2011 National Biology League answers and answers
Here are some of the answers to the 2011 National Biology League questions: 1. The organelle without a photon pump was the ER (Option A). 2. The mobility of a biological membrane was manifested by the fact that both membrane lipidsand membrane protein were mobile (Option A). 3. Transmembrane transport of Na and K, as well as co-transport, belonged to active transport (options A and C). 4. The main component of the Spindle formed during cell division is the microtubulus (Option C). 5. The description of the cell membrane breaking rapidly in the description of cell death is incorrect (Option D). 6. Both the plastids and the mitochondria contained protein, both contained H+-binding cozymes, and both produced ATPs (options A, B, and E). 7. The main function of the nucleus was the biogeneration of the Ribosome (Option B). 8. The best time to observe the quadrants of the same species during Meiosis was the pachyphakinete stage (Option C). 9. The base sequence of the template DNA was 5'-TGACCG-3', and the base sequence of the transcribed DNA was 5'-ACGUA-3'(Option B). Read more exciting novels for free
The National College Entrance Examination, a volume of biology papers, 2021 answers
1. Multiple choice questions: 1. D。This was an error because the mitochondria's DNA was located in the mitochondria's matrix and not on the outer membrane, and it was responsible for the metabolism of the bacteria. 2. B。There are also Dna-protein compounds in the karyomimetics of prokaryotic cells, such as during DNA replication and replication, so this is an error. 3. A。The wheat could not directly absorb and utilize the N <2> in the soil. This was an error. 4. C。It can be seen from the change trend of the number of cells in the picture that the cell reproduction of Group B is accelerated after adding drug X. In Group C, drug X is added first to promote the cell reproduction, and then drug D is added to suppress the effect of drug X, slowing down the cell reproduction trend. If drug X is a protein, drug D may change its spatial structure and thus suppress its function. However, in Group C, drug D is added first to suppress the cell reproduction, and then drug X is added. This does not match the performance in the picture. This item is unreasonable. 5. (Because the document does not fully display the answer content of this part, the answer content of question 5 cannot be accurately provided. Please refer to the complete 2021 college entrance examination biology volume 1 answer document to obtain the accurate answer). (As the document does not fully display part of the content of the non-multiple-choice questions, it is impossible to accurately provide the answers to the non-multiple-choice questions. Please refer to the complete 2021 National College Entrance Examination Biology Volume 1 answer document to obtain the accurate answers.) <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Help me out. Who has the answers to the 2017 biology answers book?
I'm a fan of online literature, and I can't get or provide information about the 2017 biology answers. Biology was an important subject. The biology exam was also one of the important exams. I suggest that you look for answers through other channels, such as consulting teachers or classmates, or referring to relevant high school entrance examination materials and guidance materials. Good luck!
The answers to the biology analysis questions of the third year of high school in 2023 and the answers
The following are some of the answers and analysis of the biology test questions of the first mock exam of the third year of high school in 2023 in Shandong Province: 1. Single choice questions 1. Answer: B. - Analysis: During the synthesis of cell membrane shaping protein, the location is provided by the Ribosome, and the power is provided by the mitochondria.(The main energy supplier in the cell, the plastids are mainly found in plant cells and are mainly related to photosynthesis, not involved here), A is wrong; the "molecular garbage bag" is a vesicle, mainly composed of lysomes and protein, B is correct; the "recycling factory" may be a lysoma, and the "component" may be an amine acid.(Because it is a product of protein decomposition, not a primer), C error; The organelle that can form vesicles in human cells includes the plasmatic reticule and the Golgi apparatus, but the centric body cannot form vesicles, D error. 2. Answer: A. - Analysis: The V-disorderly transport of H+ from the cellular matrix into the vesicle was a process that consumed ATP. It was an active transport, not an auxiliary spread. A was wrong. Inhibition of the activity of Cys transporter on the tonoelle would affect the process illustrated in the diagram, resulting in abnormal function of the mitochondria. B was correct. Cys entered the vesicle against the concentration slope by using the potential energy of H+. It was an active transport. C was correct. The process illustrated in the diagram indicated that there was a connection between the vesicle and the mitochondria. There was both division of labor and cooperation. D was correct. 3. Answer: D. - Analysis: The cells in the root meristematic zone of onions had no fat, so orange granules could not be observed with Sultan III staining. A was wrong; The cells in the root meristematic zone of onions became square and tightly arranged after being dissociated, rinsed, stained, and made into slices. B was wrong; The widest color of the green tube-shaped leaf on the filter paper was the cyanophile a (blue-green), C was wrong; The color of the purple onion scale leaf was cyanophile, which could not be extracted with absolute alcohol (absolute alcohol was used to extract the color in the plastids). D was correct. 