperature with a solution of NaOx at room temperature is X <2>+2NaOx = NaX + NaOx + H <2> O <3>(X <3> represents either Bror I <3>). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
不同饱和气体与氢气反应情况不同: - 若饱和气体为氧气,氢气和氧气在点燃的条件下反应生成水,反应方程式为\(2H_{2}+O_{2}\stackrel{点燃}{=\!=\!=}2H_{2}O\)。现象为产生淡蓝色火焰,放出热量,如果在火焰上方罩一个干冷的烧杯,烧杯内壁会有水雾出现。 - 若饱和气体为氯气,氢气和氯气反应生成氯化氢气体,反应方程式为\(H_{2}+Cl_{2}\stackrel{点燃或光照}{=\!=\!=}2HCl\)。现象为安静燃烧(氢气在氯气中燃烧)时发出苍白色火焰,放出热量,瓶口有白雾(氯化氢气体与空气中水蒸气结合形成盐酸小液滴);若光照条件下反应则会发生爆炸。 对于氮气,在高温、高压、催化剂条件下氢气和氮气反应生成氨气,反应方程式为\(N_{2}+3H_{2}\stackrel{高温、高压、催化剂}{=\!=\!=}2NH_{3}\)。反应现象是气体颜色无明显变化(因为反应物和生成物均为无色气体),反应容器壁会有发热现象(因为是放热反应)。 如果是二氧化碳与氢气反应,在特殊条件下(如我国中科院团队研究的情况)二氧化碳和氢气反应可制成汽油(成分复杂,反应复杂未以简单方程式表示),从反应本身来看没有明显的如燃烧、颜色变化等特殊现象。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
Ba(NO3)2 is easily dissolved in water and does not react with water. It will not produce gas, so there is no gas formation phenomenon. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction equation between helium- 3 (He - 3) and helium (D) was He3 + d = He4 + p + 18.4MeV, but this reaction had a side reaction, which would produce neutrons, and other reactions would occur between the two. For example, the two reactions were: Deuterated + Deuterated ==> Helium 3 + n and Deuterated + Deuterated ==> Tritium + p. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When the ratio of the reaction between the two was 1:1, the chemical equation was NaHSO4 +Ba(SH)2==H2O+ NaOx + BaSO4. The reaction produced water, the precipitations of soda, and the precipitations of bis sulfuric acid. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When the reaction between the two was carried out, the reaction equation was: Mn + H ^SO2 = Mn ^SO2 + H ^. The reaction between the two was to produce hydrogen and sulfuric acid. When the reaction between the two was carried out, the reaction equation was: Mn +2H ^SO2 (concentrated)= Delta = Mn ^SO2 + Mn ^SO2 + 2H ^O2, which was a reduction reaction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
During the reaction between Butanone and hydrogen, due to the fact that Butanone had a carbonyl-group and an active hydrogen adjacent to the carbonyl-group, the Pi bond in the carbonyl-group in the keto was broken during the reaction. A H was added to each of the C and O, and a hydrogen reduction reaction occurred to produce 2 -Butanol. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction mechanism between alkyls and halos was a substitution reaction of free radical. In the reaction, the halo (such as pure chorine, pure bromine, and not chorine water or bromine water) under the conditions of light/heat/free radical initiator, X-X was split into two X-free radical, X -and the HX-H on the alkyls formed hydrogen halo, and the alkyls left the alkyls free radical, which then reacted with X-X to form X -, and the cycle reaction could continue. The reaction between an aromatic compound (such as alkyne and alkyne) and a hydrogen atom was mainly an addition reaction. The double bond in an aromatic compound was a sigma-bond and a pi-bond. The pi-bond was more unstable and easy to break. The double bond opened to become a single bond, and the broken small half bond formed a covalent-bond with the hydrogen atom. In addition, the addition reaction of the hydrogen atom with the unsatured carbon could also be carried out. Aromatic compounds could only be substituted with a catalyst (such as iron trihalide, aluminum trihalide, iron powder, etc.), except for very active compounds (such as aromatic amine, vitamins, etc.). Fatty acid could only be substituted with a catalyst of red phosphorus, which generally produced an alpha substituted product. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction mechanism of hydrogen production from gasoline mainly had the following methods: 1. The steam reforming reaction (MPR) of the gasoline was one of the most common methods. The reaction equation is CH30H + H2O → CO2+ 3H2. In this reaction, the reaction between the alcohol and water vapor occurred under the effect of a catalyst to produce carbon dioxide and hydrogen. This reaction process was relatively complicated, involving the activation of the alcohol molecules, the breaking and reassembly of chemical bonds, and many other steps. 2. The reaction equation is CH30H + 1/2O2 → CO2+ 2H2. In this reaction, the partial oxidization of the oxygen and the alcohol produced carbon dioxide as well as hydrogen. The characteristic of this method was that the reaction speed was relatively fast, but the control of the reaction process was relatively difficult. It was necessary to accurately control the amount of oxygen supplied to avoid over-oxidization or incomplete reactions. 3. Alcohol autothermal reforming (ATR): It was a hydrogen production method that combined the steam reforming reaction and the partial oxidization reaction of the alcohol. The reaction equation can be roughly expressed as CH30H + xO2 +(1 - x)H2O → CO2+ (3 - 2x)H2. This method used the heat generated by the partial oxygen reaction to supply the steam reforming reaction, thus improving the energy utilization efficiency. It had certain advantages in practical applications. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The mixture of hydrogen peroxide-hydrogen peroxide-acid and hydrogen iodinate-acid would result in an oxido-reduction reaction. The reaction equation is [H2O2 + 2Hi]. In this reaction, the valency of the oxygen element in the hydrogen peroxid decreased from-1 to-2, showing its oxidisation, while the valency of the iodine-element in the hydrogen iodinate increased from-1 to 0, showing its reduction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>