In a neutral or weakly acidic solution, the reaction between thionate and iodinate would produce hypothionate and iodinate, with the reaction equation being 2Na2S2O3 +I2=== Na2S4O6 +2NaI, and there would be no gas formation. In a basic solution, the reaction equation was Na2S2O3 + 4I2 + 10NaOx ==== 2Na2SO4 + 8NaI +5H2O, and there would be no gas formation. If Na2SO3 is added and boiled, the reaction equation is Na2S2O3 + Na2SO3 +I2=== Na2S2O6 +2NaI, and there is also no gas formation. Therefore, the reaction between thiothiosulfuric acid radical and iodines did not produce gas. Read more exciting novels for free
Usually, they would not react with each other. They could coexist in water solutions. For example, in a solution of sulfuric acid, there were both sulfuric acid ions and sulfuric acid ions. However, in different environments, their existence and interaction would be different. In an acidic environment, the radical ions would combine with hydrogen ions to form water. In an acidic environment, both radical ions and sulfuric acid ions would exist, but the radical ions would be replaced by hydrogen ions in the base to form water. In an electrochemistry reaction, the reduction potential of the hydrogen ions was higher than that of the sulfuric acid ions. Therefore, the hydrogen ions would first accept electrons and be reduced to water molecules, while the sulfuric acid ions would be discharged later. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between hydrogen sulfurous acid and sulfurous acid produced elemental sulfur and water. The reaction did not produce gas. The reaction equation is: H <2> SO2 <2>+2H <2> S = 3S <2>+3H <2> O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the two will produce a gas called hydrogen iodinate (Hi). In this reaction, the hydrogen dioxide in the carbon dioxide had a hydrogen radical (-SH), which could undergo an oxidoreduction reaction with the hydrogen dioxide. In this reaction, the hydrogen dioxide gas would be produced. However, the specific reaction may also be affected by the reaction conditions (such as temperature, solution, etc.). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between copper dioxide and diluted sulfuric acid produced copper dioxide and water. The reaction equation was CuO + H2SO4 = CuSO4 + H2O. No gas was produced during this reaction, and no gas was produced when heated. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Iron and sulfuric acid react to form iron sulfuric acid (FeSO2) and hydrogen gas (H <2>) instead of iron sulfuric acid. The reaction equation is: Fe2 + H2 SO2 → Fe2 SO2 + H2. During the reaction, the iron surface was corroded by hydrogen ions (H) in sulfuric acid, forming hydrogen gas (H) and iron ions (Fe2). The iron ions combined with the sulfuric acid ions (SO2) to form FeSO2. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Iron reacted with diluted sulfuric acid to form hydrogen. Iron and concentrated sulfuric acid did not react at room temperature because concentrated sulfuric acid had strong oxidisation. The surface of the iron would form a dense oxide-film, which would be deactivated. However, when heated, the reaction would produce sulfur dioxide gas, and hydrogen gas would be produced when the reaction was almost over. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The hydrogen ions in the sulfuric acid will react with the hydrogen ions in the water. The reaction equation is: HQ + H ^O = H O + Cl. This reaction can be carried out at room temperature without heating. In water, sulfuric acid will produce hydrogen ions (H), which will combine with the hydrogen ions (H O) produced by water's self-ionisation to form hydrogen ions (H). This reaction was based on the principle of neutralizing acid and base. As an acid, it could provide hydrogen ions in water and interact with the hydrogen ions in water. It was a spontaneous reaction that usually did not require additional heating to promote. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
During the reaction between the two, the solution may appear dark purple or dark blue at first due to the presence of the iodine-based reagent.(In the presence of the starch indicator, the iodine-based reagent will make the starch appear dark blue.) As the reaction progressed, the color of the solution gradually changed. When the reaction approached the end point, if there was a starch indicator, the solution would turn from blue to light yellow, and finally the blue color would disappear. After the reaction was complete, the solution would be colorless. This was because the reaction of the iodine-like reagent with the sulfuric acid would gradually consume the iodine-like reagent, causing the color of the solution to change as described above. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
It reacted with the hydrogen radical in the water. This was because sulfuric acid was a strong acid. In water, it would completely vaporize hydrogen ions (H) and chloride-ions (Cl). The vaporized hydrogen ions would combine with the hydrogen ions in the water to form water (H O). From the essence of the reaction, it was an acid and base neutralizing reaction, and the ion equation of the reaction was H + oh2 = H O. This reaction caused the concentration of hydrogen ions and hydrogen ions in the solution to change. After the hydrogen ions and hydrogen ions combined to form water, the concentration of the two in the solution would decrease, and the ph of the solution would also change. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When the copper sulfuric acid solution reacted with diluted sulfuric acid, it would form copper ions such as copper chloride2. In the solution, copper ions (Cu2) and Cl2 (Cl2) combine to form copper ions. During the reaction process, there are also various ion forms such as copper ions. Moreover, with the different amount and concentration of Cl-ions, the color of the solution would change due to the combined influence of the yellow copper ions and the blue copper ions. For example, the solution might turn green. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>