Biology textbook compulsory 1
The compulsory content of the biology textbook includes walking into the cell (Cell is the basic unit of life activity, the variety and unity of cells), the molecules that make up cells (Elements and compounds in cells, minerals in cells, sugar and fat in cells, and protein are the main bearers of life activities, and nuclei are carriers of genetic information), the basic structure of cells (the structure and function of the cell membrane, the division of labor and cooperation between the cell organs, the structure and function of the cell nucleus), the input and output of substances in the cell (passive transport, active transport, engulfing, and exomitting), the energy supply and utilization of the cell (the activation energy of the chemical reaction of the reaction of the reaction of These knowledge sections elaborated on all aspects of cell-related knowledge, from the basic composition of cells to the various physiological activities and life processes of cells. Read more exciting novels for free
The compulsory education textbook, the "54 system" and the "70 biology"
The following is a summary of the content related to biology in the first volume of the 7th grade of the 54 system. There was the Luke edition of the 7th grade biology electronic textbook (May 4th academic system). You could log in to the account on the National Primary and Secondary School Wisdom Education Platform website (<anno data-annotation-id ="2f4a778 - 4440 - 4256 - 4480 - 888888889998"></anno></anno>, select "Junior High School (5th and 4th academic system)","Biology" as the subject,"Luke edition" as the version, and "7th grade" as the grade. The first volume of the biology textbook of the Luke edition (May 4th school system) contained the fourth unit, the people in the biosphere. There were the first chapter of the origin of human beings, the second chapter of human nutrition, the third chapter of human breathing, the fourth chapter of the transportation of substances in the human body, and the fifth chapter of the discharge of waste in the human body. There was also information about the May 4th system, Lu Education Version, Biology Seventh Grade, and the review of the knowledge points, the mind map, and the Jinan Version, the seventh grade biology volume,"Living environment of living things." In addition, there were some general learning methods for biology in junior high school, such as understanding concepts, memorizing keywords, learning examples, understanding diagrams, conducting experiments, doing exercises, finding relationships, establishing relationship diagrams, teaching others, and constantly reviewing. These methods were also helpful for the study of biology knowledge in the first volume of the 54 system. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The answer to the compulsory textbook of biology in senior high school
The following are the answers to some of the questions in the Jiangsu version of the high school biology compulsory textbook: Chapter 1: The molecular composition of cells The Elements and Inorganic Compound in the Cell - ** Speculation Questions ** - Among the chemical elements that made up living things, C, H, O, and N were the most abundant. - Free water was a good solution for many ions, not bound water. - If muscle weakness occurs, the substance that may be lacking is calcium. - ** Usage Questions ** - The trace elements were iron, mn, zn, copper, b, al, co, and se. - The carbon exists in the form of carbon dioxide, oxygen in the form of water, hydrogen in the form of water, calcium in the form of carbon dioxide, phosphorus in the form of dipotassium hydrogen orthhosphate, and potassium in the form of kci. They are involved in the composition of substances in the body; Na ions maintain the stability of the osmonic pressure of the extra-cellular fluid; K ions participate in the activation of more than 60 kinds of membranes during plant growth and development; Ferrous ions are the components of many membranes; and Magnesium ions are an important component of the phylls. - Legume plants such as alfalfas and soybeans had a nitrogen fixing bacteria at the roots, which could help them survive the winter. - Free water was a good solute. The ions and molecules needed for cell life could be dissolved in it and flow with the water to participate in the reaction. Metabolic waste could also be discharged from the body through water. ** Section Two: Carboids and Lipids in the Cell ** - ** Speculation Questions ** - Glycogen and glucose were the main energy substances, fat was an important energy storage substance, and Cellulose was a plant cell structure substance that could not be used as an energy substance. - Lipids were divided into fats, lysomes, and steroids, but lysomes did not belong to steroids. - It was not advisable to reduce overweight weight only by reducing the intake of sugar and fatty foods. It was also necessary to combine it with moderate physical exercise. - ** Usage Questions ** - Plant cells contained starch and starch, and the process of making syrup was similar to the biological