The probability table of three dice dropping points
When three dice were rolled: 1. ** Total number of situations **: Each die has 6 situations, so there are a total of {6×6×6 = 216}. 2. ** The probability of big (the sum of the points is 11 - 1/8)**: There are three kinds of big situations (4, 5, 6) for each die. There are a total of 3 ×3×3 = 27, so the probability of big appearing is 1/8. 3. ** The probability of small (3 - 10 points) appearing **: Same as the probability of large appearing, it is 1/8. 4. ** The probability of a leopard appearing (the three dice have the same number, namely 111, 222, 333, 444, 555, 666)**: There are six situations, so the probability is <1>(6/216 = 1/36>). Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
2 dice probability
For two dice, there were several possibilities: 1. ** Single number probability **: - Each die had six sides, and the numbers were 1, 2, 3, 4, 5, and 6. When a die is rolled, the probability of each number appearing is 1/6. When two dice were thrown, for example, the probability of both dice rolling a 1 was 1/6. Therefore, the probability of both dice rolling a 1 (the combination of 1 and 1) was (1/6)×(1/6)=1/36. Similarly, any particular combination of numbers (such as 3 and 5) has a probability of 1/36. 2. ** Point sum probability **: - The sum of the points was 2 (1 + 1), and there was only one possibility. The probability was (1/6)×(1/6)=1/36. - The sum of the points is 3 (1+2 or 2 + 1). There are two possibilities, and the probability is 2/36. - The sum of the points was 4 (1+3, 2+2, 3+1). There were 3 possibilities, and the probability was 3/36. - The sum of the points is 5 (1+4, 2+3, 3+2, 4+1). There are 4 possibilities, and the probability is 4/36. 3. ** Dice size probability (1 - 6 is small, 7 - 12 is big)**: - There were a total of 6x6 = 36 combinations of the two dice. Among them, there were 15 situations where the sum of points was 1 - 6 (small), and 21 situations where the sum of points was 7 - 12 (large). However, since it was impossible for two dice to have a point, the probability of a small point appearing was 5/11 (about 45.45%), and the probability of a big point appearing was 6/11 (about 54.55%). 4. ** The probability that the sum of the two dice numbers is odd (assuming the first die numbers are 1, 2, 3, 3, 5, 6, and the second die numbers are 1, 2, 4, 4, 5, 6)**: - For the first die, the probability of an odd number appearing was 4/6 = 2/3, and the probability of an even number appearing was 1/3. For the second die, the probability of an odd number appearing was 2/6 = 1/3, and the probability of an even number appearing was 2/3. To get the odd sum, there are two situations: if the first die is odd and the second die is even, the probability is 2/3×2/3 = 4/9; if the first die is even and the second die is odd, the probability is 1/3×1/3 = 1/9. Therefore, the total probability was 4/9+1/9 = 5/9. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
The probability of dice rolling
Rolling dice was a classic example of probability. For a single standard die, because it had six sides, each marked with the six numbers 1, 2, 3, 4, 5, and 6, the chances of each number appearing were equal. Therefore, when throwing a single die, the probability of any number appearing in the result was 1/6. When there were multiple dice involved, the probability calculation would be more complicated. Take two dice as an example, if you consider the size of the dice,(1 - 6 is small, 7 - 12 is big), because there are a total of 6×6 = 36 combinations of the number of points on the two dice. Among them, there are 15 cases where the sum is 1 - 6 (small), and there are 21 cases where the sum is 7 - 12 (big). However, since it is impossible for the two dice to appear, the actual probability of small appearing is 5/11 (about 45.45%), and the probability of big appearing is 6/11 (about 54.55%). If there were three dice, each die would have six situations, and there would be a total of 6x6x6 = 216 combinations. For example, if one calculated the probability of rolling a big die, there would be three kinds of big situations (namely, 4, 5, and 6 points) for each die. There were a total of 3×3×3 = 27 kinds. Therefore, the probability of a big situation appearing was 27 × 216 = 1/8. Similarly, the probability of a small situation appearing was also 1/8. The probability of a leopard appearing (three dice with the same number of points, such as 111, 222, etc.) was 6 × 216 = 1/36. In addition, in theory, if the structure of the die was uneven, for example, the dots were hollowed out, and the six small round pits on the six dots were lighter than the one on the opposite side, then the probability of the six appearing would be greater than the one. However, in the ideal standard die situation, the probability of each number was 1/6. At the same time, there were many other situations in the probability calculation of dice rolling, such as the probability calculation of the sum of two dice numbers being odd, which could be solved by different probability methods (such as the step-by-step probability calculation method in junior high school or the combination knowledge method in high school). Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
dice-rolling probability
