Ask a question about the C language. Thank you in advance. The questions are below. If they are correct, I promise to give everyone extra points.

One. The following program output is ()
#include<stdio.h>
main()
{
char b[30],*chp;
strcpy(&b[0],GH);
strcpy(&b[1],DEF);
strcpy(&b[2],ABC);
printf(%sn,b);
}
I hope everyone can give me an explanation. I don't need an answer. What I want is a train of thought. Thank you!
If there are any handwriting errors, they are purely cleric errors.

Answer 1

The questions were as follows:

How to implement a function that can convert every element in an array into a string and then join them together?

Answer:

To implement this function, you need to use a struct to define the element type of the array. The specific implementation method is as follows:

```c
#include <stdioh>
#include <stringh>

//define struct
typedef struct {
char str[100];
} String;

//define a function
String (String arrr [] int n) {
int i j;
for (i = 0; i < n; i++) {
for (j = 0; j < n-i-1; j++) {
if (arr[j] == '\0') {
arr[j+1] = arr[j];
}
}
}
return arr;
}
```

In this function, we first define a `String` structure that contains an array of strings. Then I defined a function `String` that accepts an `String` array and an array length as parameters. Inside the function, use two nesting loops to traverse each element in the array. If the current element is an empty string, the current element will be pieced together with the string that has been pieced together. Finally, it returned the assembled string array.

Using this function, you can convert every element in the array into a string and join them together. The specific way to call it is as follows:

```c
String arr[] = {Hello World !};
int n = sizeof(arr) / sizeof(arr[0]);
String result = String (arrn);
print (%s/n result); //Print Hello World!
```