You just gave it the name " Diagram of the kinetic change of sulfur dioxide to sulfuric acid reaction ". There's no more content. I can't reorganize it according to the requirements. You can add some information such as the characteristics of this chart and the relevant reaction conditions. Read more exciting novels for free
The reaction between diluted sulfuric acid and sulfur dioxide produces water, nitrogen dioxide gas, and sulfur precipitations. The reaction equation is: 8HNO +3Na ^S = 4H ^O + 2NO ^+6NaNO + 3S. The reaction between concentrated sulfuric acid and sulfur dioxide produces water, nitrogen dioxide gas, and sulfur precipitations. The reaction equation is: 4HNO + Na ^S = 2H ^O + 2NO ^+ 2NaNO + S. However, there was also a view that the reaction could not produce sulfur and sulfur. Instead, it would produce either sulfur and sulfur, or sulfur and water, or other nitrogen and oxygen compounds. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Sulfur dioxide ($SO2 $) and sulfuric acid ($H2SO4 $) had different reactions. If it was concentrated sulfuric acid, the reaction equation was: 2H2SO4 (concentrated)+ SO2 = 2H2O +3SO3. The phenomenon was that the pungent gas ($SO2 $) was absorbed by concentrated sulfuric acid, and a small amount of smoke might be seen during the reaction ($SO3 $might form acid mist in the air). If it was diluted sulfuric acid, it would basically not react. He could simply draw a picture with the reaction equation written on it and a small picture beside it to indicate the phenomenon of smoke production. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When concentrated sulfuric acid was added to the solid of the sulfur dioxide, since the concentrated sulfuric acid had a strong oxidisation property and the sulfur dioxide had a reduction property, the two would undergo an oxidoreduction reaction. The reaction equation is [Na ^S + H ^SO (concentrated)= S + Na ^SO + H ^O]. The reaction phenomenon was the formation of sulfur, and at the same time, the formation of sulfuric acid and water. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
过氧化钠与硫酸反应实际分两步进行,第一步反应为\(2Na_{2}O_{2}+2H_{2}O = 4NaOH + O_{2}\),第二步反应为\(2NaOH+H_{2}SO_{4}=Na_{2}SO_{4}+2H_{2}O\),总的反应方程式为\(2Na_{2}O_{2}+H_{2}SO_{4}=Na_{2}SO_{4}+2NaOH + O_{2}\)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The reaction ion equation was: Cr2O72- +3SO2 + 2H + = 3SO42- +2Cr3 + + H2O. There was no reference to this reaction, so it was impossible to give an accurate answer. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Elemental sulfur can undergo an oxido-reduction reaction with concentrated sulfuric acid under heating conditions. Sulfur is oxided to sulfuric acid with a +6 valency, and concentrated sulfuric acid is reduced to nitrogen dioxide with a +4 valency. The reaction equation is: S +6HNO= heating = H ^SO+ 6NO ^+2H ^O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the solid of sulfur dioxide and concentrated sulfuric acid is Na2S +2H2SO4 (concentrated) == S +2H2O + SO2 + Na2SO4. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The condition of the metathesis reaction was that if there was an acid in the reagent, the reagent could not be dissolved in water. Otherwise, the reagent had to be dissolved, and the product had to have at least one of the three: precipitations, gas, and water. Neither of them was an acid, and the latter was also difficult to dissolve in water, so they couldn't react with each other. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
以硫酸为例,二氧化硫与酸性重铬酸钾反应的化学方程式为:\(K_{2}Cr_{2}O_{7}+3SO_{2}+H_{2}SO_{4} = K_{2}SO_{4}+Cr_{2}(SO_{4})_{3}+H_{2}O\),其离子方程式为:\(Cr_{2}O_{7}^{2 - }+3SO_{2}+2H^{+}=3SO_{4}^{2 - }+2Cr^{3 + }+H_{2}O\)。 在这个反应中,重铬酸钾(\(K_{2}Cr_{2}O_{7}\))中的铬元素从 +6价被还原为 +3价的\(Cr^{3 + }\),而二氧化硫(\(SO_{2}\))被氧化为硫酸根离子(\(SO_{4}^{2 - }\))。反应现象方面,溶液的颜色会发生变化,由于重铬酸根离子(\(Cr_{2}O_{7}^{2 - }\))通常具有特定颜色(一般为橙红色),反应后生成的\(Cr^{3 + }\)离子具有不同颜色(一般为绿色),所以反应过程中可以观察到溶液颜色由橙红色转变为绿色。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
There was no reaction between Na2SO4 and CH3COH. Because the acid was weak and the sulfuric acid was strong, the reaction of the weak against the strong usually could not happen. Therefore, there were no reaction equations and reaction phenomena, so it was impossible to provide a summary in the form of a table. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>