The chemical equation of the reaction between meta-aluminum aluminum (NaAlO <2>) and aluminum (Al2 (SO2)<2> is: 6NaAlO <2>+ Al2 (SO2)<2>+12H <2> O = 8Al2 (NO3)<2>+3Na <2> SO2 <2>, and the ion equation is: Al3 <2>+3AlO2 <2>+6H <2> O = 4Al2 (NO3)<2>. Read more exciting novels for free
The chemical equation of the reaction between aluminum and sulfuric acid is [2AI +6HQ = 2AlCl3 + 3H2]. At the beginning of the reaction, there was a layer of oxygen film on the surface of the aluminum strip, so there were fewer bubbles. As the reaction progressed, more and more heat was released, and more and more bubbles were produced. Later, the concentration of the sulfuric acid decreased, and the reaction rate decreased, so the bubble production rate slowed down, and the bubbles became fewer and fewer. Finally, the sulfuric acid was exhausted. In this reaction, aluminum showed its reducing properties. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There was no reaction between aluminum ions (Al3 +) and Na2SO4. In common chemical reactions, aluminum ions and sulfuric acid ions could coexist in solution, and there would be no oxidoreduction reaction, metathesis reaction, etc., so there was no reaction equation. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between aluminum phosphorous acid (AlPo) and sulfuric acid (HQ) occurs. This was a typical alkali-base reaction. As the salt of a weak acid (phosphorous acid), aluminum phosphorus was decomposed by sulfuric acid, which formed aluminum chloride-phosphorous acid (AlClCl2) and phosphorous acid (H PO2). The chemical equation was: AlPO2 + 3HQ → AlCl2 + H PO2. In actual experiments, reaction conditions such as concentration and temperature would affect the reaction rate and yield. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The chemical equation for the reaction of aluminum phosphorous acid (AlPo) with concentrated sulfuric acid is: AlPo +3HQ = AlCl2 + H Po. The reaction phenomenon was that the solid aluminum phosphorous acid gradually dissolved. Since the aluminum chloride-formed (AlClCl2) and phosphorous acid (H3PO4) were both water-dissolved, the solid of aluminum phosphorous acid gradually decreased until it was completely dissolved as the reaction progressed. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When a solution of a solution of The first was: <<Al3 +>+3AH^{->><Al3 +>>(Ox)_{3}>. At this time, a white deposit could be observed in the solution. If he continued to add the solution of the solution of the NaH solution, the reaction would occur. The white precipitations that were produced before would gradually disappear. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When aluminum comes into contact with concentrated sulfuric acid, it will undergo a passive phenomenon, which is to form a dense layer of an oxygen film on the surface of the aluminum to prevent the reaction from proceeding further. If water was added to this system, the concentrated sulfuric acid would be diluted into diluted sulfuric acid. At this time, aluminum would react with the diluted sulfuric acid. The chemical equation was 2AI +3H ^SO = AI ^(SO)^+3H ^^. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There was no reaction when the solution of Na <2> SO2 <3> and aluminum <2> sulfateAl2 <3>(SO2 <3>)<3> was mixed. Because both of them were salt, if they reacted, they needed to meet the conditions of metathesis reaction, that is, there would be precipitations, gas, or water, but these substances would not be formed after mixing, so there was no reaction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There was no reaction between Na <2> SO2 <3> and aluminum <2> sulfate2 <3>(SO2 <3>). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. Reaction of Magnesium with Acid: [(Mn +2ClCl2 = Mn, Mn)] 2. Reaction of sulfuric acid with lithium: \(Mn + H ^SO2 = Mn ^SO2 + H ^^) 3. Reaction of hydrogen and sulfuric acid: [(Mn +2ClCl2 = Mn Cl2 + H ^^] 4. Reaction of sulfuric acid with lithium: [(Mn + H ^SO2 = Mn ^SO2 + H ^^] 5. Reaction of iron and sulfuric acid: [(Fe2 + 2HQ = FeCl2 + H2 ^] 6. Reaction of iron and sulfuric acid: <br><br></br>><br><br>>/br>> 7. Reaction of aluminum with sulfuric acid: \(2AI +6HC1 = 2AlCl +3H ^^\) 8. Reaction of aluminum with sulfuric acid: \(2AI +3H ^SO = AI ^(SO)+3H ^^) <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There is no such substance as lead and aluminum. You may want to ask about the reaction of meta-aluminum and sulfuric acid. When the amount of sulfuric acid is insufficient, the reaction equation is: NaAlO <2>+ HNO <2>+ H <2> O = AI (OR)+ NaNO <2>, which is a white deposit when the sulfuric acid is added. When the amount of sulfuric acid was sufficient, the reaction equation was: NaAlO <2>+4HNO <3>= NaNO <3>+ AI (NO <3>)<3>+2H <2> O. The phenomenon was that the white deposit disappeared when the sulfuric acid was added and shaken. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>