Kobayashi read one-fifth of the book on the first day, which was page 25. So the next day he should start reading from page twenty-five.
Xiao Dong read 3/5 of the book on the first day, which was 0.6 times the volume of the book. The next day, he read another 20 pages, which was equivalent to 1/5 of the entire book, which was 0.2 times the volume of the entire book. Therefore, the number of pages Little Dong had read was: The number of pages read = the volume of the book x the number of days read-the total number of pages = 06 × volume of the book × 1 - 02 × volume of the book = 02 × the volume of the book Since the total number of pages in the book did not change, the number of pages that Xiao Dong had read was 0.2 times that of the book.
A book has a page A. Reading 15 pages a day in a week is just enough. Assuming a book has page A and 15 pages a day, the number of days needed to finish the book in a week is: a ÷ 15 = (a + a) ÷ 2 = 2a / 2 + a / 2 Transferring items can be sorted out: 2a / 2 = a + a / 2 To simplify it: a = 4 Therefore, a book had four pages, and 15 pages a day was just enough to finish it in a week.
Xiao Ming read an average of 15 pages a day. He had already read 4 pages, so he still needed to read 4/15 = 02 days. Because Xiao Ming needed to watch for 5 consecutive days, he could move the days that he needed to watch forward by 5 days. 2 days + 4 days = 6 days Therefore, Little Ming needed to start from page 6, which was page 11.
If the book has x pages: I read 1/5x page on the first day I read (5/6)x pages the next day, where 5/6x means that the number of pages read on the first day accounts for 5/6 of the number of pages read on the second day. The remaining pages are x - 1/5x - (5/6)x = 66 pages According to the above equations, a set of linear equations with two variables can be listed: 1/5x + (5/6)x = 66 Solution:x = 460 Therefore, the book had 460 pages.
If a book had 180 pages and two-fifths of the total number had been read, then there would be 180 × 2/5 = 72 pages left. The next day, he read one-third of the total, so he had 180 × 3/10 = 24 pages left. Therefore, there were 72 + 24 = 106 pages left in the book.
According to the information given by the question, Little Min read 24 pages on the first day and read 3 pages less on the second day, so she read 23 pages on the second day. Since she had read page 23 the next day, Min had read page 23/times 2 = 46 after the next day. Since Min read 24 pages on the first day, she should have read $24 - 46 =-22$pages after the first day. Because Min read 24 pages on the first day and 23 pages on the second day, she should start from the remaining pages on the third day, which is $-22 + 24 =-8$pages. Therefore, Little Min should start reading from page $-8$on the third day.
Ya-chan reads a 114-page book, on average, 12 pages a day. After a few days, there are still 18 pages left. You can calculate it by the following steps: 114 pages/12 pages/day = 9 days Since Ya-chan needed 9 days to finish reading the book, he needed to read it from the 1st day to the 9th day, a total of 9 days. In these nine days, Ya-chan needed to read 12 pages a day, so in total, he would read: 12 pages/day x 9 days = 108 pages However, there were still 18 pages left, so Ya-chan had to read the remaining 18 pages every day: 18 pages/day = 1 page In other words, Ya-chan needed to read an extra page of the remaining 18 pages every day to finish the book.
In a book, Xiao Ming read page A for an average of seven days a day, so he read page 7A in total. Therefore, the number of pages to read on the eighth day should be: 8 days × a pages/day = 7a pages Adding the first 7 pages and the last 1 page gives: 8 + 7 = 15 days Because Xiao Ming had already read page 7a on the seventh day, the remaining pages should be: 15 days-page 7a = page 8a Therefore, Xiao Ming should start reading page 8a on the eighth day.