The condition probability refers to the probability of event A happening under the condition that event B has already happened. It is recorded as P(A| B)。The following is an example analysis of the probability of dice rolling. Suppose we have two dice. Event A is that the sum of the two dice is 8, and Event B is that the first die rolls a 3. First, calculate the probability of event A without any conditions. There were a total of 6×6 = 36 possibilities for the outcome of the two dice. There are five cases where the sum of points is 8:(2,6),(3,5),(4,4),(5,3), and (6,2), so P(A)=5/36. Then, the probability of event B is calculated. The probability of the first die rolling a 3 is 1/6, which is P(B)=1/6. The only situation where both events A and B occur at the same time is (3,5), so P(A Empyrean B)=1/36. According to the formula P(A| B)=P(A Empyrean B)/P(B). Under the condition that the first die rolls a 3, the probability of the sum of the two dice points being 8 is P(A| B)=(1/36)/(1/6)=1/6。 For example, Event C was the difference between the two dice being 1, and Event D was the second die rolling a 4. Similarly, P(C) was first found. There were 10 cases where the difference between the points was 1:(1,2),(2,3),(3,4),(4,5),(5,6),(2,1),(3,2),(4,3),(5,4), and (6,5), so P(C)=10/36. The probability of event D is P(D)=1/6. There are two cases where events C and D occur at the same time: (3,4) and (5,4), so P(C Empyrean D)=2/36. Under the condition that the second die rolls a 4, the probability of the difference between the two dice being 1 is P(C| D)=(2/36)/(1/6)=1/3。 In short, when calculating the conditioned probability of rolling the dice, the key was to clarify the relationship between the events, separately calculate the probability of the event occurring alone and the probability of them occurring at the same time, and then use the conditioned probability formula to calculate. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
The law of the probability of rolling the dice
In the case of two dice, according to probability theory, the probability of each sum was different. There was only one possibility for the sum to be 2 (1 + 1), and there were six possibilities for the sum to be 7 (1 + 6, 2 + 5, 3 + 4, 4 + 3, 5 + 2, 6 + 1). Therefore, the possibility of the sum being 7 was the highest. The possibility of the sum being 2 and 12 (6 + 6) was the lowest, because there was only one combination that could get these two sums. In a large number of dice throwing experiments, the number of times the sum was 7 was the most, and the number of times the sum was 2 and 12 was the least. For the case of three dice, the total number of points ranged from 3 to 18. The closer to the two sides, the lower the probability of appearing. The situation with the highest number and probability should appear in the middle position, such as 9, 10, 11, and 12. The probability of these points appearing could be calculated separately. When calculating, it was necessary to consider the situation where the three points in the point combination were different and the same points existed. For example, when calculating the probability that the sum of the points is 9,(1;2;6),(1;3;5), and (2;3;4) are the three points that are different,(2;2;5),(3;3;3), and (4;4, 1) are the same points, and when they are all different, the three points need to be completely arranged. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
The sum of the dice, the probability of the combination
When calculating the probability of the sum of the two dice points, one could use a combination method. For a single die, the probability of each side appearing was 1/6. When considering the sum of the two dice points: - If the sum of the points was 2, and there was only a combination of 1 + 1, the probability was (1/6)×(1/6)=1/36. - If the sum of the points is 3, there are two combinations of 1 + 2 and 2 + 1, so the probability is 2/36. - If the sum of the points was 4, there were 3 combinations of 1 + 3, 2 + 2, and 3 + 1. The probability was 3/36. - If the sum of the points was 5, there were four combinations of 1 + 4, 2 + 3, 3 + 2, and 4 + 1. The probability was 4/36. By analogy, the total combination probability could be calculated by analyzing the combination of different numbers and the probability of the corresponding number appearing on each die in each combination (1/6). For example, in the case of two dice, there were a total of 6×6 = 36 possible combinations. By analyzing the number of combinations corresponding to the sum of different points, the corresponding probability could be obtained. If there were multiple dice, the calculation would be more complicated. It was necessary to consider the possible number of points and the variety of combinations that could appear on each die. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
The probability of two people rolling the dice to 6 first
1. For a single die, the probability of rolling a 6 is 1/6. - Consider the case where two people roll the dice to get a 6 first. This can be calculated by calculating the probability that neither of them rolled a 6 and then deducting this probability from 1. - Let the probability of the first person not rolling a 6 on the first roll of the die be <p>(P1 = 5/6>), and the probability of the second person not rolling a 6 on the first roll of the die be <p>(P2 = 5/6>). - Then the probability of both players failing to roll a 6 on the first try is [P = P1> times P2 =(5/6)> times(5/6) = 25/36]. - Therefore, the probability of one of the two people rolling a 6 first is 1 - 25/36 = 11/36. Hurry up and click on the link below to return to the super classic "Lord of the Mysteries"!
Dropping out and dropping out
"Drop out" is a wrong usage. There is no such word. The literal meaning of " drop out " was to stop going to school halfway. It referred to the behavior of a student dropping out of school halfway because he did not complete the required studies. For example, in some cases, some people dropped out of junior high school and faced many difficulties and challenges in their lives. There were also 15-year-old young men who dropped out of school to repair cars, lying on the ground in the summer heat of more than 40 degrees, regretting not going to school. There were also dropouts in Thailand, and the government was working hard to promote the "Thailand Zero Drop Out" policy. There were currently 394,039 children and youths aged 6 - 18 outside the compulsory education system. The novel " The Lost Seventeen " is equally exciting. Everyone is welcome to read it!