4. (As the question did not give all the questions about this question, the answer and analysis could not be given accurately.) 2. Multiple-choice questions (As the questions did not give all the questions in this part, all the answers and analysis could not be given accurately) Third, non-multiple choice questions 21. - (1) Answer: Light intensity and CO2 concentration;Gs. - Analysis: According to the experimental content, the influencing factors are light intensity and CO2 concentration, and Gs is the relevant measurement index. - (2) Answer: Shade. Compared with natural light, the stomatal conductivity of leaves under shade increased slowly, and the Ci value decreased very little in the initial stage after light. - [Analysis: Obtain the relevant characteristics under the shade condition from the comparison of experimental data.] - (3) Answer: [H] and ATP-produced by light reaction increased, and dark reaction strengthened, but stomatal conductivity was lower, and intercellular CO2 concentration decreased. As stomatal conductivity increased, intercellular CO2 concentration gradually increased. - Analysis: This phenomenon was explained by the relationship between light and dark reactions and the effect of stomatal conductivity on intercellular CO2 concentration. 22. - (1) Answer: Genetic mutation; a trait can be affected by multiple genes. - [Analysis: Genetic changes may be caused by genetic mutation. From the content of the question, it can be analyzed that one trait is related to multiple genes.] - (2) Answer: 3. - (The analysis needs to be based on the complete information related to the genes and traits of the fruit fly. Due to partial missing, it is impossible to give details.) - (3) Answer: In mutant 1, choose the double-balanced lethal line fruit fly to cross with the wild type non-lethal line fruit fly, and let the male and female fruit flies in F1 mate freely. If F2 wild type: mutant = 6:1, then the mutant gene is located on the 2nd; if F2 wild type: mutant =3:1, then the mutant gene is located on other genes. - [Analysis: Through crossbreeding experiments, according to the inheritance law of the genes on different microorganisms, the corresponding proportion of offspring is obtained to determine the genetics of the genes.] - (4) Answer: 4, 2/3. - (The analysis needs to be based on the complete information related to the genes and traits of the fruit fly. Due to partial missing, it is impossible to give details.) 23. - (1) Answer: Assist in spreading;Na+ channel is open, Na+ flows in; cerebral hemisphere; efferent nerve endings and the diaphragm and abdominal muscles they inhabit. - [Analysis: According to the characteristics of the material transport method, it is determined to assist in the spread. The nerve center of the vomiting reflex is in the cerebral hemisphere, and the relevant muscles are indominated by the efferent nerve endings.] - (2) Answer: Choose healthy mice with the same physiological state and divide them into two groups, A and B. Group A used chemical genetics to specifically suppress M neurons, while Group B was used as a control. Stimulate the two groups of mice with toxins and observe the vomiting behavior of the mice. Inhibition of Ca2 + channel activity, reduction of Ca2 + influx, inhibition of the expression of the Tachkinin gene in the M-type neurons. - Analysis: Investigate the role of M neurons in vomiting behavior by setting up a control experiment. From the perspective of affecting the physiological process of the neurons, propose measures to suppress the relevant channels and gene expression. 24. - (1) Answer: Species composition; dominant species in the community. - [Analysis: This is a concept related to community. Species composition and dominant species are important aspects of community research.] - (2) Answer: Yunnan pine forest. The survival rate and mortality rate of Pseudotacia glazei in the Yunnan pine forest community reached a balance at a lower age class. - [Analysis: According to the relevant data of Yunnan pine forest in the map, the survival characteristics of Lancang yellow cedar can be obtained.] - (3) Answer: No. The data above does not show the proportion of individuals of different ages in the population. - [Analysis: According to the knowledge of the age structure of the population, the data in the picture cannot reflect the age structure.] - (4) Answer: The young individuals of the population of Pseudotacia glazei in Fig. 2 and Fig. 3 compete more fiercely with other species for survival resources and space. - [Analysis: Obtain the competition status of young individuals from the comparison of the data in the map.] 25. - (1) Answer: Denature the protein and separate it from the DNA; separate the DNA from the protein. - [Analysis: In related experimental operations, the purpose of this operation is to deal with the relationship between protein and DNA.] - (2) Answer: B. The primer is too short and has a weak specialty. The two primer will complement each other. - Analysis: Explain the reason for choosing B according to the characteristics of the primer and the requirements in the experiment. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Techniques in structural biology: topics and answers
