The novel was called "One Hundred Years of Solitude" by Colombia Márquez. According to the plot of the novel, Ling Ling would be able to finish reading the novel in ten days. Reading three more pages a day than the day before meant that the length of the novel would increase by three pages every day. Therefore, within 10 days, the length of the novel will increase to: 10 days x 3 pages/day = 30 pages Therefore, Ling Ling needed to read 30 pages of the novel in 10 days. If Ling Ling had this novel, she could start reading it on the first day and then read three more pages each day until she finished reading it.
Fang Fang reads a long novel. She reads 40 pages on the first day, 5 pages more on the second day, and 80 pages on the last day. So she reads $40+40 + 40 + 40 +40+5+80=225$pages. Fang Fang read 40 pages on the first day and 5 more pages on the second day, which was 45 pages. The remaining pages were 40+45=85 pages. Because the number of pages she read every day was 5 pages more than the previous day, Fang Fang needed to read a total of ${85+85}{2}=50$days. Because Fangfang had read 80 pages on the last day, she needed to read 80+5+80=130 pages, so the remaining pages were 50-130=-80 pages. This result was a negative number that did not conform to the actual situation. Therefore, Fangfang did not finish reading the novel.
On the first day, Xiaofang read the book's 51 pages, and the remaining pages were $51/div2 = 25$. The next day, he read another 10 pages and the remaining pages were $25 + 10 =$35. At this point, the ratio of pages seen to pages not seen is 2:3, which can be expressed as $25:35=2:3$. Therefore, Xiaofang had read the book for $2+3=5$days and still had $35-5=28$pages left.
The number of pages read is the number of pages read on the first day plus the 16 pages read on the second day. Number of pages viewed = 10/1 + 16 = 16 + 10/1 = 26 + 10/1 = 36 Therefore, Wang Ying had already read 36 pages.
According to the ratio of the number of pages read to the number of pages unread on the first day was 2:7, the number of pages unread was 2/7 of the number of pages read. Because he read 42 pages the next day, the number of pages read was 42/2/7=91(pages), and the number of unread pages was 42/(2/7)=63(pages).
Xiaofang read 15 of the book on the first day and read 10 pages on the second day, so she read a total of ${1}{5} +{1 = 15}$pages. Assuming that the book has a total of $x$pages, then Xiaofang has read a total of $x \times \frac{1}{5} + x \times \frac{10}{1 = 10x + 50}$pages. At this time, the ratio of the number of pages read to the number of pages not read is 2, which means that the number of pages left by Xiaofang is twice the number of pages in the book, which is $x/times 2 = 10x + 50$. The solution is $x = 105$, which means that the book has 105 pages. Xiaofang read 15 pages on the first day and 10 pages on the second day. She read 25 pages in total.
The number of pages read on the fifth day was the number of pages read on the first day plus the number of pages read on the fourth day, which was 74 + 82 = 156 pages. Because the number of pages read on the fifth day was more than the sum of the previous four days, 156 > 4 × 71 + 3 × 63 + 2 × 82 + 1 × 74. Therefore, the answer was that Xiao Li read page 156 on the fifth day.
Little Min read a 900-page storybook, and on the first day, she read 124 pages. On the second day, she read 37 pages less than the first day. Assuming Min reads x pages the next day, the number of pages left on the second day is 900-x. According to the first day of reading page 124, the following equation can be listed: 124 + x = 900 - x + 37 Solve the equation: 151 = 867 Therefore, the number of pages that Little Min read on the third day should be a multiple of 867. Since 900 is an even number, 867 is a multiple of 900, so Min should start reading from page 867.
Zhang Li read a book of 80 pages. On the first day, she read 35% of the book, and on the second day, she read 1/4 of the book. How many pages did she read in two days? On the first day, he read 35% of the book, which was 80 pages x 35% = 28 pages. The next day, he read 1/4 of the book, which was 80 pages x 1/4 = 20 pages. Therefore, the total number of pages he read in two days was 28 + 20 = 48. Answer: 48 pages in two days.
Assuming that the novel has a total of $n$pages, the first day read $5/ %=005$pages, then the second day read $005/times (1-005)=001$pages. Because I read ten pages less on the second day than the first day, I read $10-001=999$. Since he had read one-third of the total pages in two days, he had read a total of $(1/3)×999 =0399$pages in two days. Therefore, Xiao Ke read a total of $0399,5 =1995$pages, or about $10$pages.
How many pages did it take to finish a novel? She was ecstatic. Reading two more pages a day than the day before meant that she only needed to read ${1+2}=1$to finish the entire novel! Hence, Xiao Xiao continued to read the novel at this speed. After a few days of hard work, she finally managed to finish reading the entire novel.