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Elementary school fourth grade second volume vertical calculation questions 100 questions with answers

Elementary school fourth grade second volume vertical calculation questions 100 questions with answers

2026-10-10 14:59
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The following are some of the vertical calculation questions in the fourth grade of primary school (with answers): * * 1. Add vertically ** 1. $56.9 + 156.32 = 213.22$ 2. $289 + 476 = 765 $(Commutative law: $476 + 289 = 765 $) * * 2. Subtraction vertical calculation ** 1. $300 - 29.956 = 270.044 $(Checking:$270.044 + 29.956 = 300 $) 2. $15.49 - 2.3 = 13.19$ * * 3. Multiplication in vertical form ** 1. $28×34 = 952$ 2. $65×83 = 5395$ 3. $4050×780 = 3159000$ * * 4. Divide vertically ** 1. $69÷23 = 3$ 2. $324÷81 = 4$ 3. $832 × 4 = 208 $(Checking:$208 × 4 = 832 $) Due to the large number of 100 questions, only some typical vertical calculation questions are listed here. You can continue to write more vertical calculation questions for practice according to the basic rules of the four arithmetic operations. Read more exciting novels for free

Elementary school fifth grade decimals mixed calculation questions and answers

The following are some examples of fifth-grade elementary school decimal-point mixed calculation questions and answers: 1. Mental calculation: - \(3.6 + 4.4 = 8\) - \(5.2 - 3.4 = 1.8\) - \(0.2×7.8 = 1.56\) - \(7.8÷6 = 1.3\) - \(1÷4 = 0.25\) - \(7.5÷0.3 = 25\) - \(9.8 - 8 = 1.8\) - \(0÷27.9 = 0\) - \(6.5×0.2 = 1.3\) - \(0.1÷0.5 = 0.2\) - \(13.2 - 6.8 = 6.4\) - \(0.15÷15 = 0.01\) - \(2×3.8 = 7.6\) - \(9÷4.5 = 2\) - \(0.42÷3 = 0.14\) - \(11 - 0.92 = 10.08\) - \(4×5 = 20\) - \(1.8÷0.03 = 60\) - \(75÷2.5 = 30\) - \(0÷25.4 = 0\) - \(0.125×8 = 1\) - \(7.24 - 2.4 = 4.84\) - \(17.2 - 17.2 = 0\) - \(0.99÷0.1 = 9.9\) 2. Free calculation: - \(82.34×0.5×0.8 = 82.34×(0.5×0.8)=82.34×0.4 = 32.936\) - \(4.53 + 19.8÷(26.8 - 1.24)=4.53+19.8÷25.56 = 4.53 + 0.775 = 5.305\) - \((90.45)÷(2.5 + 1.53)=45.45÷4.03 = 11.28\) - \(10.98-(3.51×3.51)=10.98 - 12.3201=-1.3401\) 3. Formula calculation: - \( (3 + 1.5)÷4.5 = 4.5÷4.5 = 1\) - \(0.5×(4.8 - 3.5)=0.5×1.3 = 0.65\) <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-01 07:34

