Xiaoke read a novel. On the first day, she read one-fifth of the total number of pages. On the second day, she read ten pages less than the first day. In two days, she read exactly one-third of the total number of pages.Assuming that the novel has a total of $n$pages, the first day read $5/ %=005$pages, then the second day read $005/times (1-005)=001$pages. Because I read ten pages less on the second day than the first day, I read $10-001=999$.
Since he had read one-third of the total pages in two days, he had read a total of $(1/3)×999 =0399$pages in two days.
Therefore, Xiao Ke read a total of $0399,5 =1995$pages, or about $10$pages.
Little Min read a 900-page storybook. On the first day, she read 124 pages. On the second day, she read 37 pages less than the first day. On the third day, which page should she start reading?Little Min read a 900-page storybook, and on the first day, she read 124 pages. On the second day, she read 37 pages less than the first day.
Assuming Min reads x pages the next day, the number of pages left on the second day is 900-x.
According to the first day of reading page 124, the following equation can be listed:
124 + x = 900 - x + 37
Solve the equation:
151 = 867
Therefore, the number of pages that Little Min read on the third day should be a multiple of 867. Since 900 is an even number, 867 is a multiple of 900, so Min should start reading from page 867.
Xiaoming reads a book on the first day, reading 20% of the total number of pages, the number of pages read on the second day and the number of pages read on the first day is 5:4Xiao Ming read 20% of the total number of pages on the first day of reading a book, which means that the total number of pages multiplied by 20% equals 20% of the total number of pages.
On the second day, the ratio of pages read on the first day was 5:4, which meant that half of the total pages read on the second day was 25% of the total pages.
Therefore, Xiao Ming read the total number of pages multiplied by 25% the next day, which was equal to the total number of pages multiplied by 5%.
Divide the total number of pages by 5 to get the number of pages that Xiaoming read the next day divided by 5. That is, the total number of pages divided by 5 multiplied by 40% equals the total number of pages multiplied by 10%.
Therefore, Xiao Ming read the total number of pages multiplied by 10% the next day, which was equal to the total number of pages multiplied by 5.