method. - The second biological method was used to utilize the raw material of the Cellulosic. - Celluloses and other glycans were important structural substances in plant cells, while glucose was the main energy source for life activities. - Ferlin's reagent could only identify reducing sugar. Sweet potatoes mainly contained non-reducing sugar such as starch, so it could not be used to identify them. However, Sultan III staining solution could be used to detect the fat in sweet potatoes. ** Section Three: The Nucleic Acid and Nucleic Acid in the Cell ** - ** Speculation Questions ** - Nucleic acid in the human body was composed of eight kinds of nuclei (adenine deoxy, guanine deoxy, cystine deoxy, thymine deoxy, adenine Ribo, guanine Ribo, cystine Ribo, and uracil Ribo). Uridine Ribo was composed of uracil, Ribo, and Phosphoryl. - The seeds of wheat, sorghums, and other plants are rich in starch, while animals such as cattle and sheep are rich in protein and fat. - ** Usage Questions ** - In contrast to the "food pyramid", if you eat too much dessert and meat, you may be obese, and if you eat too little vegetables and fruits, you may lack vitamins. - Mung beans may contain more starch; it is not possible to judge whether they are nutritious based on the content of protein; the cell composition of beans cannot be separated from protein. Cell structure and life activities (Part) - In the content related to organic matter in cells, there were various statements: - Not all kinds of sugar could be used as a plant energy material. Ribose and deoxy sugar formed the genetic material, and the plant cell wall made of Cellulose could not be used as an energy material. Therefore, it was wrong to say that all kinds of sugar could be used as a plant energy material. - The basic framework of the cell membrane was composed of a double-layer consisting of lysomes. Choline was an important component of animal cell membranes and was involved in the transport of fats in the blood. Therefore, it was correct to say that both lysomes and Choline were components of animal cell membranes. - The main reason for protein degeneration was the destruction of the spatial structure rather than the cleavage of the bond. Deoxy acids were connected to each other by the bond of the ester. Therefore, it was wrong to say that the high temperature degeneration of the protein was due to the cleavage of the bond, and the single chain was formed by the bond of the deoxy acids. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
A textbook of marine biology
Here are some textbooks on marine biology: - "Marine Biology" was published by Suzhou University Press. - The first edition of "Teaching Materials of Marine Biology" was published by Peking University Press on January 1, 2011. The foreign title was "Marine Biology".(Six Edition)", 488 pages in paperback, the text language was simplified Chinese, the size was 16, the isbns were 9787301160138, 7301160135, the bar code was 9787301160138, the product size was 28.2 x 20.2 x 2.6 cm, the product weight was 862 g, and the ASIN was B004 REF 63G. The book told the story of the ocean over hundreds of millions of years in easy-to-understand language. It described the underwater world decorated with corals, sea anthems, and caverns. It also described the characteristics and gifts of the ocean, emphasizing the need to cherish and protect the ocean. - An early textbook of marine biology, The Depths of the Sea, written by Sir Charles Wavell Thompson in 1877. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
New textbook, high school English compulsory textbook, listening notes
If you were to take notes from the listening comprehension of the new high school English textbook published by the People's Education Press, you could refer to the following methods: - ** vocabulary preparation **: Learn vocabulary before listening and remove vocabulary barriers in listening. This part of the vocabulary can be sorted out and recorded separately. It is clear about the pronunciation and meaning of the words, which is helpful for listening comprehension. - ** Listening to the Listening test questions **: When listening to the listening materials that contain the vocabulary of the teaching materials, record the key content related to the vocabulary of the teaching materials, such as some habitual collocations, special usages, etc. - ** Post-listening feedback segment **: In-depth study of the listening text, combining listening, reading, and dictation. Dictation of key sentences and hard-to-understand parts of the listening text could deepen the mastery of vocabulary, grammar, and other knowledge. At the same time, he took detailed notes on the grammar phenomena and key vocabulary usage in the listening text to build his own knowledge system. - ** Follow-up Reading Stage **: Follow the listening text, imitate the standard English pronunciation, and consolidate the vocabulary of the teaching material again. If there were words that were difficult to pronounce, or words that were linked or weak, they could also be recorded for review. Take Bubugao's study notes as