The subject of structural biology was based on molecular biology, biochemistry, and biochemistry. Its research targets were biological molecules, such as protein and nuclear acid. The following is a summary of some common structural biology techniques: * * I. X-ray Crystallography ** 1. * * History ** - In 1895, Roentgen discovered X-rays, and in 1912, Laue and others used X-rays to perform a refraction experiment on copper sulfuric acid crystals and discovered X-ray crystal refraction. Then, he repeated this experiment and derived the Bragg equation, marking the birth of X-ray crystallology. In 1957, X-ray Crystallography was used to analyze the structure of the first biological macro molecular, sperm whale myobin. 2. * * Technique Principle ** - By X-ray illumination of the crystals of the biological molecules, the structure of the biological molecules was analyzed according to the X-ray refraction pattern. 3. * * Strengths and Limitations ** - [Strengths: Able to achieve very high resolution, close to the atomic level; No restrictions on the size and composition of the protein, whether it is a multi-unit complex with a large molecular weight or a small molecular weight.] - [Limitations: High-quality, large-sized crystals are required. For objects with large molecular weight or flexible structures, it is often difficult to obtain high-quality crystals.] * * 2. Cryo-electron microscope (cryo-EM) is based on single-particle analysis technology ** 1. * * History ** - In 1939, the world's first commercial electron microscope was manufactured. In the early days, in order to prevent damage to the sample due to high vacuum and intense electron bombardment, heavy metal dyeing or sugar embedding methods were used to process the sample, but the resolution was limited. In 1984, J. Dubochet and others developed a method to freeze biological samples, opening the era of "frozen" electron microscopes. 2. * * Technique Principle ** - The solution sample of the biological molecules was quickly put into liquid ether cooled to liquid nitrogen temperature to obtain a frozen sample with a suitable thickness of the ice layer. Then, thousands of photos were taken of the biological molecules evenly distributed in the ice layer. The two-dimensional photos were analyzed by an algorithm to finally obtain its structure. 3. * * Strengths and Limitations ** - [Strengths: It is of great significance to the study of the structure of biological molecules, especially for some biological molecules that are difficult to crystalize.] - [Limitations: Freezing sample preparation and image processing are still challenging, and data processing is complicated.] * * 3. Nuclear Magnetic Resonance (MRI)** 1. * * Technique Principle ** - It was mainly aimed at samples with a small molecular weight (about 20 kDa) in solution. It used the magnetic resonance phenomenon of the atomic nucleus to analyze the structure of biological molecules. 2. * * Strengths and Limitations ** - [Strengths: It can be used to study biological molecules in solutions, and can provide dynamic structural information of biological molecules in solutions.] - [Limitations: Mainly targeted at samples with small molecular weight, rarely used in recent years.] * * 4. Microcrystallite Electronic Diffraction (MicroED) 1. * * Technique Principle ** - It was a technique that used a electron microscope to analyze the structure of tiny crystals. Since the interaction between an electron beam and matter was much stronger than that of X-rays, it could analyze the structure of nanocrystals that were difficult to deal with in X-ray crystallogy. 2. * * Strengths and Limitations ** - Strengths: It provides a new structural analysis method for protein samples that were difficult to cultivate single crystals in the past, making up for the shortcomings of existing technologies. It was named one of the top ten breakthrough technologies in 2018 by Science magazine. - Limitations: As a relatively new technology, there may be some problems in terms of technology penetration and application optimization. * * 5. Artificial Intelligence (AI) in structural biology ** 1. * * Technique Principle ** - For example, in the field of protein structure prediction, the 3D structure of a protein was predicted from the sequence of the protein by using deep learning technology. In the field of drug research and development, it can be used to predict the biological activity of drugs and the binding mode with the target. 2. * * Strengths and Limitations ** - Strengths: It has a high accuracy in predicting protein structures. For example, the predicted MMSD value of the AlpaFold system is less than 2A, indicating that the predicted structure is very close to the experimental results. In the field of drug development, he successfully predicted the biological activity of many drugs and their binding mode with the target. - Limitations: There are limitations such as data quality and annotation problems, and the explainability of the algorithm. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Ten biology experiment questions with answers