Points for attention in table tennis competition
The points to note for table tennis matches were as follows: - ** Before the competition **: - It is strictly prohibited to participate in the competition when sick. - It was not advisable to play basketball immediately after a meal. - She had to wear professional table tennis shoes. - Do warm-up activities before playing, such as skipping rope, jogging until you sweat slightly, and stretching your joints and ligaments. - Wear protective gear according to your condition. - Don't eat too much, just eat a little. - In a slightly formal match, the opponent's racket had to be checked before the match. - Pay attention to the clothing requirements. Wear dark sportswear. No white or light-colored sportswear. - Arrive at the competition venue to check the match list, and sign in at the sign-in area and the referee on the competition stage in time. After signing, wait outside the venue and listen to the referee's call. No one is allowed to enter at other times. - ** In the competition **: - There must be multiple sets of tactical routines, such as a long serve to prepare for the attack, a short backhand to prepare for the ball, a long serve to prepare for a stalemate, etc., and each set of serve must be prepared in advance for the tactical return of serve. - He had to adjust his mentality, respect the opponent and the rules, focus on the game, not be proud of scoring or discouraged by losing points, and not give up until the ball landed. - If the tactics did not score, they should be adjusted in time. After the game, the reasons for the loss of points should be summarized, such as the quality of the serve, rotation, landing points, etc. - Possess the ability to read the game, observe the opponent's strengths and weaknesses, avoid the opponent's strengths during the game, and send the ball and landing point that makes the opponent uncomfortable. - Don't hesitate in actual combat and attack decisively. - He should avoid being too impatient, making mistakes or making wrong judgments on the rotation, which would lead to a calm response when the ball was high. He should watch the opponent's movements and prepare to defend and receive the ball before looking for an opportunity to counterattack. - You must dare to attack when you have the chance to take the ball and be prepared to attack continuously. - Understand the advantages and disadvantages of your own techniques, and formulate tactics according to your own situation, such as using more short balls to hit the ball, occasionally stealing long attacks, etc. - When receiving a serve, you should first predict the landing point, predict the length of the ball, spin up and down, and then move your pace. You should make a firm move and not habitually retreat from the stage. - Pay attention to the use of the basic skills of stalemate (horizontal, straight left and right push block and rub the ball), usually practice receiving and stalemate. - Control the rhythm of the game, adjust your mentality, and grasp the timing of the pause. - Obey the referee's decision. If there is any objection, look for the head judge to resolve it. To avoid conflict, maintain the discipline of the competition, and not make a loud noise. - The winner of the first round should not be too far away so as not to delay the next round. Those who were eliminated should go to the registration area to collect the deposit. While watching the Olympics, you can also read the wonderful novels related to the Olympics!
Similar to super geno points, killing monsters and dropping beast souls
The following novels had settings similar to killing monsters to drop items (such as beast souls): - In Super Gene, there was a setting that said,"Kill a sacred-blood creature, black beetle, and obtain its beast soul. Eat the flesh of a sacred-blood black beetle to gain zero to ten sacred geno points randomly." - In some novels that were set in the world of mysterious shelters, humans faced countless powerful creatures. When they killed sacred-blood creatures and other monsters, they would receive corresponding rewards, such as beast souls and gene points. For example,"Primitive creature green-scaled beast killed. No beast soul gained. Eat the flesh of a primitive green-scaled beast to gain zero to ten primitive geno points." - Although "The 4.6 Billion Ensemble of Evolution" mainly focused on biological evolution, the protagonist continued to develop in a world full of danger. There were also plots that were similar to obtaining elements from dangerous creatures or environments to improve themselves. - In the early stages of "Gene Traitor", the main character was in a sci-fi version of a low-end game. During the exploration process, there would be similar scenes of killing monsters to obtain resources or special abilities. After all, the main character's genes were reorganized and modified to enter the starry sky. This growth process might involve killing monsters to obtain resources that were useful for genetic modification.
The difference between dropping out and dropping out
Both dropping out and dropping out meant that they had not completed their studies, but there were certain differences. Incomplete studies mainly referred to the state of studying in school but not graduating or not graduating. It was a process of learning. For example, two years of university meant that they had studied in school, but they did not meet the graduation requirements. In the modern context, university students would receive an associate's certificate, indicating that they had studied at a university but had not completed their studies to obtain a diploma. Dropping out of school referred to stopping school halfway, emphasizing the interruption of the learning process. It could be due to various reasons, such as family difficulties, personal choices, etc., who had to drop out of school because their families could not afford the cost of accommodation, or some young people in the countryside who dropped out of university because they wanted to change the world. The novel " The Lost Seventeen " is equally exciting. Everyone is welcome to read it!