The chemical equation of the reaction between meta-aluminum aluminum (NaAlO <2>) and aluminum (Al2 (SO2)<2> is: 6NaAlO <2>+ Al2 (SO2)<2>+12H <2> O = 8Al2 (NO3)<2>+3Na <2> SO2 <2>, and the ion equation is: Al3 <2>+3AlO2 <2>+6H <2> O = 4Al2 (NO3)<2>. Read more exciting novels for free
There was no reaction between aluminum ions (Al3 +) and Na2SO4. In common chemical reactions, aluminum ions and sulfuric acid ions could coexist in solution, and there would be no oxidoreduction reaction, metathesis reaction, etc., so there was no reaction equation. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation for the reaction of aluminum phosphorous acid (AlPo) with concentrated sulfuric acid is: AlPo +3HQ = AlCl2 + H Po. The reaction phenomenon was that the solid aluminum phosphorous acid gradually dissolved. Since the aluminum chloride-formed (AlClCl2) and phosphorous acid (H3PO4) were both water-dissolved, the solid of aluminum phosphorous acid gradually decreased until it was completely dissolved as the reaction progressed. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When a solution of a solution of The first was: <<Al3 +>+3AH^{->><Al3 +>>(Ox)_{3}>. At this time, a white deposit could be observed in the solution. If he continued to add the solution of the solution of the NaH solution, the reaction would occur. The white precipitations that were produced before would gradually disappear. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. Reaction of Magnesium with Acid: [(Mn +2ClCl2 = Mn, Mn)] 2. Reaction of sulfuric acid with lithium: \(Mn + H ^SO2 = Mn ^SO2 + H ^^) 3. Reaction of hydrogen and sulfuric acid: [(Mn +2ClCl2 = Mn Cl2 + H ^^] 4. Reaction of sulfuric acid with lithium: [(Mn + H ^SO2 = Mn ^SO2 + H ^^] 5. Reaction of iron and sulfuric acid: [(Fe2 + 2HQ = FeCl2 + H2 ^] 6. Reaction of iron and sulfuric acid: <br><br></br>><br><br>>/br>> 7. Reaction of aluminum with sulfuric acid: \(2AI +6HC1 = 2AlCl +3H ^^\) 8. Reaction of aluminum with sulfuric acid: \(2AI +3H ^SO = AI ^(SO)+3H ^^) <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction equation of aluminum magnesite and sulfuric acid: Al2 Mn (Ox) CO2·4H2 O+18HQ = 2AlCl2 +6MgCl2 + CO2 ^+21H2 O. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Since the two didn't react, it wouldn't turn black. When aluminum meets acid and strong base, it will react, while the sulfuric acid is neutral and does not react with aluminum. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
You might want to ask about the reaction of meta-aluminum aluminum with sulfuric acid. When the amount of sulfuric acid is insufficient, the reaction equation is: NaAlO <2>+ HNO <2>+ H <2> O = AI (OR)+ NaNO <2>, which means that white precipitations are produced when the sulfuric acid is added. When the amount of sulfuric acid is sufficient, the reaction equation is: NaAlO <2> O + HNO <2>+ H <2> O = AI (OR)+ NaNO <2>, AI (OR)+3HNO <2>= AI (NO <2>)+3H <2> O, which means that white precipitations are produced first, and then the white precipitations disappear after continuous dripping and shaking the test tube. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
You might want to ask about the reaction between meta-aluminum aluminum and sulfuric acid. When the amount of sulfuric acid is insufficient, the reaction equation is NaAlO <2>+ HNO <2>+ H <2> O = AI (OR)+ NaNO <2>. At this time, the addition of sulfuric acid will produce a white deposit, which is because of the formation of aluminum trioxid. When the amount of sulfuric acid was sufficient, the reaction was divided into two steps. The first step was to form aluminum trioxid as described above. The second step was to react with the reaction of AI (Ox)+3HNO = AI (NO)+3H <2> O. Continue to add the sulfuric acid and shake the test tube, and the white deposit will disappear. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between aluminum and sulfuric acid would not produce nitrogen. When aluminum reacted with concentrated sulfuric acid, it would form a dense layer of oxygen film on the surface, which would be passive and prevent the reaction from proceeding further. When the sulfuric acid was diluted, the reaction equation was: AI +4HNO3 = AI (NO3)3+NO → +2H2O. When the sulfuric acid was concentrated, the reaction equation was: AI +6HNO3 = heating = AI (NO3)3+ 3NO2 → +3H2O. It could be seen that the reaction product was nitrogen dioxide or nitrogen dioxide, not nitrogen. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There is no such substance as lead and aluminum. You may want to ask about the reaction of meta-aluminum and sulfuric acid. When the amount of sulfuric acid is insufficient, the reaction equation is: NaAlO <2>+ HNO <2>+ H <2> O = AI (OR)+ NaNO <2>, which is a white deposit when the sulfuric acid is added. When the amount of sulfuric acid was sufficient, the reaction equation was: NaAlO <2>+4HNO <3>= NaNO <3>+ AI (NO <3>)<3>+2H <2> O. The phenomenon was that the white deposit disappeared when the sulfuric acid was added and shaken. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>