Rewriting the junior high reaction into an ion equation generally followed the following steps: ###1. Write the chemical equation First of all, he had to write down the chemical equation of the reaction. This was the foundation. If the chemical equation was written wrong, the subsequent steps would be wrong. ###2. Dismantle the chemical formula 1. ** Dismountable material ** - Strong acid, strong base, and dissolved salt could be written in the form of ions. - Strong acid generally included sulfuric acid, hydrogen acid, hydrogen iodate, peroric acid, etc. in water solutions. - Strong bases such as lithium, lithium, and lithium were in the water solution or molten state (the middle school stage focused on the water solution). - Most of the salt could be disassembled in an water solution or molten state (the emphasis in junior high school was on water solution), such as the common salt, such as the common salt such as salt and salt. 2. ** Non-dismantled substance ** - A simple substance couldn't be dismantled because a simple substance wasn't made of ions. - Solids (such as poorly dissolved solid such as calcium dioxide) could not be dismantled. They mainly existed in solid form in the solution, not in the form of ions. - Oxides could not be dismantled, such as copper dioxide, iron dioxide, etc. They did not participate in the reaction in the form of ions. - The volatile substances (such as carbon dioxide gas, etc.) could not be dismantled. They were not in the form of ions. - Weak ions (weak acid, weak base, and water) could not be dismantled. For example, vinegar was a weak acid and existed in the form of molecules in the solution. - The hard to dissolve substances (precipitations) could not be dismantled, such as the precipitations of the sulfuric acid. - The non-eletrolyte could not be dismantled. The non-eletrolyte was not ionised in the solution, such as alcohol. - The weak acidic radical generally could not be dismantled (except for the HSO4-bisulfuric acid radical in the solution state, which could be completely dismantled in some cases). ###3. Remove the same ions He deleted the same ions on both sides of the equation and simplified the equation. ###4. Check the equation 1. It was to check if the reaction was true. 2. To check if the elements were conservative, the number of atoms of the same element on both sides of the equation had to be equal. 3. Check the conservation of charge. The total amount of charge on both sides of the equation must be equal.(The conservation of lost and gained electrons must also be paid attention to in the oxido-reduction reaction, but it is relatively easy to rewrite the ion equation in the middle school oxido-reduction reaction.) 4. Check if the ion symbol is correct. Read more exciting novels for free
The chemical equation of the reaction between $NaHSO3 $and $NaOx $is: $NaHSO3 + NaOx = Na2SO3 + H2O $. Rewriting it into an ion equation,$NaHSO3 $is an acid salt of a weak acid, which can be dissociated into $Na^+$and $HSO3 ^-$in solution.$NaH $is a strong base, which can be completely dissociated into $Na^+$and $Oh^-$in solution. After the reaction,$Na2SO3 $is a strong solute, which can be completely dissociated into $Na^+$and $SO3 ^{2 - }$. The ion equation is: $HSO3 ^-+ SH ^- = SO3 ^{2 - }+ H2O $. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Under acidic conditions, manganate (Mn O42-) will react with hydrogen dioxide (H2O2). The ion equation is: Mn O42- +2H2O2 + 4H + = Mn2+ +4H2O +2O2. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between Na2SO4 and ClCl2 is Na2SO4 + Cl2 = NaHSO4 + Cl2. Because the HSO4 ^-in water was partially ionised, after adding a strong acid such as sulfuric acid, the reaction formed a weaker acidic HSO4 ^-ion. The ion equation for this reaction is: <i>(SO4 ^{2 - }+H^+ = HSO4 ^-<i>). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
