The chemical equation for the replacement reaction between copper sulfuric acid solution and iron was: Iron was more mobile than copper. During the reaction, the surface of iron would be attached with red copper (metallic copper was a red metal with a metallic luster), and the solution would gradually turn from blue (blue for copper sulfuric acid solution) to light green (light green for iron sulfuric acid solution). During the reaction process, due to the weak acid nature of the copper sulfuric acid solution, iron was first corroded to form iron ions, and the color of the solution changed because of the light green color of the iron ion solution. At the same time, the copper ions in the solution were replaced by iron and reduced to copper, and copper adhered to the surface of the iron. Moreover, if the iron immersion area was not large enough and the concentration of the copper sulfuric acid solution was high, the reaction might stop at a certain level because the copper attached to the iron surface would protect the iron and prevent the reaction from continuing. In addition, the Fe2 + ions in the reacted Fe2 + were unstable and would continue to be oxided into Fe3 + ions. The Fe3 + ion solution would appear brown, and the solution might eventually turn from light green to brown. Read more exciting novels for free
When the iron reacted with the copper sulfuric acid solution, the surface of the iron layer would release a red substance, and the solution would turn from blue to light green and finally brown. This was because the copper sulfuric acid solution was blue and weakly acidic, so the reaction first corroded the iron and formed the iron ions. The iron ions solution was light green, causing the solution to change from blue to light green. At the same time, because the metal activity of iron was stronger than copper, a replacement reaction occurred. The copper ions in the solution were replaced and reduced to copper. The copper was red, and red substances were separated from the surface of the iron. Subsequently, the iron ions in the solution were unstable and would continue to be oxided into iron ions. The iron ions in the solution were brown, so the solution would turn from light green to brown. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation for the reaction between iron nails and copper sulfuric acid solution was: This reaction was a replacement reaction. Because iron was more mobile than copper, iron could replace copper from copper sulfuric acid solution. During the reaction, the surface of the nail was covered with a layer of red material. As the reaction progressed, the color of copper sulfuric acid solution gradually became lighter. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
电解硫酸铜溶液时,阳极反应式为\(4OH^{-}-4e^{-}=O_{2}\uparrow+2H_{2}O\),阴极反应式为\(2Cu^{2 +}+4e^{-}=2Cu\),总反应式为\(2CuSO_{4}+2H_{2}O = 2Cu+O_{2}\uparrow+2H_{2}SO_{4}\),实际减少的是\(Cu\)和\(O_{2}\),因此恢复原溶液要用\(CuO\)。如果加\(Cu(OH)_{2}\)就相当于加入\(CuO + H_{2}O\),会稀释溶液。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The reaction between iron (Iron) and copper (CuSO2) is a substitution reaction. Iron is more mobile than copper, and copper can be replaced. The reaction equation is: FeSO2 = FeSO2 + Cu2. The reaction phenomenon was: red substance (copper) was deposited on the surface of the iron layer, because copper was a red metal with metallic luster; the solution changed from blue (the color of copper sulfuric acid solution) to light green (the color of FeSO2 solution), and finally to brown. This was because the iron ions in the solution were unstable and would continue to be oxided into iron ions, and the iron ions in the solution would appear brown. From the reaction principle, the copper sulfuric acid solution was blue and weakly acidic, so the iron was corroded first, forming a pair of iron ions. At the same time, because the metal activity of iron was stronger than that of copper, a replacement reaction occurred, and the copper ions in the solution were replaced and reduced to copper. Because iron was a solid, after it was immersed in the copper sulfuric acid solution, the reaction occurred on the surface of the metallic iron, so the copper produced by the reaction would adhere to the surface of the metallic iron. If the immersion area was not large enough, and the concentration of the copper sulfuric acid solution was very high, the chemical reaction would stop when it reached a certain degree. The copper attached to the surface of the iron would protect the iron, so that it could not continue to react. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Esters can be subjected to a reaction of either acid or base. In an acidic environment, the ester's decomposition was irreversible, and sulfuric acid acted as a catalyst. Although the catalyst participated in the chemical reaction, its mass and chemical properties remained unchanged during the reaction, and it returned to its initial state after the reaction ended. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The iron nail and copper sulfuric acid undergo a replacement reaction, and the chemical equation is: During the reaction process, red copper would be formed on the surface of the nail and adhere to the surface of the nail. As the reaction progressed, the copper ions in the copper sulfuric acid solution would be replaced, and the copper sulfuric acid in the solution would gradually decrease. The color of the solution would gradually turn from blue to light green. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
铁与硝酸的反应: - 铁和稀硝酸反应:\(Fe + 4HNO_{3}(稀)=Fe(NO_{3})_{3}+NO↑+2H_{2}O\)。 - 铁遇浓硝酸在常温下会钝化,加热时反应:\(Fe + 6HNO_{3}(浓)\stackrel{△}{=}Fe(NO_{3})_{3}+3NO_{2}↑+3H_{2}O\)。 - 若\(Fe\)过量,会与\(Fe(NO_{3})_{3}\)继续反应:\(Fe+2Fe(NO_{3})_{3}=3Fe(NO_{3})_{2}\)。 铜与硝酸的反应: - 铜与稀硝酸反应:\(3Cu + 8HNO_{3}(稀)=3Cu(NO_{3})_{2}+2NO↑+4H_{2}O\)。 - 铜与浓硝酸反应:\(Cu + 4HNO_{3}(浓)=Cu(NO_{3})_{2}+2NO_{2}↑+2H_{2}O\)。 当铁铜混合物与硝酸反应时,若硝酸不足量,反应后生成硝酸盐,溶液中的盐含有\(NO_{3}^{-}\),再加稀硫酸提供\(H^{+}\),会发生氧化还原反应,再次溶解一部分金属。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The reaction between copper and sulfuric acid could be divided into two situations. If it was a reaction between copper and concentrated sulfuric acid, the phenomenon would be extremely obvious. The copper plate would quickly dissolve, and the solution would turn from colorless to blue-green. At the same time, a large amount of reddish-brown gas would be produced, which was nitrogen dioxide. What if copper reacted with dilute sulfuric acid? The copper would slowly dissolve, and the solution would turn blue, but the gas produced would be colorless nitrogen dioxide. However, the nitrogen dioxide would react with the oxygen in the air and turn into reddish-brown nitrogen dioxide. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Anhydrous copper sulfuric acid can react with water to form copper sulfuric acid. After heating copper sulfuric acid to lose crystal water, it can be restored to blue crystal copper sulfuric acid if it is put into alcohol or water-containing organic matter. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Copper Sulphate is easily dissolved in water and forms a blue solution. This was because the copper ions (Cu2) in copper sulfuric acid and water formed copper ions, which made the solution appear blue. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>