硫酸亚铁铵的制备一般从废铁屑开始,先将铁屑经碱溶液洗净之后,用过量硫酸溶解,反应方程式为\(Fe + H_{2}SO_{4}=FeSO_{4}+H_{2}\uparrow\),这一步会观察到铁屑逐渐溶解,溶液中有气泡产生。 然后加入稍过量硫酸铵饱和溶液,反应方程式为\(FeSO_{4}+(NH_{4})_{2}SO_{4}+6H_{2}O = Fe(NH_{4})_{2}(SO_{4})_{2}\cdot6H_{2}O\),在小火下蒸发溶剂直到晶膜出现,这一过程溶液逐渐变得浓稠,最后停火利用余热蒸发溶剂。过滤后用少量乙醇洗涤,得到硫酸亚铁铵晶体,产物为浅蓝绿色结晶或粉末。 点击前往免费阅读更多精彩小说
The nature of the reaction depended on the type of reaction. For example, in some reactions, it was actually a metathesis reaction, which would form a deposit. In the reaction related to oxygen, due to the reduction of the iron, the iron will be oxided in the presence of the hydrogen to form the hydrogen of the iron. Under acidic conditions, it will be oxided by oxygen to form the hydrogen of the iron and water. Ferrous ions would also undergo a decomposition reaction in water, combining with the water's free radical ions to form a deposit of Ferrous Oxides. However, this decomposition reaction was irreversible. In a solution with a strong acid, a high concentration of hydrogen ions would suppress the decomposition reaction of the Ferrous Ion. In addition, Ferrous Sulphate was an acidic substance, which would neutralize with an acidic substance. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Copper could not undergo a substitution reaction with the metal. Because in the metal activity sequence table, the copper bar was weaker than iron, its reduction was weaker than iron, and the conductivity of the iron ion in the iron was weaker than that of the copper ion, so the two would not undergo a replacement reaction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction of iron and sulfuric acid could not directly produce iron dioxide. Nitric acid has a strong oxidisation. When iron and sulfuric acid react, the sulfuric acid will catalyze iron into iron ions (Fe3) instead of iron ions (Fe2). The reaction equation is as follows: - The reaction of dilute sulfuric acid with a small amount of iron: Fe4 HNO2 (dilute) = Fe3 (NO2) 2 + NO2 + 2H2 O. - The reaction of dilute sulfuric acid with excess iron: 3Fe8HNO2 (dilute) = 3Fe2 (NO2) 2 + 2NO2 2 + 4H <2> O (but the iron ions formed here are easily further oxided to iron ions by sulfuric acid). The preparation of FeOx required the reaction of a solution of a Ferrous Salt (such as a solution of Ferrous Sulphate) with a solution of an Alkaline (such as a solution of NaOx). The reaction equation was: FeSO2 + 2NaOx = FeOx + NaOx. At the same time, in order to prevent the corrosion of the metal, the reaction usually needed to be carried out in an oxygen free environment. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between copper and copper is: Mn + CuSO2 = Mn + CuSO2 + Cu2. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation of the reaction between calcium hydrogen and potassium chlorideis: 2NHCl2 + CaCl2 + 2NHCl2 + 2HCl2 O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction equation between BeOx and NaOx was: Be(Ox) 2 + 2NaOx = Na 2 BeO 2 + 2H 2 O. Besium hydrogen was an amphoric hydrogen dioxide, which could react with both strong acid and strong base, so it could react with the above reaction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The preparation of ferrate mainly has the following reaction formula and its meaning: 1. ** wet preparation ** - The reaction formula is [2FeO4 ^{2-}+3ClO ^-+4OH^- = 2FeO4 ^{2 -}+3ClO ^-+5H2O']. - This reaction formula shows that under basic conditions, the reduction reaction of iron (Fe(OH)_3) and the reduction reaction of iron (ClO^-) occurs. The iron element in the iron dioxide was oxided, increasing from the valency of [+3] to the valency of [+6], forming ferrate ions [(FeO4 ^{2 -})], while the Cl-element in the Cl-ion was reduced from the valency of [+1] to the valency of [-1], forming Cl-ion [(Cl4-)]. At the same time, the reaction required the participation of the hydrogen ion, which formed water. 2. ** Dry preparation ** - The reaction formula is [2FeSO4 + 6Na2O2 = 2Na2FeO4 + 2Na2O +2Na2SO4 + O2]. - In this reaction, the iron element in FeSO4 is dissolved in Na2SO2. Oxidation of ((Na2O2), Iron increases from +2 to +6 to form ferrate.