Below are the answers to the ten biology experiment questions: ** 1. Experiment related to making onion scales and leaf cuticular cells into temporary slices ** 1. ** Title * There were several steps to make the onion scale leaf skin cells into temporary films: 1. Dripping water; 2. Taking materials; 3. Covering the cover glass; 4. Dyeing; 5. Flatting with tweezers. Please write down the correct sequence of operation and explain what liquid was used for dripping water and dyeing. ** Answer ** The correct order was: 1. Drip water, 2. Take samples, 5. flatten with tweezers, 3. Cover the glass, 4. Stain. The dripping of water was to maintain the normal shape of the cells, and the liquid used for dyeing was an iodine-based solution. The iodine-based solution could dye the nucleus and other structures with color for easy observation. 2. ** Title * What was the correct way to cover the cover glass when making the onion scale leaf skin cells? If air bubbles appeared under the cover glass, what effect would it have on the observation? ** Answer ** The correct way to cover the cover glass was to use tweezers to pick up the cover glass, so that one side of it first touched the drop on the slide, and then slowly lay it flat. If air bubbles appeared under the cover glass, the air bubbles would interfere with the observation of the cell structure. Because the air bubbles looked like black circles under the microscope, they might be mistaken for cell structures. 3. ** Title * When he was making the onion scale leaf skin cells, if there were overlapping cells in his field of vision, which step might have been handled incorrectly? ** Answer ** If the cells in the field of vision overlapped, it might be due to the improper operation of flattening the onion scales with tweezers after the sample was taken. 4. ** Title * When observing the onion scale leaf cuticular cells under the microscope, it was found that the field of vision was relatively dark. How to adjust the microscope to make the field of vision brighter? ** Answer ** You can adjust the shutter to choose a larger aperture, or adjust the mirror to use a concave mirror. Both methods could increase the amount of light entering the microscope, thus brightening the field of view. ** 2. Experiment on cell structure and function ** 5. ** Title * In the experiment to observe the cell structure, how to distinguish between plant cells and animal cells? (Write at least three points) ** Answer ** (1) Plant cells have cell walls, but animal cells do not. (2) Plant cells have plastids (green cells), but animal cells do not have plastids. (3) Plant cells have large vesicles, but animal cells generally do not have large vesicles (some lower animal cells have small vesicles, but they are different from plant cells). 6. ** Title * In the experiment to explore the cell is the basic unit of biological structure and function, some examples of different biological cells with different forms and functions were given. ** Answer ** For example, onion skin cells were flat and tightly arranged, mainly for protection. Red blood cells in human blood were spherical, with thick edges and slightly concave in the middle. They had no nucleus, and their main function was to transport oxygen and carbon dioxide. Human nerve cells were divided into two parts, the cell body and the projections. The cell body was hexagonal, and the projections were intertwined like tree roots. Their main function was to receive and transmit information. ** 3. Exploring the environmental factors that affect the survival of living things ** 7. ** Title * Design an experiment to explore the effect of temperature on the life of the rat woman. (Write down the experimental steps, variables, and expected results) ** Answer ** Experimental steps: (1) Prepare a paper box and lay a layer of wet soil inside. (2) Divide the paper box into two parts. One side is shielded with black cloth to form a dark environment, and the other side is not shielded. (3) Put the same number of rat women (such as 10) on both sides of the carton. (4) Place the carton in an environment with different temperatures, such as 10 ° C on one side and 25 ° C on the other side. The variable was temperature. Anticipated result: In an environment with a suitable temperature (e.g. 25 ° C), the activity of the rat wives is more frequent and the number is more; in an environment with a low temperature (e.g. 10 ° C), the activity of the rat wives is less and the number may be reduced. 8. ** Title * What were the experimental variables in an experiment to explore the effect of light on the sprouting of a plant seed? If he wanted to ensure the accuracy of the experimental results, what problems should he pay attention to in the experimental design? ** Answer ** The experimental variable was light. In order to ensure the accuracy of the experimental results, the following issues needed to be noted: (1) The number of seeds must not be too small, and a sufficient sample size must be ensured. (2) Other than the variable of light, other conditions such as temperature, moisture, air, seed type, and fullness must be maintained. (3) Set up a control group and an experimental group. The control group was under normal light or no light (according to the experimental design), while the experimental group changed the lighting conditions. ** 4. Experiment on plant photosynthesis ** 9. ** Title * In the experiment to verify that green leaves could produce organic matter under light, what was the purpose of putting potted geraniums in the dark for a day and night? What was the purpose of covering a part of the leaf from top to bottom with black paper? ** Answer ** The purpose of placing the potted geraniums in the dark for a day and night was to remove or exhaust the original starch in the leaves to prevent the original starch from interfering with the experimental results. The purpose of covering a part of the leaf from top to bottom with black paper was to form a comparison experiment with and without light, so that he could explore the indispensable conditions for green leaves to produce organic matter. 10. ** Title * In the experiment to explore the oxygen produced by photosynthesis, how was the oxygen collected and tested? ** Answer ** One could collect oxygen using the drainage method. Put a green plant (such as hornfish) in a large beaker filled with clear water, cover the plant with a funnel, and then turn a test tube filled with water upside down on the funnel. After shining it under light for a period of time, oxygen would be collected in the test tube. The way to test for oxygen was to put a piece of wood with sparks into the collected gas. If the wood reignited, it proved that the gas was oxygen. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology questions and answers related to oranges