an example, focus on the topic, stick to the goal, and explore the listening content independently; In the process of group discussion, presentation and communication, and solving doubts and correcting errors, the knowledge points and questions related to listening will be sorted into notes; In the training test, summary review, reflection and improvement stage, listening skills, common listening vocabulary and expressions can be summarized in the notes, so as to harmonize the teaching material knowledge and consolidate the foundation. In addition, he could also use the table note-taking method. He could write down phrases in the left column, example sentences in the middle column, and his own experience in the right column (including questions and conclusions about knowledge points) to make his notes more organized. For example, record the phrase "be different from" or the example sentence "My school is different from yours." The notes could be written about questions about the usage of the phrase or a summary of its usage in listening. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
High school biology review compulsory 1
Biology compulsory two formulas and explanations
1. ** Base calculation for double-stranded DNA and messenger acid ** - **DNA single and double-strand pairing base relationship ** - In double-stranded DNA, the number of A (adenine) in one strand is equal to the number of T (thymine) in the other strand, namely,<A1=T2>,<T1 = A2>;; in the entire double-stranded DNA,<A=T>, and <A=T=A1 + A2=T1+T2>;; similarly,<C = G>,<C=G=C1 + C2=G1+G2>. Double-stranded DNA [A + C=G + T],[A+G=C + T], they are equal to half of the total number of double-stranded DNA bases, that is,[1/2] of [(A + G + C+T)], and [(A + G)],[(C + T)],[(A + C)], and [(G + T)] are all [50%], which shows that the total number of purine bases in double-stranded DNA is equal to the total number of prismatic bases. - ** Calculation of DNA Single and Double-Stranded Base Levels ** - In double-stranded DNA,<(A + T)> %+(C + G)> % = 1>. ((C+ G)< %>= 1-(A + T)< %>, at the same time <(C + G)< %>= 2C < %>=2G < %>,<(A + T)< %>= 1 - 2C < %>=1 - 2G < %>,<(A1+T1)< %>= 1-(C1 + G1)< %>,<(A2+T2)< %>= 1-(C2 + G2)< %>). - ** Relationship between the number of bases in a single strand of DNA ** - \(A1+T1+C1+G1=T2+A2+G2+C2), the sum of which is equal to the total number of double-stranded DNA bases (1/2);(A1+T1=A2+T2=A3 + U3)(Here,<<A3 + U3>> is the corresponding relationship between <<A1+T1>> and <<A2+T2>> when the DNA is transcribed into mR A), and it is equal to <(1/2> of <(A + T)>);<C1+G1=C2+G2=C3+G3>>, which is equal to <(1/2> of <(G + C)>). - ** The ratio of DNA single-strand and double-strand pairing bases ** - If <(A1+T1)/(C1+G1)=M>, then <(A2+T2)/(C2+G2)=M>,<(A + T)/(C + G)=M>, this ratio could represent the DNA molecular's specific property. - ** The ratio of the sum of single and double-stranded non-paired bases in DNA ** - If (A1+G1)/(C1+T1)=N, then (A2+G2)/(C2+T2)=1/N, and (A + G)/(C + T)=1; If (A1+C1)/(G1+T1)=N, then (A2+C2)/(G2+T2)=1/N, and (A + C)/(G + T)=1. - ** The relationship between the base content of two single-strands and double-strands ** - \(2A\%=2T\%=(A + T)\%=(A1+T1)\%=(A2+T2)\%=(A3+U3)\%=T1\%+T2\%=A1\%+A2\%\);\(2C\%=2G\%=(G + C)\%=(C1+G1)\%=(C2+G2)\%=(C3+G3)\%=C1\%+C2\%=G1\%+G2\%\)。 2. ** Calculating cell division, ontogeny, DNA, Chromatids, Chromatids, Homological Chroomes, and Quarters ** - ** Type of genetic information stored in DNA **: It is a type of DNA (4 ^n)(n is the base pair of DNA). - ** Cell division ** - The number of nuclei is equal to the number of kinetochore. The number of mitosis anaphase is [N], the number of somatic cells is [2N], minus the number of mitosis anaphase I is [2N], minus the number of mitosis anaphase II is [2N]. The number of sperm or egg cells or polar nuclei <br><br><br> The number of somatic cells <br> The number of fertilized eggs <br> The number of fertilized eggs An oogonia formed an egg cell and three polar bodies, and a sperm cell formed four sperm. If the DNA number of gametes (sperm or egg cells) is <M>, then the number of DNA in the body cell is <M>;;; the number of DNA in the gonogonia is <M>(= 2M>)(before DNA replication) or <4M>(after DNA replication); the number of DNA in the primary gonelle is <M>;;;; and the number of DNA in the secondary gonelle is <M>. When the number of DNA molecules in a single <br><br> 1, the number of chromatids is 0; when the number of DNA molecules in a single <br> 2, the number of chromatids is 2. The number of quadrants was equal to the number of pairs of homolog genes (syndesis and minus the middle stage I), and the number of quadrants after the middle stage I minus the late stage I was 0. - ** Ontogeny of the flowering plants ** - Embryo Cell Chromatic Number (2N = 1/3) Nucleus of the Polarity of Fertility (3N = 1/3') The number of embryos in the embryo cell is equal to the number of embryos in the fertilized egg, equal to the number of embryos in the sperm cell and the number of embryos in the egg cell (distant crossing). The number of embryos in the embryo cell is equal to the number of embryos in the fertilized polar nucleus, equal to the number of embryos in the sperm cell and the number of embryos in the egg cell and the number of embryos in the polar nucleus.