Which is more cost-effective, samsung s 23 small cup, medium cup, and large cupThe Galaxy S23 series includes the S23 (Small), S23+(Medium), and S23 Ultra (Large).
From the perspective of the screen, the S23 and S23+ had FHD+ straight screens, while the S23 Ultra had a 6.8-inch QHD+ curved screen. The S23 Ultra's screen quality was even higher. The S23 Ultra's main camera had been upgraded to 200 million resolution, which gave it an advantage in terms of photography.
In terms of memory, the S23 and S23+ both came with 8GB of memory, while the S23 Ultra had 12GB +256GB and other options.
In terms of battery capacity, the S23 Ultra's battery capacity was relatively larger. If you have high requirements for screen quality, photo effects, memory, and battery capacity, and have a sufficient budget, the S23 Ultra is more cost-effective.
However, if you were pursuing a small-screen flagship experience, the S23 with the support of the Snapdragon 8 Gen2, the 3900mAh battery life pressure was not too big. For small screen enthusiasts, it was a rare 6.1-inch small cannon in the flagship product. The price may be more appropriate, and it also had a certain cost-performance ratio.
The S23+ was between the S23 and S23 Ultra in terms of screen, memory, and battery. The price-performance ratio depended on the individual's demand for the various functions of the phone.
In general, the S23 Ultra was cost-effective for users who pursued extreme photography, high configuration, and a large screen experience. The S23 Ultra was more cost-effective for users with limited budget and preferred small screen phones. The S23+ was suitable for users who had certain performance requirements but did not have the budget to buy the S23 Ultra.
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What is the size of the master cup?Jianzhan can be divided into three types: large, medium and small. The diameter of the large device is about 15cm, the diameter of the medium device is about 11 - 15cm, and the diameter of the small device is about 11cm. However, when used as the master cup, there were also examples of different sizes. For example, some of the cups had a diameter of 76.7mm, a diameter of 82.3mm, a diameter of 89.4mm, a diameter of 82.3mm, a diameter of 89.4mm, a diameter of 82.3mm, a diameter of 82.3mm, and a diameter of 6.2X5.1. The size of the cup was 6.2X5.1, and the capacity was 65ml.
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small to largeThe following are a few common sorting algorithms:
##1. Bubble sort
1. ** Principle **
- It repeatedly visited the sequence to be sorted, comparing two adjacent elements each time, and if the order was wrong (such as the larger element being before the smaller element), it would swap them.
- He repeated the process of searching the sequence until there were no more elements that needed to be exchanged. At that time, the sequence was completed.
2. ** Instance **
- Suppose there is a sequence [5, 3, 4, 6, 2].
- The first round of comparison: first compare 5 and 3, because 5 > 3, the exchange is [3, 5, 4, 6, 2]; then compare 5 and 4, 5 > 4, the exchange is [3, 4, 5, 6, 2]; then compare 5 and 6, no exchange; then compare 6 and 2, 6 > 2, the exchange is [3, 4, 5, 2, 6].
- The second round of comparison: starting from 3, compare 3 and 4 without swapping; compare 4 and 5 without swapping; compare 5 and 2, 5 > 2, swap to get [3, 4, 2, 5, 6].
- The third round of comparison: compare 3 and 4 without swapping; compare 4 and 2, 4 > 2, swap to get [3, 2, 4, 5, 6].
- The fourth round of comparison: compare 3 and 2, 3 > 2, swap to get [2, 3, 4, 5, 6]. At this moment, the sequence was completed.
##2. Sorting
1. ** Principle **
- Its basic idea was to select a certain element from the data to be sorted according to the specified rules, and then exchange the positions according to the rules to achieve the purpose of sorting.
- The first time, the minimum value was selected from the entire array and exchanged with the first element of the array; the second time, the minimum value was selected from the remaining elements (except for the first element that had been sorted) and exchanged with the second element of the array; and so on.
2. ** Instance **
- For the sequence [5, 3, 4, 6, 2].
- First round: First assume that 5 is the smallest value, then compare it with the following elements and find that 2 is the smallest. Exchange 2 and 5 to get [2, 3, 4, 6, 5].
- The second round: Start from 3. Assuming that 3 is the smallest value, compare it with the later ones and find that 3 is the smallest. Without swapping, the sequence is still [2, 3, 4, 6, 5].
- The third round: Start from 4. Assuming that 4 is the smallest value, compare it with the later ones and find that 4 is the smallest. Without swapping, the sequence is still [2, 3, 4, 6, 5].
- The fourth round: Starting from 6, assuming that 6 is the smallest value, compare it with the later ones and find that 5 is the smallest. Exchange 5 and 6 to get [2, 3, 4, 5, 6].
##3. Heap Sorting
1. ** Principle **
- First of all, he had to understand the concept of a heap. A heap had the properties of a complete tree. If the value of each node is less than or equal to the value of its children, it is called a small top heap.
- The basic idea of heap sorting was to construct the sequence to be sorted into a small top heap. At this time, the minimum value of the entire sequence was the root node at the top of the heap. If it was exchanged with the last element, the last element would be the minimum value. Then, the remaining n - 1 elements were reconstructed into a heap, which would get the second smallest value of n elements. Repeating this process would result in an orderly sequence.
2. ** An example (simple)**
- Suppose there is a sequence [5, 3, 4, 6, 2].
- First, construct it into a small top heap (the detailed steps are omitted here) to obtain a small top heap structure. The top heap element of 2 is the minimum value.
- Exchange 2 with the last element 6 to get [6, 3, 4, 2, 5], then rebuild the top heap of the sequence except for the last element 6, and continue this process until the sequence is orderly.
##4. Counting Sorts (applicable to a certain range of numbers)
1. ** Principle **
- This was a sorting algorithm that was not based on comparison.
- When sorting a certain range of numbers, its complexity is O (n + k)(where k is the range of numbers). It counted the number of times each number appeared in the sequence, and then according to the results of the statistics, the numbers were output in order to achieve sorting.
2. ** example (Assuming the range of the whole number is 0 - 9)**
- For the sequence [5, 3, 4, 6, 2].
- First, count the number of times each number appears. For example, 2 appears once, 3 appears once, 4 appears once, 5 appears once, and 6 appears once.
- Then, in the order of 0 - 9, the elements in the sequence were output according to the statistics, and [2, 3, 4, 5, 6] was obtained.