There was no reaction between the two. Because it did not meet the conditions for the metathesis reaction to occur, there was no reaction equation or reaction phenomenon. Read more exciting novels for free
There is no chemical reaction between the two of them. In terms of chemical principles, the conditions for the metathesis reaction to occur were the formation of precipitations, gases, or water. The mixture of the two did not meet the conditions for the metathesis reaction to occur, so there would be no reaction. Therefore, there was no reaction equation, reaction phenomenon, and phenomenon analysis. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The solution of NaCl2 and NaNO2 did not react, so there was no reaction equation. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between hydrogen and Cl2 was H ^+ Cl2 = 2HQ (Condition: Illumination or ignition). [Phenomenon: When hydrogen and Cl2 react, if it burns quietly, it will emit a pale flame, and there will be white fog at the mouth of the gas collector. If hydrogen and Cl2 are mixed and illuminated, it will explode.] <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. **硫与铁反应** - 方程式:\(Fe + S \stackrel{\triangle}{=\!=\!=} FeS\)(硫化亚铁,黑褐色) - 现象:反应剧烈,生成黑褐色固体。 2. **硫与铜反应** - 方程式:\(2Cu+S \stackrel{\triangle}{=\!=\!=}Cu_{2}S\)(硫化亚铜,黑色) - 现象:有黑色固体生成。 3. **硫与汞反应** - 方程式:\(Hg + S=\!=\!= HgS\)(硫化汞,黑色) - 现象:常温下迅速反应,生成黑色固体。 4. **硫与氢气反应** - 方程式:\(H_{2}+S \stackrel{点燃}{=\!=\!=}H_{2}S\) - 现象:有臭鸡蛋气味的气体生成。 5. **硫与氧气反应** - 方程式:\(S + O_{2}\stackrel{点燃}{=\!=\!=}SO_{2}\) - 现象:有刺激性气味的气体生成。 6. **硫与热的碱溶液反应** - 方程式:\(3S + 6NaOH \stackrel{\triangle}{=\!=\!=}2Na_{2}S+Na_{2}SO_{3}+3H_{2}O\)(离子方程式为\(3S + 6OH^{-}\stackrel{\triangle}{=\!=\!=}2S^{2 -}+SO_{3}^{2 -}+3H_{2}O\)) - 现象:无明显特殊现象(溶液中的反应,反应后溶液成分发生改变)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
|content| particulars| |--|--| |reaction equation| CH₃CH₂Br + NaC≡CCH₃ → CH₃CH₂C≡CCH₃ + NaBr| |phenomenon| The reference materials did not mention this reaction phenomenon, so it was impossible to answer accurately.| <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between red phosphorus and Cl2 would result in two reactions. The first reaction is the reaction of red phosphorus with Cl2 to form phosphorous tri-(2P +3Cl2) [2PCl3], and the phosphorus trichosphate was a colorless liquid; the phosphorus trichosphate then reacted with the Cl2 to form phosphorus pentachloride (<br><br>"<br>" 2PCl3 ", and the phosphorus trichosphate was a colorless liquid; the phosphorus trichosphate then reacted with the Cl2 to form phosphorus pentachloride (<br>" PCl3 + Cl2 "<br>" stacking " Phosphorous pentachlorides was a white solid. During the reaction process, the white solid particles of phosphorus pentachlorinate formed smoke, and the colorless liquid droplets of phosphorus tricolor formed fog, so the reaction phenomenon was white smoke. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction equation between sulfur and hydrogen is: H2 + S (====) H2S. However, the reference materials did not provide a video tutorial of this reaction phenomenon. Sorry, I can't give an accurate answer. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
以硫酸为例,二氧化硫与酸性重铬酸钾反应的化学方程式为:\(K_{2}Cr_{2}O_{7}+3SO_{2}+H_{2}SO_{4} = K_{2}SO_{4}+Cr_{2}(SO_{4})_{3}+H_{2}O\),其离子方程式为:\(Cr_{2}O_{7}^{2 - }+3SO_{2}+2H^{+}=3SO_{4}^{2 - }+2Cr^{3 + }+H_{2}O\)。 在这个反应中,重铬酸钾(\(K_{2}Cr_{2}O_{7}\))中的铬元素从 +6价被还原为 +3价的\(Cr^{3 + }\),而二氧化硫(\(SO_{2}\))被氧化为硫酸根离子(\(SO_{4}^{2 - }\))。反应现象方面,溶液的颜色会发生变化,由于重铬酸根离子(\(Cr_{2}O_{7}^{2 - }\))通常具有特定颜色(一般为橙红色),反应后生成的\(Cr^{3 + }\)离子具有不同颜色(一般为绿色),所以反应过程中可以观察到溶液颜色由橙红色转变为绿色。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The flame reaction could be used to detect the Na ion in the salt. The flame reaction of the Na element was yellow. The specific operation was as follows: Method 1 (tweezers-cotton-alcohol method): Use tweezers to take a small ball of cotton and suck up a little 95% alcohol. Squeeze the alcohol on the cotton dry. Dip the cotton with some salt powder (grind it fine) and light it to see a yellow flame. Method 2 (iron wire method):(1) Take a thin iron wire, wipe one end with sandpaper, and then burn it on the external flame of the alcohol lamp until there is no yellow flame;(2) Dip the end of the iron wire in water, and then dip it in some salt powder;(3) Light a new alcohol lamp (the lamp head and wick are clean, and the alcohol is pure);(4) Put the iron wire stained with salt powder on the tip of the external flame to burn. At this time, there is a small yellow flame on the tip of the external flame, which is the salt flame. If it was a student's experiment, it would be difficult to see the tip of the flame because most alcohol lamps were not clean. It could be changed to a steel wire dipped in salt and placed in any part of the outer flame that had a blue flame. If the yellow flame covered the blue flame, it could be considered that the yellow flame was the salt flame. In addition, a small amount of AgNO could be added first. If a white deposit was produced, it might be salt. However, this method could not identify salt alone. It also needed to be combined with other methods such as flame reaction, because salt would also produce a similar phenomenon. The two could be further distinguished by flame reaction. The yellow flame was salt. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There was no chemical reaction between the two. However, when the salt was added to the calcium dioxide, the dissolution of the calcium dioxide would increase. This was because of the salt effect. In the presence of a strong solute (such as calcium dioxide), the dissolution of some solute (such as calcium dioxide) would be greater than in water. This phenomenon of increasing the dissolution of the precipitations due to the addition of a strong solute was called the salt effect. It had to be distinguished from the same ion effect, which would reduce the dissolution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>