The first volume of the fourth grade of primary school, 20 calculation questions

The following are examples of 20 calculation questions that may be involved in the first volume of the fourth grade of primary school (vertical, off-form, simple calculation): ** 1. Horizontal calculation (10 lines, example of dividing a three-digit number by a two-digit number)** 1. $324÷12 =$ 2. $456÷18 =$ 3. $567÷21 =$ 4. $298÷13 =$ 5. $345÷15 =$ 6. $490÷25 =$ 7. $512÷16 =$ 8. $630÷21 =$ 9. $728÷28 =$ 10. $840÷35 =$ ** 2. Free Form Calculation (5)** 1. $25×(34 + 16) - 120$ - First calculate the number in the parenthesis: $34+16 = 50$, then multiply: $25×50 = 1250$, and finally subtract: $1250 - 120 = 1130$. 2. $128 + 72÷8×5$ - Divide: $72 div8 = 9$, multiply: $9×5 = 45$, and add: $128+45 = 173$. 3. $(45 - 18)×(32 + 16)$ - First calculate the numbers in the parenthesis: $45 - 18 = 27$,$32+16 = 48$, then multiply: $27×48 = 1296$. 4. $360÷(72÷8)$ - First, he calculated the number in the parenthesis: $72 div8 = 9$, then he calculated the division: $360 div9 = 40$. 5. $158 - (64 + 36÷9)$ - First, he calculated the division in the parenthesis: $36 div9 = 4$. Then, he calculated the addition in the parenthesis: $64 + 4 = 68$. Finally, he calculated the deduction: $158 - 68 = 90$. ** 3. Simple calculation (5)** 1. $25×36$ - It could be converted to: $25×4×9 = 100×9 = 900$. 2. $125×88$ - It was converted to $125×8×11 = 1000×11 = 11000$. 3. $45×99$ - It is written as: $45×(100 - 1)=45×100 - 45×1 = 4500 - 45 = 4455$. 4. $36×102$ - It became: $36×(100 + 2)=36×100 + 36×2 = 3600 + 72 = 3672$. 5. $23×18 + 77×18$ - Using the multiplication distribution law: $(23 + 77)×18 = 100×18 = 1800$. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-07 02:19

Elementary school fourth-grade interesting math questions and answers

The following are some of the answers to some of the interesting math questions in the fourth grade: ** 1. Number Combination ** 1. [Question: How to make the number 8 equal to 1000?] - ** Answer **: 8 + 8+8+88 + 888 = 1000. - ** Explanation **: By adding different combinations of the number 8, a number close to 1000 can be obtained. For example, 888 is close to 1000, and adding other combinations of the number 8 to get 1000. 2. [Question: Use three 3s to form the largest number?] - [Answer: 3 to the power of 33] - ** Explanation **: 3 to the power of 33 is much larger than 333, because the exponential operation will make the number grow very fast. When the base is 3 and the index is 33, this number is the largest number that can be formed by three 3s. 3. [Question: What is the largest number that can be formed by 1, 2, and 3?] - ** Answer **: 3 to the power of 21. - [Description: If it is formed according to the convention, 321 is not the largest.] Because of the nature of exponential calculation, 3 to the power of 21 was much larger than other combinations. ** 2. Points and Number of People ** 1. [Question: 100 steamed buns, 100 people eating, 1 adult eating 3, 3 children eating 1, how many adults and how many children can finish it?] - [Answer: 25 adults and 75 children.] - ** Explanation **: Suppose there are x adults and y children. You can get the equation set of <x + y=100>(the total number of people is 100) and <3x+<frac{1}{3}y = 100>(the total number of buns is 100). Transform the first equation to {y = 100 - x}, substitute it into the second equation {3x+{frac{1}{3}(100 - x)=100}, and solve {x = 25}, then {y = 75}. 2. ** Question **: There are 63 notes in total for 2 yuan and 5 yuan each, totaling 171 yuan. How many notes are there for each of the two kinds of yuan? - ** Answer **: 48 for 2 RMB and 15 for 5 RMB. - ** Explanation **: Suppose there are x pieces for 2 RMB and y pieces for 5 RMB. The equations are x + y=63 and 2x +5y =171. From the first equation, we get x = 63 - y, and substitute it into the second equation, which is x = 48. ** 3. Itinerary and Time ** 1. ** Title **: A well is seven meters deep. A snail climbs up from the bottom of the well. It climbs three meters during the day and falls two meters at night. Ask a snail how many days it takes to climb out of a well? - [Answer: 5 days.] - ** Explanation **: The snail actually climbs 3 - 2 = 1 m every day. However, on the last day, after climbing out of the well during the day, they would not fall anymore. Therefore, in the first few days, they had climbed a total of 7 - 3 = 4 meters, which required 4 days. Including the last day, it was a total of 5 days. 2. [Question: If the clock shows that it is 18 o'clock sharp, what time will it be after the minute hand has rotated 1991 times?] - ** Answer **: The minute hand rotating once is 1 hour, 1991/12 = 165…11 (12-hour cycle), 18+11 - 24 = 5 points. - ** Explanation **: First, look at how many 12-hour cycles 1991 contains. The remainder is the extra hours added, plus the initial 18 points. If it exceeds 24 points, then subtract 24 to get the final time. ** 4. Trading Profits ** 1. [Title: Someone bought a toy for 19 yuan and sold it for 20 yuan.] He felt that it was not worth it, so he bought it for 21 yuan and sold it for 22 yuan. How much did it earn? - ** Answer **: 2 yuan. - ** Explanation **: The first transaction earned "(20 - 19 = 1") yuan, the second transaction earned "(22 - 21 = 1") yuan, the total earned "(1+1 = 2") yuan. ** 5. Logic-related reasoning ** 1. [Question: Xiao Qiang's math score was only 6 points away from passing, and so was Xiao Ming's. However, Xiao Ming's and Xiao Qiang's scores were different. Why?] - [Answer: 54 points and 0 points.] - ** Explanation **: If the full score is 60 points, 54 points will be 6 points away from passing, and 0 points will also be 6 points away from passing. The requirement is that the two people are 6 points away from passing but have different scores. 2. [Question: There are three empty rooms. One room has three lights, and the other room has three switches. Each switch can only turn on one light. If you can only enter each room once, how do you know which switch controls which light?] - Answer: Enter a room with a switch, turn on one switch, turn it off after 5 minutes, turn on the other switch, and then enter a room with a light. The light that was on was controlled by the switch that was turned on the second time. He touched the other two lights that were not on. The one that was hot was controlled by the switch that was turned on the first time, and the remaining one was controlled by the switch that had not been turned on. - ** Explanation **: Use the characteristics of the light bulb to judge whether the switch that is turned on will make the light on or heat up. Use different operations to distinguish the lights controlled by different switches. 3. [Title: Two chess friends played a total of nine games in a day. They won the same number of times without a draw. What's going on?] - [Answer: Not all nine games were played by the two of them.] - [Description: If the two of them played all nine games, the number of times they won would not be the same without a draw. Therefore, there must be a situation where they played against someone else.] <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-08 11:43

