Markovnikov's rule referred to the addition reaction between an electrophile such as hydrogen Halide and an unsymmetrical alkene. The hydrogen was added to the double-bond carbon atom that contained more hydrogen, and the halo was added to the double-bond carbon atom that contained less hydrogen. The chemical equation of the Marquardt addition reaction between hydrogen ClCl-H-Cl-H-Cl-Cl This reaction can be carried out at normal temperature and pressure without special reaction conditions. However, in the presence of peroxides or light, the reaction might obey the anti-Markovnikov rule, and the main reaction was $CH2 = CHCH3 + HQ → CH2ClCH2CH3 $. Read more exciting novels for free
The chemical equation for the reaction between iron dioxide (Fe2 O2) and hydrogen (H2) is: Fe2 O2 + 3H2 = heating = 2Fe2 + 3H2 O. In this reaction, iron dioxide is reduced to iron (iron), and hydrogen is oxided to water (H <anno data-annotation-id ="0000000 - 4445 - 4445-a110-a160-a1800000000"> O </anno>. The reaction phenomenon is that the reddish-brown iron dioxide becomes a black solid because the iron produced is black. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation for the heating reaction of hydrogen and oxygen is: 2H ^+ O ^= 2H ^O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation for the reaction of a halo gas (such as Cl2 <anno data-annotation-id ="cdf3c12 - 4c10 - 4c10 - 4c10 - 9c1111111124"> Cl2 </anno>) with a solution of NaClO </anno> is: The chemical equation for the reaction of Bromine and Iodine at room temperature with a solution of NaOx at room temperature is X <2>+2NaOx = NaX + NaOx + H <2> O <3>(X <3> represents either Bror I <3>). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The electropathic addition reaction between propene and bromic water did not require any special reaction conditions. The reaction formula was: CH2 = CH-CH3 + Br2 → CH2Br-CHBr-CH3. Under illumination or with a free radical initiator, a free radical substitution reaction could occur: CH2 = CH-CH3 + Br2 → CH2 = CH-CH2Br2 (the main reaction). At the same time, a free radical addition reaction could also occur: CH2 = CH-CH3 + Br2 → CH2Br-CHBr-CH3. Under appropriate conditions, the reaction of propene and Bromine to form 1,3 -dibromopropan is usually carried out in an inactive solution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the two was a physical one. There was no chemical equation. The chemical properties of the metathesis reaction between the compounds were that it only reacted with acid, base, and salt. It did not react with non-metal compounds (water was a non-metal compound). However, the hydrogen carbonate-like ion would undergo a water decomposition reaction, and the chemical equation was: [HCO3]^{-}+H_{2}O [Rightleftharpoons H_{2} CO3}+ SH ^{-}]. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When the ratio of the reaction between the two was 1:1, the chemical equation was NaHSO4 +Ba(SH)2==H2O+ NaOx + BaSO4. The reaction produced water, the precipitations of soda, and the precipitations of bis sulfuric acid. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction mechanism between alkyls and halos was a substitution reaction of free radical. In the reaction, the halo (such as pure chorine, pure bromine, and not chorine water or bromine water) under the conditions of light/heat/free radical initiator, X-X was split into two X-free radical, X -and the HX-H on the alkyls formed hydrogen halo, and the alkyls left the alkyls free radical, which then reacted with X-X to form X -, and the cycle reaction could continue. The reaction between an aromatic compound (such as alkyne and alkyne) and a hydrogen atom was mainly an addition reaction. The double bond in an aromatic compound was a sigma-bond and a pi-bond. The pi-bond was more unstable and easy to break. The double bond opened to become a single bond, and the broken small half bond formed a covalent-bond with the hydrogen atom. In addition, the addition reaction of the hydrogen atom with the unsatured carbon could also be carried out. Aromatic compounds could only be substituted with a catalyst (such as iron trihalide, aluminum trihalide, iron powder, etc.), except for very active compounds (such as aromatic amine, vitamins, etc.). Fatty acid could only be substituted with a catalyst of red phosphorus, which generally produced an alpha substituted product. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Additional reaction: - The addition reaction of ethene and Bromine: <<CH2 = CH2 + Br2> - The addition reaction of ethene and hydrogen bromidate was as follows: <CH2 = CH2> - Under certain conditions, addition reactions could also occur between ethene, hydrogen, and water. Since the chemical properties of ethyne (carbon-carbon triple bond) were similar to that of alkene (carbon-carbon double bond), similar addition reactions could also occur. - The aromatic ring can undergo an addition reaction with hydrogen (in the presence of a catalyst such as Ni). - Aldol groups can undergo a reduction reaction (addition reaction), such as: <anno data-annotation-id ="00000000 - 4c00 - 4c00 - 8c00 - 9c00 - 9c000b000000"> CH3CH20H </anno>. Substitution reaction: - The substitution reaction between methane and Cl2: CH4 + Cl2. - The substitution reaction of the aromatic ring: For example, the substitution reaction with the aromatic group using FeBr3 as a catalyst; the nitration reaction with the aromatic group using concentrated sulfuric acid under heating conditions (the hydrogen on the aromatic ring is replaced by the nitrogen group). - The substitution reaction of the halated carbon was as follows: <<CH3CH2Br2>+<NaBr2>>. - The substitution reaction of alcohol: <CH3CH20H>+<br>> longrightarrow <CH3CH2br>+<H2O>> - The ester's cleavage reaction (which can be seen as a substitution reaction):<CH3COOCH2CH3 + H2O> <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There were different views on the reaction of hydrogen and alcohol. One view was that the reaction between alcohol (CH3CH20H) and hydrogen peroxid (H2O2) could produce esh (CH3Cho2) and water (2H2O), that is, CH3CH20H + H2O2 = CH3Cho2 + 2H2O. The other view was that there would be no change after mixing the two, and there would be no chemical reaction, especially when the hydrogen peroxid was medical grade. If the hydrogen peroxid was 100% concentrated, it would explode directly. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Under normal circumstances, the reaction between the two could not be carried out directly. Because the lone pair of electrons of the oxygen of the alcoholic group was coupled with the aromatic ring, the reaction activity was very weak, and it could not be used to catalyze the ester reaction with the acid. To synthesize the ester, the reaction of an acid acid or an acid ether with the ether was usually done. For example, the reaction between the ether and the ether was: C6H50H +(CH3CO) 2O = CH3COOC6H5 + CH3COON. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>