Reading a long novel, 30 pages on the first day, 60 pages on the 11th day, just finished. How many pages is this book?
The book took 11 days to finish because 30 pages were read on the first day. The remaining pages were: 30 pages/day = 30/day The number of pages left every day was 60 - 30 = 30 pages. Therefore, the book would take 11 days to read, 30/day x 30 pages = 900 pages.
When Xiao Li read a novel, she would read 74 pages on the first day, 82 pages on the second day, 71 pages on the third day, 63 pages on the fourth day, and more pages on the fifth day than this…
The number of pages read on the fifth day was the number of pages read on the first day plus the number of pages read on the fourth day, which was 74 + 82 = 156 pages. Because the number of pages read on the fifth day was more than the sum of the previous four days, 156 > 4 × 71 + 3 × 63 + 2 × 82 + 1 × 74. Therefore, the answer was that Xiao Li read page 156 on the fifth day.
Xiaoming reads a book on the first day, reading 20% of the total number of pages, the number of pages read on the second day and the number of pages read on the first day is 5:4
Xiao Ming read 20% of the total number of pages on the first day of reading a book, which means that the total number of pages multiplied by 20% equals 20% of the total number of pages. On the second day, the ratio of pages read on the first day was 5:4, which meant that half of the total pages read on the second day was 25% of the total pages. Therefore, Xiao Ming read the total number of pages multiplied by 25% the next day, which was equal to the total number of pages multiplied by 5%. Divide the total number of pages by 5 to get the number of pages that Xiaoming read the next day divided by 5. That is, the total number of pages divided by 5 multiplied by 40% equals the total number of pages multiplied by 10%. Therefore, Xiao Ming read the total number of pages multiplied by 10% the next day, which was equal to the total number of pages multiplied by 5.
How many pages does this novel have? If you read 10 pages on the first day, and then read 2 more pages every day, you would finish 24 pages on the last day?
A day with superpowers, about 2 pages
A day with superpowers, about 2 pages If I have superpowers one day, I will use them to help others and change the world. First, I will use my superpower to cure diseases. I will go to the hospital and help those who are sick recover. Whether it's cancer, heart disease, or other diseases, I will do my best to help them. I believe that this can reduce people's suffering and allow more people to live healthy and happy lives. Secondly, I will use my superpower to protect the environment. I will clean up the garbage in the ocean and protect the balance of the marine ecosystem. I will also help plants grow and make nature more beautiful and prosperous. Through such efforts, I hope to improve the Earth's environment so that our future generations can live in a better world. In addition, I will also use my superpower to help those who need help. I will go to the poor areas and help those who do not have enough food and water. I will build schools and medical facilities so that they can receive education and medical care. I believe that through such hard work, we can change their destiny and give them a better future. In short, if I have superpowers one day, I will use this ability to help others and change the world. I believe that through my hard work, I can make the world a better and fairer place.
Little Ming was reading a storybook. He planned to read 12 pages a day, but he actually read 8 pages a day. In the end, he finished reading it two days earlier. How many pages is this storybook?
Xiao Ming planned to read 12 pages a day, but he actually finished reading 8 pages a day two days earlier. Assuming that this storybook has x pages: - The plan is to read x/12 days, which is x/12 pages. - Actually, x/8 days is x/8 pages. Because Little Ming finished reading it two days earlier, he only needed to read x/8 - x/12 = x/4 days. Because Xiao Ming reads 8 pages a day, he needs to read x/4 days x 8 pages = x 4/5 pages. Therefore, we can get the following equation: x/4 - x/12 = x/5 By solving this equation, one could obtain: x/12 = x/5 + 1/2 x/12 = (x+10)/5 x/12 = x/5 + 1/6 x/6 = 1/6 x = 1 Therefore, this storybook had one page.
For an extra-cursory book, after reading 24 pages on the first day, he would read 3 more pages each day than the previous day. On the last day, he would read 36 pages.
The number of pages of this extra-cursory book should be an increasing number, so we can list its approximate values as follows: 24 7 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 49 51 53 55 57 59 61 63 65 67 69 71 73 75 77 79 81 83 85 87 89 91 93 95 97 99 101 103 105 107 109 111 113 115 117 119 121 123 125 127 129 131 133 135 137 139 141 143 145 147 149 151 153 155 157 159 161 163 165 167 169 171 173 175 177 179 181 183 185 187 189 191 193 195 197 199 201 203 205 207 209 211 213 215 217 219 221 223 225 227 229 231 233 235 237 239 241 243 245 247 249 251 253 255 257 259 261 263 265 267 269 271 273 275 277 279 281 283 285 287 289 291 293 295 297 299 301 303 305 307 309 311 313 315 317 319 321 323 325 327 329 331 333 335 337 339 341 343 345 347 349 351 353 355 357 359 361 363 365 367 369 371 373 375 377 379 381 383 385 387 389 391 393 395 397 399 401 403 405 407 409 411 413 415 417 419 421 423 425 427 429 431 433 435 437 439 441 443 445 447 449 451 453 455 457 459 461 463 465 467 469 471 473 475 477 479 481 483 485 487 489 491 493 495 497 499 501 503 505 507 509 511 513 515 517 519 521 523 525 527 529 531 533 535 537 539 541 543 545 547 549 551 553 555 557 559 561 563 565 567 569 571 573 575 577 579 581 583 585 587 589 591 593 595 597 599 601 603 605 607 609 611 613 615 617 619 621 623 625 627 629 631 633 635 637 639 641 643 645 647 649 651 653 655 657 659 661 663 665 667 669 671 673 675 677 679 681 683 685 687 689 691 693 695 697 699 701 703 705 707 709 711 713 715 717 719 721 723 725 727 729 731 733 735 737 739 741 743 745 747 749 751 753 755 757 759 761 763 765 767 769 771 773 775 777 779 781 783 785 787 789 791 793 795 797 799 801 803 805 807 809 811 813 815 817
How many pages are left in this novel? If Lele reads 105 pages a day, there will be 28 pages left in three days?
The question cannot be answered based on the information provided. Please provide more information about the novel.
If you read 20% of the book on the first day, 25% of the total pages on the second day, and there are 110 pages left, how many pages are there in the book? stated
Ling Ling read a heavy story. On the first day, she read 11 pages, and on the second day, she read 14 pages. From then on, she read 3 pages more than the previous day. She finished reading it in 10 days. this
The novel was called "One Hundred Years of Solitude" by Colombia Márquez. According to the plot of the novel, Ling Ling would be able to finish reading the novel in ten days. Reading three more pages a day than the day before meant that the length of the novel would increase by three pages every day. Therefore, within 10 days, the length of the novel will increase to: 10 days x 3 pages/day = 30 pages Therefore, Ling Ling needed to read 30 pages of the novel in 10 days. If Ling Ling had this novel, she could start reading it on the first day and then read three more pages each day until she finished reading it.
He had read 12 pages on the first day, 6 more pages on the next day, and 48 pages on the last day. How many days had he read?
After reading 12 pages on the first day, he read 6 more pages every day than the previous day. On the last day, he read 48 pages. How many days did he read in total? He had read $12+12 + 12 + 12 + 12 +12+6+48$in total. Reading 6 more pages a day than the day before, so obviously in the first week, I read $12+12 + 12 + 12 + 12 +12+6+12=55$days. In the second week, he read $12+12 + 12 + 12 + 12 +12+6+12+12=63$days. By analogy, we can know that the total amount of reading before the end of the book is $55+63+70+73+80+86+98+48=695$days. Therefore, he read for a total of seven days.