Here are some biology questions and answers about oranges: ** 1. Multiple choice questions ** 1. The oranges are mainly distributed in the south of China, and the apples are mainly distributed in the north of China. The main ecological factors that cause this distribution difference are () - A. Temperatures - B. Water - C. Sunlight - D. Soil - Answer: A. Orange was a tropical fruit that liked warm and humid environments. The higher temperature in the south was suitable for its growth. Apple was a temperature-zone fruit, and the temperature conditions in the north were more suitable for its growth. Therefore, the main ecological factor that caused this distribution difference was temperature. 2. Huanglong disease is caused by the Huanglong disease virus that seriously harms orange fruit trees. In order to cultivate "virus-free orange seedlings", the most effective method is () - A. Grafting - B. Seed reproduction - C. Cultivation of tissues - D. Space Breeding - Answer: C. The tissue culture was the most effective way to cultivate virus-free seedlings. This was because tissue culture could take advantage of the omnipotent nature of plant cells and take the virus-free tissues of oranges for cultivation to obtain virus-free seedlings; Grafting may spread viruses; Seed reproduction offspring may have trait separation and may not be completely virus-free; Space breeding was mainly used to create new variants, not an effective method of detoxification. ** 2. Comprehensive Question ** The orange flesh was sweet and juicy, and it was rich in organic matter. 1. The substance that determines the sweetness of oranges is stored in the cell ()(fill in the name of the cell structure). - The answer was a vacuum. The vesicles of plant cells contained substances such as sugar, mineral salt, coloring matter, and protein. The substances that determined the sweetness of oranges (organic substances such as sugar) were stored in the vesicles. 2. The fruit of an orange is developed from the pistil. - Answer: Zifang. During the reproductive process of plants, the pistil's ovaries would develop into fruits. The fruits of oranges also developed from the ovaries. 3. When oranges rot, they produce a variety of toxic gases. The following statement about orange rot is correct () - A. When oranges rot, hydrogen hydrogen, nitrogen, and aromatic substances containing a aromatic ring are all toxic. Among them, hydrogen is the most toxic and has a strong rotten egg smell. - B. The gas produced by the decay of oranges is not harmful to the human body, because every time you can't finish eating the oranges, you throw them away after they rot without finding any problems. - C. The gas produced by the decay of oranges is only a toxic substance called hydrogen hydrogen. - Answer: A. When oranges rot, they will produce a variety of toxic gases, such as hydrogen sulfur, nitrogen, and aromatic substances containing the aromatic ring. The hydrogen sulfur is the most toxic and has a strong smell of rotten eggs; Option B is wrong. The gas produced by the decay of oranges is toxic. Although no obvious harm may be found at ordinary times, the gas produced by the decay of a large number of oranges is enough to threaten life and safety; Option C is wrong. The toxic gas produced by the decay of oranges is not only hydrogen sulfur. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Biology Proficiency interview questions and answers
Here are some questions and answers that might be asked during a biology interview: ** 1. Basic Concepts ** ** Question 1: Please briefly describe the concept of cell breathing and its main types. ** Answer: Cell breathing refers to the process in which organic matter goes through a series of oxidisation and decomposition in the cell to produce carbon dioxide or other products, releasing energy and producing bound protein. The main types include both oxygen breathing and oxygen breathing. Aerobic breathing was a process in which cells, with the participation of oxygen, completely oxided and decomposed organic substances such as glucose through the catalyze of various membranes, producing carbon dioxide and water, releasing energy and producing a large amount of ATP. The term "oxygen free" refers to the process in which cells break down organic substances such as glucose into incomplete oxidisation products through the catalyst of an organism under oxygen free conditions. At the same time, a small amount of energy is released. For example, the oxygen free breathing of plants produces alcohol, carbon dioxide, or actic acid.