Third grade elementary school second volume mathematics calculation questions 50

The following are 50 third-grade elementary school math problems: ** 1. Mental arithmetic questions (20 questions)** 1. $25×4 =$ 2. $120÷6 =$ 3. $300 - 50 =$ 4. $45 + 55 =$ 5. $18×5 =$ 6. $200÷4 =$ 7. $560÷7 =$ 8. $320 + 80 =$ 9. $13×3 =$ 10. $90 - 35 =$ 11. $40×5 =$ 12. $270÷9 =$ 13. $100 + 230 =$ 14. $63÷3 =$ 15. $0×125 =$ 16. $480÷8 =$ 17. $70×8 =$ 18. $360 - 90 =$ 19. $50×6 =$ 20. $110 + 90 =$ ** Two, vertical calculation questions (15 questions)** 1. $345 + 255 =$ 2. $567 - 342 =$ 3. $234×5 =$ 4. $456÷3 =$ 5. $321 + 479 =$ 6. $789 - 567 =$ 7. $123×6 =$ 8. $560÷7 =$ 9. $432 + 268 =$ 10. $705 - 438 =$ 11. $25×16 =$ 12. $396÷6 =$ 13. $543 + 357 =$ 14. $876 - 543 =$ 15. $48×12 =$ ** 3. Free Form Calculation Questions (15)** 1. $25×(4 + 8) =$ 2. $120 - 30×3 =$ 3. $(13 + 17)×5 =$ 4. $450÷(9÷3) =$ 5. $36 + 24×2 =$ 6. $560÷(7×8) =$ 7. $18×(5 + 3) =$ 8. $200 - 150÷5 =$ 9. $(23 + 27)÷10 =$ 10. $480÷8 - 30 =$ 11. $35×2 + 15 =$ 12. $12×(9 - 5) =$ 13. $500÷(25 - 15) =$ 14. $42 + 36÷6 =$ 15. $72÷(8 + 1) =$ <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-11 01:42