((Na2FeO4)); part of the oxygen element in the sulfur dioxide decreased from the valency of <-1> to the valency of <-2>, and the other part of the oxygen element increased from the valency of <-1> to the valency of <0> to form oxygen <((O2)>, and at the same time, it formed sulfur dioxide <((Na2O)> and sulfur dioxide <(Na2SO4)>. 3. ** Preparing Ferrate from Ferrate ** - In the industry, the first step was to produce the solution of ferrate, and then at a low temperature, a certain amount of potassium ferrate could be added to the solution of ferrate to produce the solution of ferrate. The reaction principle was based on the double decomposition reaction. The ion reaction was 4FeO4 ^{2 -}+10H2O = 4Fe0H (Ox) 3 (colloid)+3O21 + 8Kh21, and the chemical equation was 4K2FeO4 + 10H2O = 4Fe0H (Ox) 3 (colloid)+3O21 + 8Kh21). This reaction showed that when the ferrate reacted with water, the ferrate ions would be digested to form iron colloid, oxygen, and hydrogen ions, reflecting the chemical properties of the ferrate in water. In this reaction, the valency of the iron element did not change. There was also the reaction of dry method of producing ferrate,[2FeClO +4NaOx = 2Na2FeO4 + 5H2O +3NaClO]. This reaction indicated that iron was oxified by hypochlor under an acidic condition to produce ferrate, chlor, and water. This was a way to produce ferrate and then ferrate. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
According to the available information, the reaction between hydrogen hydrogen and molten carbonates would produce sulfur, carbon dioxide, and water, but the exact reaction equation had not been found. From the perspective of the phenomenon, hydrogen hydrogen was an acidic gas. When it reacted with molten carbonates, it produced carbon dioxide. This might be because the hydrogen in hydrogen hydrogen reacted with the carbonates in the carbonates, thus producing carbon dioxide gas. However, because the sulfur and hydrogen elements in hydrogen hydrogen dioxide were not effectively utilized in this reaction, the sulfur and carbon dioxide produced by the reaction were not good for environmental friendliness and green development. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The double decomposition reaction between aluminum and sulfur could produce aluminum sulfuric acid, which was called NaAlSO4·12H2O. The reaction formula was: the reaction between aluminum and sulfur could produce aluminum sulfuric acid, which was called aluminum sulfuric acid. It was a colorless cubic octagonal crystal or white crystalline powder with a density of 1.6754 g/cubic centimeter. It was easily dissolved in water but not in alcohol. It was easily weathered in the air and lost 12 crystals of water when heated to become an anhydrite. It was widely used as a buffer, neutralizing agent, and solidifying agent in the food industry. It could also be used for refining sugar, as a raw material for swelling agents, and as a water purifying agent. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
In the process of preparing fruit vinegar, there were two corresponding reactions. When oxygen and sugar were sufficient, the vinegar bacteria would break down the sugar in the grape juice into vinegar. Although the reaction formula for this process did not give a specific formula, the principle was that the vinegar bacteria used sugar to synthesize vinegar. When sugar is lacking, the reaction is This reaction formula indicates that the acetoid acid bacteria can convert the alcohol into alcohol when there is insufficient oxygen and sugar source. The first step was to convert the reagent from (<anno data-annotation-id ="0000000 - 4110 - 4000 - 4000 - 8000 - 80000000000"> C </anno> H <anno data-annotation-id ="0000000 - 4000 - 4000 - 8000 - 80000000000"> Ox </anno>) to jumped from the reagent to the reagent, and then the reagent from the reagent to the reagent, and at the same time, water was formed. This process reflected the material transformation relationship in the process of fermentation under specific conditions, namely the conversion process from alcohol to the reagent. This conversion process required the participation of oxygen and was the result of the metabolism of the vinegar bacteria. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>