The ion equation of the reaction between the reagent and the acid would vary depending on the type of acid. Using sulfuric acid as an example: Borax will react with water: $Na2B4O7 + 7H2O = 2Na^+++4H3BO3 + 20H ^ -$. When it reacted with sulfuric acid,$Oh^ -$would react with $H^+$, and the total ion equation was: $B4O7 ^{2 -}+2H ^+++5H2O = 4H3BO3 $. Borax reacted with acid to form Boric acid ($H3BO3 $). Read more exciting novels for free
The ion equation of the reaction between dilute acetic-acid and koh is: (CH3COON + Ox ^- = CH3COO ^- + H2O). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
硼砂中的\(Na_{2}B_{4}O_{7}\)在酸溶液中反应的离子方程式为:\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。其书写思路如下: 1. 首先确定反应物和生成物,硼砂\(Na_{2}B_{4}O_{7}\)与酸反应生成硼酸\(H_{3}BO_{3}\)。 2. 然后根据物质的组成写出其离子形式,\(Na_{2}B_{4}O_{7}\)可拆分为\(B_{4}O_{7}^{2 -}\),酸中的氢离子\(H^{+}\)参与反应,反应后生成\(H_{3}BO_{3}\)(硼酸为弱酸,在离子方程式中写分子式)。 3. 根据电荷守恒和原子守恒配平离子方程式,得到\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
There was no reaction between Na2SO4 and CH3COH. Because the acid was weak and the sulfuric acid was strong, the reaction of the weak against the strong usually could not happen. Therefore, there were no reaction equations and reaction phenomena, so it was impossible to provide a summary in the form of a table. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between acid and indicator: KHIn/(H+)=(In-)/(HIn)=a/(a-c). Using litmus as an example, the equilibrium of the ions was HIn = In- + H+. However, it should be noted that the acid and base indicator will change color when it meets an acidic or basic solution. The actual color change is the acid and base indicator, not the solution itself. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between Na2SO4 and ClCl2 is Na2SO4 + Cl2 = NaHSO4 + Cl2. Because the HSO4 ^-in water was partially ionised, after adding a strong acid such as sulfuric acid, the reaction formed a weaker acidic HSO4 ^-ion. The ion equation for this reaction is: <i>(SO4 ^{2 - }+H^+ = HSO4 ^-<i>). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between $NaHSO3 $and $NaOx $is: $NaHSO3 + NaOx = Na2SO3 + H2O $. Rewriting it into an ion equation,$NaHSO3 $is an acid salt of a weak acid, which can be dissociated into $Na^+$and $HSO3 ^-$in solution.$NaH $is a strong base, which can be completely dissociated into $Na^+$and $Oh^-$in solution. After the reaction,$Na2SO3 $is a strong solute, which can be completely dissociated into $Na^+$and $SO3 ^{2 - }$. The ion equation is: $HSO3 ^-+ SH ^- = SO3 ^{2 - }+ H2O $. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Take the fermentation reaction of alcohol and sulfuric acid as an example, the chemical equation is: CH COOx + CH CH Ox $$ The chemical equation for the reaction of alcohol and sulfuric acid to produce ethvl nitrates is: C H CH + HNO $___→}$C₂H₅ONO₂ + H₂O。It should be noted that in the reaction of alcohol and sulfuric acid, the acid was dehydrated, and the alcohol was dehydralized. In addition, most of the reactions between alcohol and acid produce esters, but there are also some special cases. For example, when alcohol and bromic acid are mixed and heated, a substitution reaction occurs to produce bromolene: C H Oh + Brr $___→}$C H br + H O; Alcohol and concentrated sulfuric acid are mixed and heated together. At 170 ° C, a substitution reaction occurs to form ethene, and at 140 ° C, intermolecular dehydration occurs to form ether: C H Oh$\stacking {concentrated sulfuric acid 170 ° C}{-! -! -! -!→}$C ^H ^+ H ^O, C ^H SH + Ho - C ^H $\stacking rel {concentrated sulfuric acid 140 ° C}{-\!-\! -\!→}$C₂H₅ - O - C₂H₅ + H₂O。 <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
For the reaction between sulfur and metal, the following are the common reactions and situations: - Sulfur and iron reaction: The chemical equation is: FeS + S = (heating)FeS. This reaction does not involve free moving ions, so it cannot be rewritten as an ion equation. The phenomenon was the formation of black solid iron Sulphide. - Sulfur and copper reaction: The chemical equation is 2Cu + S = (heating) Cu2 S. Similarly, the ion equation cannot be written. The phenomenon was the formation of black cuprous sulfur solid. - Sulfur and Na reaction: The chemical equation is 2Na + S =(grinding)Na <2> S. There is no need to rewrite the ion equation. The phenomenon was that during the grinding process, a violent reaction formed a white solid of sulfur dioxide. - Sulfur and aluminum reaction: The chemical equation is 3S +2AI = Al2S, which cannot be rewritten as an ion equation. The reaction phenomenon was the formation of aluminum sulfur solid. - Sulfur and mercury reaction: The chemical equation is as follows: Mercury + S = HgS, which cannot be written as an ion equation. The reaction phenomenon is the formation of black mercury sulfur solid. In general, since most of these reactions were solid-state reactions or did not carry out the ionisation process in the solution system, there was basically no ion equation. Most of the reaction phenomena were the formation of the corresponding sulfur solid, and the color of the solid was different. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between Cl2 and Ox had different ion equations depending on the reaction conditions. - When Cl2 reacted with a cold, diluted solution of soda, the ion equation of the reaction was: [Cl2 + 20H ^- = Cl2 ^-+ ClO^-+ H2O]. - When Cl2 reacted with hot, concentrated solution of NaOx, the ion equation of the reaction was: [3Cl2 + 60H ^- = 5Cl2 ^-+ ClO3 ^-+3H2O]. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
硫酸和硝酸反应方程式如下: 1. \(HNO_{3}+H_{2}SO_{4}\to NO_{2}^{+}+H_{3}O^{+}+HSO_{4}^{-}\),在这个反应中,硝酸和硫酸发生反应,产生了亚硝酸离子\((NO_{2}^{+})\)、氢离子\((H_{3}O^{+})\)和硫酸氢根离子\((HSO_{4}^{-})\)。 2. \(HNO_{3}+H_{2}SO_{4}\to NO+NO_{2}+H_{2}O+HSO_{4}^{-}\),此反应中,硝酸与硫酸反应,产生了亚硝酸\((NO)\)和二氧化氮\((NO_{2})\),以及水和硫酸氢根离子\((HSO_{4}^{-})\)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>