Third grade elementary school questions and answers

Below are some of the third grade math questions and answers: ** I. Question on the weight of the goods ** 1. ** Title * There are 6 boxes of goods of the same weight. If you take 6 tons from each box, the mass of the remaining goods in the 6 boxes is equal to the mass of the goods in the original two boxes. How many tons does each box weigh? 2. ** Answer ** First, he calculated the total weight of the goods taken: $6×6 = 36$(tons). Because the quality of the remaining goods in the six boxes is equal to the quality of the goods in the original two boxes, the goods taken away are equivalent to the original $6 - 2=4$boxes. The weight of each box of goods was: $36/4 = 9$(tons). ** 2. Question on the area of the graph ** 1. ** Title * If two squares of the same size overlap, each square has a side length of 27 centimeters. After one side of the overlapping part is covered, there is 15 centimeters left. Find the area of the overlapping shadow (square). 2. ** Answer ** First, find the side length of the overlapping square.$27 - 15 = 12$(cm). The area of the overlapping shadow was $12×12 = 144$(square centimeters). ** 3. Questions about position and direction ** 1. ** Title * In the known location question, with the school as the observation point, which corner of the school was the park? (You need to follow the direction of the top, north, bottom, south, left, west, right, east) 2. ** Answer ** First, the school was used as the direction of the observation point, and then the corresponding angle (such as the northwest corner) was determined according to the direction of the park. ** 4. Questions on Natural Numbers ** 1. ** Title * There was a class of natural numbers less than 200. The sum of each digit was odd, and it was the product of two two-digit numbers. Find the third largest number in this class of natural numbers. 2. ** Answer ** The largest number in this class is $195 = 13×15$, followed by $182 = 13×14$, and the third largest is $180 = 12×15$. ** 5. Time calculation question ** 1. ** Title * Xiao Ming and Xiao Qiang each had a large piece of chocolate. Xiao Ming ate a small piece every 20 minutes and ate the last small cube at 14:40. Xiao Qiang ate a small piece every 30 minutes and ate the last small cube at 18:00. He begged them to start eating the first small piece. 2. ** Answer ** 18:00 - 14:40 = 3 hours and 20 minutes = 3×60 + 20 = 200 minutes. The number of pieces eaten = $200/(30 - 20)=20$, Little Ming ate 20 yuan, and the time taken was 20×20 = 400 minutes = 6 hours and 40 minutes. The time to start eating the first piece was 14:40 - 6:40 = 8:00. ** 6. Questions on the relationship between quantities ** 1. ** Title * There were a total of 163 watercolor pens and pens in the shop. If he took away 19 watercolor pens, the number of watercolor pens would be exactly five times that of the pens. How many watercolor pens and pencil did you have? 2. ** Answer ** After taking away 19 watercolor pens, the total became $163 - 19 = 144$, which was exactly $1 + 5 = 6$times the number of pens. The pencil is: $144/6 = 24$(pieces) The watercolor pens were: $24×5 + 19 = 139$(each). ** 7. Self-study time ** 1. ** Title * Student A and Student B originally planned to spend the same amount of time on self-study every day. If Student A increased his self-study time by half an hour every day and Student B reduced his self-study time by half an hour every day, then Student B's self-study time of six days would only be equivalent to Student A's self-study time of one day. He asked A and B how many minutes they had set for self-study every day. 2. ** Answer ** Self-study time after reducing half an hour every day = $1/(6 - 1)=1/5$hour = 12 minutes. The original plan was to study on his own every day = $30 + 12 = 42$minutes. A's original plan was to study by himself every day = $12×6 - 30 = 42$minutes. ** 8. Subtraction Questions ** 1. ** Title * In a deduction formula, the sum of the minuend, the subtract, and the difference was equal to 120, and the subtract was three times the difference. What was the difference? 2. ** Answer ** Because the minuend = subtrahend + difference, and because the minuend + subtrahend + difference = 120, the minuend = $120 div2 = 60$. The difference = $60/(3 + 1)=15$. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-04 22:39

Primary school students 24-point calculation questions 100 questions with answers