(Some organs of higher animals and some plants, such as potato tubers and sugar beets, produce actic acid through oxygen free breathing.) [Question 2: What are genes?] What is the role of genes in inheritance? The answer was that genes were fragments of DNA that had hereditary effects. Genes played an important role in inheritance. They were the basic units of genetic information. Genes control the synthesis of protein through the process of translation and translation, and thus control the traits of organisms. In the process of reproduction, genes could be accurately replicated and passed on to future generations, allowing future generations to inherit the genetic characteristics of their parents. At the same time, genes would also mutate and provide raw materials for the evolution of organisms. ** 2. Biological Phenomena ** [Question 3: Why do some creatures migrate during seasons?] Answer: There are the following main reasons for the seasonal migration of creatures. From the perspective of food resources, as the seasons changed, the amount and types of food in different regions would change. For example, some migrating birds would migrate to the south to look for food. In terms of environmental adaptability, seasonal changes would bring about huge changes in environmental factors such as temperature and humidity. Some creatures would find it difficult to survive and reproduce in unsuitable environmental conditions. For example, some fish would swim from cold water areas to warm waters for reproduction. In addition, reproductive needs were also an important factor. Many animals needed specific environmental conditions to reproduce. They would migrate to areas suitable for reproduction, like salmon that would migrate to their birthplace to reproduce. [Question 4: How do you explain the mimicry phenomenon of creatures?] Answer: The mimicry phenomenon of a living creature is an adaptation strategy to the environment formed during the evolution process of a living creature. Some creatures would imitate the shape, color, and markings of other creatures or objects in the environment. From a defensive point of view, prey creatures could avoid their natural enemies by mimicking other creatures that were dangerous or inedible. For example, the Dead Leaf Butterfly mimicked the shape and color of the dead leaves, making it difficult for predators to discover it. In terms of hunting, predators could also approach their prey through mimicry. For example, the shape and color of some orchid mantises were like flowers, attracting insects that came to collect honey for easy hunting. This mimicry phenomenon was the result of natural selection, which was beneficial to creatures in the competition for survival. ** 3. Frontier Research ** ** Question 5: What is your understanding of the significance of gene editing technology (such as CrispR-Cas9) in biological research and application? ** Answer: Gene editing technology (CrispR-Cas9) has many important implications in biological research and applications. In terms of basic research, it allowed scientists to accurately edit the genomes and help them study the function of genes. For example, one could observe the changes in the biological traits by knocking out or modifying specific genes to determine the role of genes in growth, development, disease occurrence, and so on. In the field of medical applications, it brought hope to gene therapy. It could be used to repair pathogenic mutations in the human genomes and treat some hereditary diseases, such as sickle cell leukemia. In agriculture, it could improve the genes of crops, increase the yield, resistance to pests, and nutritional value of crops. For example, it could cultivate crop varieties that were more resistant to drought and insects. However, this technology also faced ethical and safety challenges, such as the possibility of off-target effects leading to unpredictable genetic changes. [Question 6: Please talk about your understanding of the latest research progress on the conservation of biological species.] Answer: Currently, there are new research developments in many aspects of conservation of biological resources. In terms of conservation strategies, there was a gradual shift from single-species protection to the overall protection of the ecosystem, because people recognized that the integrity of the ecosystem was crucial to the maintenance of species. The study found that measures such as protecting hot spots of biological richness and establishing ecological corridors could help protect the habitat of many creatures. In terms of technical means, satellite remote sensing, drone monitoring and other technologies could more accurately monitor the dynamic changes of the ecosystem. For example, changes in forest coverage and changes in the habitat of rare species could be monitored. In the aspect of the protection of genetic variation, the genetic resources of species were preserved by establishing gene banks and seed banks, and the genes of endangered species were analyzed and protected by means of biotechnology to prevent the loss of genetic variation of species. At the same time, in terms of raising public awareness, through education and publicity activities, more people would realize the importance of biotechnology, thus promoting the participation of the whole society in the conservation of biotechnology. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Analysis of the answers in cell biology textbooks