<1> ovule (double fertilisation)<1> egg cell><+2> polar nucleus><+2> sperm><1> seed;<1> ovaries><1> fruit. 3. ** Calculation of protein and nuclei (Note: Number of Peptides (m); Total Number of Acid (n); Average Weight of Acid (a); Average Weight of Acid (b); Total Number of Nucleic Acid (c); Average Weight of Nucleic Acid (d))** - ** Genes (and Peptides)** - ** Calculation of the number of atoms of the different atoms of the ammo acid **: the number of atoms in the base of the [C] atom in the base of the [H] atom in the base of the [H] atom in the base of the [C] atom in the base of the [H] atom in the base of the [C] atom in the base of the [H] atom in - ** Each chain has at least **: each has 1 free amine and each has at least 1 free amine and each has at least m free amine and each has at least m free amine. - ** Number of Peptide Bond **: Number of Peptide Bond <>/>/>=<> Number of Dehydrating Water>/>=<<>=>=<=<=>=>=<=& - ** The protein is composed of [m] number of protein chains **:[N] number of atoms [=] number of peptidic bonds [+m] number of amino groups (end)[+R] number of amino groups [=] number of peptidic bonds [+] number of amino groups [+m] number of peptidic bonds [end];<<O>> Total number of atoms><=>> Total number of bond bonds><+2(m>)<<+R>><+ Carboxy groups><=><Total number of bond bonds><+2><Carboxy groups><<+2m>><Carboxy groups></> - ** protein molecular weight **: molecular weight of protein/(=/) total molecular weight of ammo acid-total molecular weight of dehydration (total atomic weight of dehydration)/(=na-18(n-m)/). - ** The calculation of the number of the number of the bases in the double-stranded DNA (gene), and the number of the bases in the messenger acid in the protein ** - The number of bases in the gene (at least): the number of bases in the gene (at least): the number of the protein's aa (=6:3:1); the number of peptidic bonds (number of water gain and loss); the number of peptidic chains; the number of aa; the number of bases in the gene; the number of bases in the gene; the number of bases in the gene. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology compulsory 1, which part is more difficult?
Biology compulsory 1 had the following difficulties: 1. Cell structure and function: - The distinction between procaryotic cells and eukaryotic cells involved the differences in the cell structure such as the nucleus (with or without the nuclear membrane as the boundary), the organelle, and so on. It was necessary to accurately remember the unique structure and functions of different cell types. For example, in procaryotic cells, fungi were the smallest and simplest cells without special structures such as cell walls. - The structure and function of the cell membrane, such as Irvington's conclusion that it was easier for lipid-based substances to pass through the cell membrane through experiments, and Robert's observation of the dark-light-dark three-layer structure of the cell membrane under the electron microscope and his speculation of its composition, as well as the role of the protein on the cell membrane, such as the protection, smoothness, and cell recognition functions of the protein on the surface of the respiratory and digestive tract, all involved a variety of experimental evidence and complex functional explanations. It was difficult to understand. - The functions of the organelle and the relationship between them, such as mitochondria was the main place for oxygen breathing, the plastids were the place for photosynthesis, the plastids were the workshop for protein synthesis and processing, and the Golgi apparatus processed and packaged the protein, etc., and they were interconnected through the synthesis and secretion of secreted protein. For example, the synthesis of secreted protein involved many organelle such as the Ribosome, the plastids, and the Golgi apparatus. These processes were more complicated and closely related. 2. Cell Theory: - There were three points in the cell theory proposed by Schwann and Slyden, including that the cell was an organism, all animals and plants were developed from cells and composed of cells and cell products, the cell was a relatively independent unit, which had its own life and played a role in the overall life, and the cell was a relatively independent unit. New cells were produced from old cells (Virshaw's supplementary cells produced new cells through division). This part required a deep understanding of the importance of cell theory in the development of biology and its fundamental role in modern biological research. 3. Biofilm System: - The membrane system consisted of cell membranes, organelle membranes, nuclear membranes, and other structures. It was difficult to understand its functional characteristics. For example, the decisive role of the cell membrane in the process of material transport, energy conversion, and information transmission. The chemical reaction on the membrane required the participation of the reagent. The wide membrane area provided the attachment site for the reagent. The membrane separated the organelle to ensure that various chemical reactions were carried out efficiently and orderly. 