The following are some of the 24-point calculation questions and answers: 1. 1、1、1、8:(1+1+1)*8 = 24 2. 1、1、2、6:(1+1+2)*6 = 24 3. 1、1、2、7:(1+2)*(1+7)=24 4. 1、1、2、8:(1*1+2)*8 = 24 5. 1、1、2、9:(1+2)*(9 - 1)=24 6. 1、1、2、10:(1+1)*(2+10)=24 7. 1, 1, 3, 4: 8. 1、2、5、10:(10÷2)*5 - 1 = 24 9. 2, 7, 8, 10: 10. 4, 8, 2, 10: 11. 7、6、10、3:1. 10 - 3 = 7,7*3 = 21,21+6 = 24 12. 10, 3, 8, 8 (Requires calculation) 13. 3、4、5、7:1. 7*3 = 21,21+7 = 28,28 - 4 = 24 14. 1、1、5、6:(5 - 1)*1*6 = 24;5×(6 - 1)-1 = 24 15. 3、9、9、9:3×(9 - 9÷9)=24;9 - 3+9+9 = 24;(9×9 - 9)÷3 = 24 16. 5、7、7、10:(7 - 5)*7+10 = 24 17. 2、3、5、12:12÷(3 - 5÷2)=24 However, only these questions were provided, and there was still a gap from 100 questions. If you need more questions, it is recommended to search for more comprehensive content through the search engine "24-point calculation questions with 100 answers". <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-01 03:20

Elementary school second grade Chinese first volume writing training questions and answers

The following is some of the content related to the writing training for the second grade of primary school: 1. ** Special training to improve writing skills in the second year's first volume of Chinese language module (answers included)**, can be used to improve writing skills. 2. ** The second year's first volume of Chinese oral communication and writing exercises (with answers)**, including oral communication and writing. 3. ** Teaching materials to help with writing exercises (with answers)**, can teach writing step by step. 4. ** Ministry edition, second grade Chinese exercise questions with answers (6 sets in total)**, some of which involved writing training related content, such as the question of looking at pictures and writing words. It required carefully looking at the characters and their actions and then imagining to write a paragraph. It also included basic exercises such as filling in the blanks after adding words to assist in writing training. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-11 22:21

Primary school fourth grade key mathematics questions and answers

The following are some of the key math questions and answer types in the first volume of the fourth grade: ** I. Type of application questions ** 1. ** Problem on operational relationships ** - [Question: Xiao Ming has 25 candies. Xiao Hong has 3 times more candies than Xiao Ming. How many candies does Xiao Hong have?] - [Answer: First calculate the number of Little Red's candies by three times, which is 25×3 = 75 candies. Adding the extra 5 candies, 75+5 = 80 candies, so Little Red has 80 candies.] 2. ** About how to convert units in application questions ** - [Question: The capacity of a water tank is 500 liters, and 5000 milliliters of water can be used every day. How many days can this water be used?] - Answer: First, convert the units. Since 1 liter = 1000 milliliters, 500 liters = 500×1000 = 500000 milliliters. Divide the total amount of water by the daily water consumption. 500,000/5,000 = 100 days. ** 2. Type of fill-in-the-blank question ** 1. ** Digital related ** - Title: The million digits of a number are 7, the ten thousand digits are 3, the thousand digits are 9, and the remaining digits are 0. This number is written as (). - Answer: 7039000. 2. ** Calculating rules ** - [Question: According to the distribution law of multiplication, 25×(40 + 4)=25×40+() ×4.] - Answer: 25. ** 3. The key questions and error-prone questions in the calculation questions ** 1. ** Four Mixed Operations ** - Title: 360 × (72 - 6×12) - Answer: First calculate the multiplication 6×12 = 72 in the parenthesis, then calculate the substitution 72 - 72 = 0 in the parenthesis. Because the division number cannot be 0, this question is meaningless. 2. ** Simple calculation ** - Title: 25×32×125 - The answer was to split 32 into 4×8, and the original formula became (25×4)×(8×125)=100×1000 = 100000. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-04 06:41

