psc miscellaneous 2018 math solution

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The following are some common types of elementary school fun math problem solving ideas: ** 1. Sum-difference problem (Take the sum-difference relationship between two numbers as an example)** 1. Drawing line segments - Decide to use line segments to represent two numbers. Small numbers are represented by shorter line segments, and large numbers are represented by longer line segments. - For example, the sum of two numbers is 103 and the difference is 27. First, draw a long line segment that represents a larger number and a short line segment that represents a smaller number. The sum of the two numbers is 103, and the difference between the two numbers (that is, the portion of the long line segment that is more than the short line segment) is 27. - When calculating, you can first subtract the difference of 27 from the two numbers and 103. The remaining length corresponds to the length of two equal short line segments. Divide by 2 to get the smaller value, and then find the larger value according to the difference. ** 2. The relationship between factor and product (Take the relationship between two natural numbers A and B as an example)** 1. Drawing a Rectangle - Draw a rectangular shape, using length to represent A, width to represent B, the area of the rectangular shape is the product of the original two numbers. - If A was increased by 12 (i.e., the length was extended by 12), B was unchanged (the width was unchanged), and A was unchanged (the length was unchanged), and B was increased by 12 (the width was extended by 12), the rectangular graphs after the changes could be drawn. - By observing the graph, the original factors A and B were found according to the increased product and the increased factor. For example, the product increased by 72 because A increased by 12 and B did not change, so B = 72 div12; the product increased by 120 because B increased by 12 and A did not change, so A = 120 div12, and then the product of the two numbers was found. ** 3. Trapezoid-related problems (such as the relationship between the top and bottom of the ladder and the area problem)** 1. Floor plan drawing - Draw a echelon according to the meaning of the question and mark the top, bottom, and height (the exact value is unknown for the time being). - When the upper base is extended to a certain length and becomes a quadrilateral, the extended part of the upper base (such as 4 cm) and the multiple relationship between the upper and lower bases (the lower base is 1.5 times the upper base) are reflected on the map. - By observing the graph, find the relationship between the difference between the upper and lower bases (4 cm) and the multiplying relationship (1.5 - 1 = 0.5 times), and then find the values of the upper base, the lower base, and the height, and then find the area of the echelon. ** 4. Three-dimensional graphics related problems (such as cubes and cuboids)** 1. 3D Drawing - As for the problem of increasing the surface area of a cube when cut into two cuboids, draw the cube and the two cuboids after cutting according to the meaning of the question. - Mark out the part of the surface area that has increased (for example, an increase of 8 square meters). By observing the graph, you can know that the surface area of the two squares has increased. From this, you can calculate the area of each face and then the surface area of the cube. - For the problem of combining multiple cuboids into a large cuboid, draw three possible ways of combining the cuboids according to the meaning of the question. For example, using three cuboids that were 3 cm long, 2 cm wide, and 1 cm high to form a large cuboid, the possible way to join them was to form a cuboid with a length of 2×3 = 6 cm, a width of 3 cm, and a height of 1 cm. Then, the surface area of the large cuboid would be calculated according to the graph. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

I'm not sure. Maybe it wasn't popular enough or there were some legal issues.

The order of the cangue of the miscellaneous characters was: left, horizontal bending hook, horizontal, vertical hook, left, point, a total of six strokes, and the first part was wood. The novel " Mixed Flowers " is equally exciting. Everyone is welcome to click and read it!

The meaning of "miscellaneous" in "miscellaneous" was varied and not simple, but also mixed. For example," miscellaneous items " could be understood as a collection of various things. This reflected the meaning of " miscellaneous ", which meant a variety of things and a mixed collection. The novel " Mixed Flowers " is equally exciting. Everyone is welcome to click and read it!

He didn't quite understand the exact meaning of 'miscellaneous idioms'. If you wanted to ask about idioms with miscellaneous words, the most common one was " messy ", which described the arrangement of things or articles without order. If you mean something else, please clarify the content of the question. The novel " Mixed Flowers " is equally exciting. Everyone is welcome to click and read it!

Ferrocyanide could react with the reaction of the acid to form a deposit of the acid. This deposit could carry away or absorb interfering substances. It had a strong ability to remove protein, but its ability to remove color was poor. The main reaction phenomenon was the formation of the precipitations of the metal. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

There were different opinions on whether or not the reaction between the two substances occurred. One view was that silver chloride-soda would react to produce silver-white silver silver precipitations and NaCl2, and the silver-white precipitations could easily be converted to brown silver oxide-soda. The other view was that the reaction could not be carried out because the reaction between base and salt required the salt to be dissolved, while AgCl2 was difficult to dissolve. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>

There was no reaction between the saturated solution of NaCl2 and the solution of NaOx. This was because it did not meet the conditions for a metathesis reaction (forming a deposit, gas, or water). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>