4. The material foundation of cells: - As the main bearer of life activities, the structural variety of the protein (different types, numbers, sequence, and spatial structure of the chain) determined the functional variety. To understand it, one needed a certain amount of spatial imagination and logical thinking ability. - The functions of sugar, fat, mineral salt, and water in cells, such as the important component of the cell membrane that was involved in the transport of fat, and the existence of water in the cell in the form of free water and bound water with different functions, needed to be accurately memorized. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology compulsory, a full set of recitation materials
Biology compulsory, mind map of cell life course
The following is the general framework of the cell life process mind map: ** 1. Cell reproduction ** 1. cell growth - Cell size increases - The efficiency of substance exchange would change with the growth of cells. The larger the volume, the smaller the relative surface area, and the lower the efficiency of substance exchange. This limited the unlimited growth of cells. 2. cell division - mitosis - Cell cycle: It includes interphase (G1 phase-preparatory work such as protein synthesis, S phase- DNA replication, G2 phase-further preparation) and division phase (prophase-appearance of the nuclei, formation of the spindles, etc.; Metaphase-arrangement of the nuclei on the equator; anaphase-division of the nuclei, separation of the sister chromatids into the nuclei and migration to the poles; telophase-disappearance of the nuclei and the nuclei, reappearance of the nuclear membrane and the nuclei, etc.). - [Meaning: Maintain the stability of the genetic material of the parent-child generation.] - Amitosis: There are no changes in the spindle-like fibers and the nuclei of the nuclei, just like the division of the frog's red blood cells. ** 2. Cell Division ** 1. [Concept: The process in which cells undergo changes in their form, structure, and function.] 2. characteristic - Durability: occurs throughout the life of an organism, but reaches its maximum during the embryonic stage. - [Stable: The differentiated cells will not return to their undifferentiated state.] 3. [Meaning: It can specialize the cells in multicellularized organisms and help improve the efficiency of various physiological functions.] ** 3. Cell aging ** 1. The characteristics of cell aging - The cell membrane's penetrability changed, and the material transport function decreased. - The water content in the cells decreased, the cells shrank, and their size became smaller. - The activity of many kinds of cellular zymes decreased. - Pigments in the cells would gradually accumulate as the cells aged. - The size of the nucleus increased, the nuclear membrane folded inward, the chromatin contracted, and the staining deepened. 2. The relationship between cell aging and individual aging: The cell aging of a single-celled organism is the aging of an individual; the cell aging of a multicellularized organism is not equal to the aging of an individual, but the aging process of an individual is also the aging process of the cells that make up an individual. ** 4. Cell Death ** 1. apoptosis - [Concept: The process of cells automatically ending their lives is a normal physiological phenomenon.] - [For example, the disappearance of the tail and the formation of fingers during the development of a human embryo.] - [Meaning: It plays a key role in the normal development of organisms, maintaining the stability of the internal environment, and resisting external interference.] 2. cell necrosis - [Concept: Under the influence of various adverse factors, cell damage and death caused by the damage or interruption of normal cell metabolism.] - [Characteristic: It is a passive, pathological death, such as tissue cell death caused by regional hemorrhage.] <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology high school compulsory information book recommendation
Here are some recommendations for high school biology textbooks: 1. "The new curriculum standard thoroughly explains the teaching materials for high school biology compulsory 1 (companion teaching edition)", which was helpful for the study of compulsory 1. 2. You can pay attention to the headline of "High School Biology Teaching and Learning" and obtain the "2022 College Entrance Examination Review 'Return to Teaching Materials to Win the College Entrance Examination' Series of Materials: Required One" according to the free method provided by it. It will help you review and prepare for the required one. 3. As for teaching assistants,"handwritten notes or a book" was also a good choice. It would help to further learn biological knowledge after mastering the content of the textbook. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>