The following is an explanation of the concepts related to cell biology: ** 1. Basic Concepts of Cell ** 1. ** Understanding that cells are the basic unit of life activities ** - From a structural point of view, all organisms were made up of cells, and cells were the foundation for constructing organisms. - The cells had an independent and orderly self-controlled metabolism system. They were the executors of metabolism and function. The cell was also the foundation for the growth and development of an organism. It was also the basic unit of inheritance and had genetic omnipotency. Without cells, there would be no complete life. The cells themselves were a multi-layered, non-linear, and complex structural system. They were also a complex combination of substance (structure), energy, and information processes. They had a high degree of order, self-assembly, and self-organization. 2. ** The reason for the existence of the smallest and simplest form of cells ** - It could grow on a medium and had a typical cell membrane. - Its genetic information was carried by a circular double-stranded DNA. The messenger acid could combine with the Ribosome to form a polysome to guide the synthesis of the protein. It split into two and multiplied. Its size was only one-tenth of that of bacteria, and it could also parasitize and reproduce in the cell. 3. ** The understanding of viruses as non-cellular life forms and the difference and relationship between viruses and cells ** - A virus was composed of a core of a single DNA or R A and a shell of a protein. It was the smallest and simplest organism. There were also special forms such as virus-like viruses that were composed only of infectious R A and prions that were composed only of infectious protein. Although viruses had the basic characteristics of replication and inheritance, they lacked the structure of cells and were incomplete life forms. Its main life activities could only be displayed inside the cells. It replicated and proliferated inside the host cells. It did not have an independent metabolism and energy conversion system. It had to rely on the host cells 'structure, raw materials, energy, and digestive system to proliferate. It was a complete parasite. - Compared to cells, viruses were very small and had a very simple structure. Their genetic carriers were diverse and completely parasitic. They proliferated by replicating and assembling. ** 2. Concepts related to cell classification ** 1. ** Evolutionary similarities and differences between prokaryonic cells, archaeokaryotic cells, and eukaryonic cells **(The reference materials did not provide a complete analysis, from the perspective of general knowledge) - The similarities were that they all had genetic material, which was related to the basic functions of life, such as the ability to synthesize certain substances. - The difference: - Procaryotes did not have a nucleus covered by a nuclear membrane. Their DNA was exposed, and they had the characteristics of space-time continuity in DNA replication, replication, and translation. - Eukaryotic cells had a nucleus that was covered by a nuclear membrane, and its expression and regulation were much more complicated. It could be regulated at various levels, such as pre-transcribed level, transcribed level, post-transcribed level, translated level, and post-translated level. - Archaeus cells had unique properties in some aspects. In terms of evolutionary relationship, they were in a special position between procaryotic cells and eukaryotic cells. For example, they had some characteristics different from procaryotic cells in terms of gene replication and translation. ** 3. Concepts related to cell structure and function ** 1. ** Concepts related to the composition of cells ** - The most basic biological small molecules that make up cells are the nuclei, the acids, the fatty acid, and the sugar. They form important biological molecules such as the nuclei, the protein, the fat, and the glycan. 2. ** Concepts related to cell sub-discipline (Experimental Biology)** - The main branches of cell science that were formed by the combination of cell science and other biological sciences were cell genetics, cell biology, and cell chemistry. 3. ** Concepts related to cell membrane structure ** - Phospholiptides on the biological membrane mainly include Phosphatidylcholin (Phosphatidyl Choline), Phosphatidyl Serine, Phosphatidylinositol, Phosphatidylethanolamin, and Sphingomyelin. The membrane protein could be divided into membrane intrinsic protein (integral membrane protein) and membrane peripheral protein (membrane outer protein). The basic characteristics of biological membranes were mobility and unsymmetrical. The main ways of binding between intrinsic protein and membrane were the interaction of water affinity, ion bond, and the interaction of the two bonds. 4. ** Concepts related to cell connection ** - Cell connections could be divided into closed connections, anchored connections, and communication connections. The main ways of anchor connection were desmosome, hemidesmosome, and the adhension zone and focal adhension. The desmosome was connected to the intermediate fibers in the skeletal system, while the adhension zone was connected to the microfibers (actins). The main ways of communication were gap junction, plasmodesmata, and chemical bond. 5. ** Concepts related to the extra-cellular matrix ** - The basic components of the matrix were mainly composed of protein, elastins, glycan, laminins, fibronectins, etc. The main components of plant cell walls were Celluloses, Hemicelluloses, Flucoids, Expansins, and Proglycans. 