Xiao Ming reads a book every day, reads 15 pages, and after 4 days, there are still 3/5 of the book left. How many pages does this book have? Assuming that the book has a total of $x$pages, then the number of pages that Xiao Ming reads in 4 days is $15,4 = 60$pages. The remaining pages are 3/5 of the book's worth, so there are: $$ 60 \div (3/5) = 12 $$ So the book has a total of $12$pages.
Little Red reads a book 15 pages a day, and after 4 days, there is still 3/5 of the book left. We can assume that this book has x pages. According to the question, Little Red had read a total of $4/times 15 = 60$pages in 4 days. The remaining pages are 3/5 of the book, so there are: $$ 60\div 3/5=24 $$ Therefore, the book had 24 pages.
Assuming that the book has a total of $x$pages, then Little Red has read $x/times 15$pages in 4 days. The remaining pages are 3/5 of the book's worth, so there are: $$x <times 15><times 3/5>= Total pages $$ Solve this equation: $$x = \frac{total pages}{15} = \frac{1200}{15} = 80$$ Therefore, the book had a total of 80 pages.
Suppose the book has x pages: Little Cong read 15 pages a day for four days, a total of 4×15=60 pages. The total number of pages in the book is x, so: 60÷(1+3/5)=x÷5 The solution was:x=60×5 div3 =600 div3 =200 pages. Therefore, the book had a total of 200 pages.
Little Red reads 15 pages a day for 4 days and still has 3/5 of the book left. She can write the following equation: Remaining pages/pages per day = 3/5 of the book Solve the equation: Remaining pages = 3/5 x pages of the book Substituting the remaining pages into the original book's page count, he obtained: 3/5 x pages of the book = 15 pages Therefore, this book had: 15 pages × 3/5 = 15 pages/3/5 = 150 pages
Xiao Ming read a book for the first 4 days and read 15 pages, then read 6 pages every day for 5 days. We can use the following formula to calculate the average number of pages seen per day: Average number of pages read per day = total number of pages/days Substituting the total number of pages and the number of days into the formula, we get: Average number of pages read per day = 15 pages/4 days = 3 pages/day Therefore, Xiao Ming read an average of three pages a day.
Xiao Ming reads 24 pages a day and after 3 days, there are still 9/11 pages left. Remaining pages = book pages × 911/11 Substituting the number of pages in the book into the above formula: Remaining pages = 729 pages/11 Since Xiao Ming reads 24 pages a day, 24 × 3 = 72 pages of the remaining pages have already been read by Xiao Ming. Number of pages in the book-number of pages viewed = number of pages remaining That is: 729 pages- 72 = 720 pages Thus, the book had a total of 720 pages.
If Xiaoming reads 72 pages in the first 4 days, then Xiaoming's total page count in the first 4 days is 72 pages. Reading 29 pages every day for the next 6 days would mean that the total number of pages for the next 6 days would be 29 pages x 6 days = 171 pages. Therefore, Little Ming's total page count in the last six days was 171 pages. Little Ming read 171 pages per day for the next 6 days, 6 days = 27 pages. Therefore, Xiao Ming read an average of 27 pages a day.
Suppose the book has a total of x pages, and Chen Ming has read a total of y pages in these seven days: - Chen Ming read 11*3=33 pages in the first three days - In the next three days, Chen Ming read a total of 18*3=54 pages - In seven days, Chen Ming read a total of y*7=497 pages Therefore, Chen Ming read an average of 497/7=74 pages a day in the past seven days.
Xiao Ming read a total of $4/15 = 60$pages in 4 days. The remaining pages are $2/5$of the book, so the book has a total of $2/5/60 = 48$. Thus, the book had a total of 48 pages.
Let's say the book has $x$pages. Reading 15 pages a day, it would take Xiaohong $x$days to finish reading this book. The remaining pages were three-fifths of the book, which was $025x$. According to the question, it would take Xiaohong four days to finish reading this book. Therefore, we can write the equation: $$ x + 025x = 025 \times (x+4) $$ Solve this equation: $$ x = 30 $$ So this book has 30 pages.