硼砂中的\(Na_{2}B_{4}O_{7}\)在酸溶液中反应的离子方程式为:\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。其书写思路如下: 1. 首先确定反应物和生成物,硼砂\(Na_{2}B_{4}O_{7}\)与酸反应生成硼酸\(H_{3}BO_{3}\)。 2. 然后根据物质的组成写出其离子形式,\(Na_{2}B_{4}O_{7}\)可拆分为\(B_{4}O_{7}^{2 -}\),酸中的氢离子\(H^{+}\)参与反应,反应后生成\(H_{3}BO_{3}\)(硼酸为弱酸,在离子方程式中写分子式)。 3. 根据电荷守恒和原子守恒配平离子方程式,得到\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The ion equation of the reaction between the reagent and the acid would vary depending on the type of acid. Using sulfuric acid as an example: Borax will react with water: $Na2B4O7 + 7H2O = 2Na^+++4H3BO3 + 20H ^ -$. When it reacted with sulfuric acid,$Oh^ -$would react with $H^+$, and the total ion equation was: $B4O7 ^{2 -}+2H ^+++5H2O = 4H3BO3 $. Borax reacted with acid to form Boric acid ($H3BO3 $). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The ion equation is: $2Fe^{2 + } + H_{2}O_{2} + 2H^{+}=2Fe^{3 + } +2HO $. Reaction phenomenon: The solution turns from light green to yellow (because the iron ions are light green, the iron ions generated after the reaction are yellow). There may be a deposit during the reaction (when there are other ions in the solution that can form a deposit with the iron ions). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
For the reaction between sulfur and metal, the following are the common reactions and situations: - Sulfur and iron reaction: The chemical equation is: FeS + S = (heating)FeS. This reaction does not involve free moving ions, so it cannot be rewritten as an ion equation. The phenomenon was the formation of black solid iron Sulphide. - Sulfur and copper reaction: The chemical equation is 2Cu + S = (heating) Cu2 S. Similarly, the ion equation cannot be written. The phenomenon was the formation of black cuprous sulfur solid. - Sulfur and Na reaction: The chemical equation is 2Na + S =(grinding)Na <2> S. There is no need to rewrite the ion equation. The phenomenon was that during the grinding process, a violent reaction formed a white solid of sulfur dioxide. - Sulfur and aluminum reaction: The chemical equation is 3S +2AI = Al2S, which cannot be rewritten as an ion equation. The reaction phenomenon was the formation of aluminum sulfur solid. - Sulfur and mercury reaction: The chemical equation is as follows: Mercury + S = HgS, which cannot be written as an ion equation. The reaction phenomenon is the formation of black mercury sulfur solid. In general, since most of these reactions were solid-state reactions or did not carry out the ionisation process in the solution system, there was basically no ion equation. Most of the reaction phenomena were the formation of the corresponding sulfur solid, and the color of the solid was different. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between Cl2 and Ox had different ion equations depending on the reaction conditions. - When Cl2 reacted with a cold, diluted solution of soda, the ion equation of the reaction was: [Cl2 + 20H ^- = Cl2 ^-+ ClO^-+ H2O]. - When Cl2 reacted with hot, concentrated solution of NaOx, the ion equation of the reaction was: [3Cl2 + 60H ^- = 5Cl2 ^-+ ClO3 ^-+3H2O]. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The hydrogen ions (H) do not react with carbon dioxide (CO2). When carbon dioxide is dissolved in water, it will form carbolic acid (H Chi CO). Carbonic acid is a weak dibasic acid, and its equation is H Chi CO H + HCO, HCOH + CO2. It can produce hydrogen ions, so it will not react with hydrogen ions. If it can react with hydrogen ions, then its equation will not work. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between sulfur dioxide (<anno data-annotation-id ="00000000 - 4110 - 4000 - 4010-a150-a11001110000"> SO2 </anno>) and iron (<anno data-annotation-id ="0000000 - 4000 - 4000 - 4000-a1500000000">^{3 +}</anno>) is </anno></anno>(SO2 + 2H2O +2Fe3 += 2Fe2 ^{2 +}+ SO4 ^{2-}+4H2 +. In this reaction, Fe3 + is oxidisable, and SO2 is oxidisable. The two will undergo an oxido-reduction reaction. Fe3 + will be reduced to Fe2 +, and SO2 will be oxidisable to SO4-. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>