6. ** Concepts related to cell surface specialized structures ** - The specialized structures formed on the surface of the cell included membrane skeleton, microvils, flagella, cilia, and deformed feet. 7. ** Concepts related to the transport of substances across membranes ** - The main pathways of material transport across the membrane were passive transport, active transport, as well as the effects of engulfment and exomyosis. Passive transport could be divided into simple and assisted diffusing. The latter required specific membrane transport protein (carrier protein and channel protein) to complete the transport of substances across the membrane. According to the energy source, active transport could be divided into ATP-directly powered transport, ATP-indirectly powered transport, and optical driven active transport. Co-transport belonged to the active transport type. According to the relationship between the direction of material transport and the direction of ion transfer along the electrochemistry, it could be divided into co-transport (co-transport) and reverse transport. For example, in the sodium-potassium pump, every atom of ATP-consumed could transport 3 Na ions and 2 K ions. The sodium-potassium pump and the calcium pump were both multi-spanning membrane protein with ATP-ase activity. In eukaryotic cells, there were three types of photon pump: P-type photon pump, V-type photon pump, and H + -ATPases. The transport of large molecules across the membrane was completed by transcytosis and exomyosis. According to the size of the vesicle and the substances that were swallowed, transcytosis could be divided into transcytosis and engulfment. ** 4. Concepts related to cell observation technology ** 1. ** Microscope resolution concept ** - The resolution referred to the smallest distance between two particles that the microscope could distinguish. 2. ** Concepts related to electron microscope ** - The electron microscope was mainly divided into two types: transmission electron microscope and scanning electron microscope. The commonly used electron microscope techniques in biology included ultra-thin section technique, negative staining technique, freeze-engraving technique, and so on. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
2016 biology exam paper and answers in detail
2009 national college entrance examination comprehensive biology paper answers detailed explanation
The detailed answers to the 2009 National College Entrance Examination for Science and Biology are as follows: 1. ** Overall Situation ** - The objective questions were still five questions with 30 points, while the subjective questions were changed from two to four, with a total score of 42 points. This kind of change was a breakthrough in form. The number of test points increased, and the score for a single question decreased. Although it was not easy to distinguish, it helped the examinees to perform steadily. - The difficulty level was slightly higher than 2008, and it was easier than 2006 and 2007. There were no eccentric questions, and the background of the questions mostly came from textbooks or common exercises. The test points were all core knowledge points of high school biology. - The genetic part appeared in the form of two multiple-choice questions instead of big questions, which reduced the difficulty of the biological part. The ecological content that used to appear in the form of multiple-choice questions appeared in the national paper for the first time in the form of big questions. The test point was the content that students were familiar with. Some key contents such as photosynthesis, molecular genetics, and immunity were not reflected in the test questions, and cell multiplication was not examined. - The total score was 21 points for cell metabolism, 11 points for regulation, 12 points for genetics, 10 points for ecology, and 18 points for elective content. The proposition was relatively stable, reflecting the tendency of returning to the textbook, which was helpful in guiding the positive development of high school biology teaching. However, there were few innovative parts and the ability assessment was lacking. 2. ** Analysis of Part of the Test Questions ** - For questions related to human genetic diseases: - Human genetic diseases were divided into three categories: monogeneic genetic diseases, polygenetic genetic diseases, and genetic diseases with abnormal chromosomy. Mutations in single genes and changes in the structure of the nuclei could lead to hereditary diseases. Marriage between close relatives would increase the risk of hereditary diseases. Polygenetic diseases not only had familial clusters, but they were also susceptible to environmental factors. - For questions related to metabolism: - During the metabolism of substances in the body of microorganisms, the essence of the regulation of the activity of the protein was the irreversible combination of the substances produced during the metabolism and the protein, resulting in the change of the structure of the protein. For example, substance D was the product of the synthesis of the reagent, and it was also the feedback inhibition of the reagent, while substance E reduced the activity of the reagent by combining with the reagent. However, there was no information in the picture that showed that the activity of the reagent 1 would be inhibited when either substance D or substance E was excessive. If the final product of the metabolism pathway was continuously discharged from the body, the inhibition of the third substance on the protein could be eliminated. - For questions related to fermentation engineering: - During the production of Glutinic acid through fermentation engineering, sterile air must be constantly introduced during the fermentation, otherwise, it will accumulate into the acid. Liquid natural medium is often used. The yield of wild-type strains isolated from nature was low and could not be directly used for production. They needed to be improved through mutation breeding and other methods. When the growth of the bacteria entered a stable period, the yield of Glutinic acid could be increased by supplementing nutrients. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>