Fourth grade primary school mathematics Olympiad questions and answers

The following are some of the fourth grade primary school math Olympiad questions and answers: 1. ** and times problem **: The quotient of two numbers is four, the remainder is two, and the sum of the two numbers is forty-two. Find these two numbers. - If the smaller number is x, and the quotient of the larger number divided by the smaller number is 4 and the remainder is 2, then the larger number is x. The sum of the two numbers is 42, which gives the equations: x+(4x + 2)=42, 5x+2 = 42, 5x=40. The solution is x = 8, and the larger number is 44. 2. ** Divide with known dividends, quotient, and remainder **: Divider is 3320, quotient is 150, remainder is 20. - According to the formula, we can get the result: <<(3320 - 20)> div150 = 22>. 3. ** Successive natural number sum problem **: 3998 is the sum of four consecutive natural numbers, find the smallest number. - Let the smallest number be {x}, then the other three numbers are {x + 1},{x+2}, and {x + 3}, which gives the equation {x+(x + 1)+(x+2)+(x + 3)=3998},{4x+6 = 3998}, and {4x=3992}. The solution is {x = 998}. 4. ** Number and Decimals Adding Problem **: There is a two-digit number. Add a decimals point in front of one of its digits and add it to the two-digit number. The result is 20.9. Find the two-digit number. - Let this two-digit number be <x>, because the result after adding is <20.9>, we can know that this decimal is <0.1x>, then <x+0.1x = 20.9>,<1.1x = 20.9>, the solution is <x = 19>. 5. ** Family age problem **: A family of three, the total age of the three is 72 years old, mother and father are the same age, mother's age is four times that of the child, please age the three. - If the child's age is considered as a multiple of 1, and the parents are four times the child's age, then the child's age is <72'> div4>(1 + 4+4)=8>, and the mother and father's age is <8'> time4>= 32>. 6. ** Sports allocation problem **: A, B, C and D will participate in basketball, volleyball, football and chess respectively. It was known that A was taller than a volleyball player, that D had lost his legs in an accident a few years ago, and that a soccer player was shorter than C and a basketball player. Ask A, B, C and D to participate in what event. - From the fact that Ding lost his legs, he could tell that Ding was a chess player; A was not a volleyball or football player, so A was a basketball player; C was not a football player, so C was a volleyball player; B was a football player. 7. [Fruit packing problem: 10 fruits must be packed in 6 bags. The number of fruits in each bag must be even, and there must be no fruit or bags left.] - He put two bags in each bag and five bags in the last bag. 8. ** Comparing the amount of money left after spending money **: Naughty had 300 yuan, 56 yuan for books, and 128 yuan for stationery. How much less was Naughty left than before? - The money that was less than the original amount was the money spent. The total amount spent was [56+128 = 184] yuan. 9. [Question of the number of fishes: The two brothers went fishing and caught a total of 23 fishes. The elder brother caught three times more fish than the younger brother. How many fishes did the elder brother and younger brother catch?] - First, calculate the number of fish the younger brother has caught. The number of fish the older brother has caught is [(23 - 3)][Div(3 + 1)][5][1][2][3][3] 10. ** Alien payment problem **: Aliens have 1 cent, 2 cent, 4 cent, and 8 cent coins each. Please pay for 7 cent, 9 cent, 10 cent, 13 cent, 14 cent, and 15 cent items. - \(7 = 1+2+4\),\(9 = 1+8\),\(10 = 2+8\),\(13 = 1+4+8\),\(14 = 2+4+8\),\(15 = 1+2+4+8\)。 11. [Fruit distribution problem: There are bananas, apples, and oranges on the plate.] Xiao Gang, Xiao Lin, and Xiao Hong each took a different fruit. "Everyone can only eat one kind of fruit. I don't eat oranges," said Xiao Gang. "I don't eat apples or oranges," said Xiao Lin. Beg who to take what fruit. - Xiao Lin took the bananas, Xiao Hong took the oranges, and Xiao Gang took the apples. 12. ** Four-digit numbers and questions **: Which four-digit numbers have the sum of each number equal to 34? - There were 8899, 8989, 8998, 9889, 9898, 9988, 7999, 9799, 9979, and 9997. 13. ** Price of tables and chairs **: Given that the price of a table is 10 times that of a chair, and knowing that a table is 288 yuan more than a chair, please find the price of a table and a chair. - The price of a chair was $288,000, and the price of a table was $32,000. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-02 09:13

Elementary school third grade second volume Chinese unit one test questions and answers

Based on the information provided so far, we are unable to provide the test questions and answers for the third grade Chinese Language Unit 1. I am sorry. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

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2026-10-05 04:07
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