When the newly produced chloride-water reacted with the solution of sulfuric acid, it would turn red first. The reason was that the sulfuric acid in the chloride-water had a neutralizing reaction with the solution of sulfuric acid. As the reaction went on, the solution would be consumed, and the basicity of the solution would weaken. The sulfuric acid would turn red when it met the base. When the basicity weakened, the red color would become lighter or even disappear. However, at this time, the chloride-water could also react with other substances, such as the reaction with the solution of iron salt (the newly produced chloride-water could catalyze the iron ions), so it could still be used. When the newly prepared chloride-water reacted with litmus test solution, it would turn red first because the chloride-water contained H, which was acidic. After the solution turned red, it would fade due to the bleachability of HClO. During the reddening process, the chloride-water was not completely consumed, so it could still react with other substances (such as some reducing substances) and could still be used. Read more exciting novels for free
新制氯水与硝酸银反应时,首先氯水中存在反应\(Cl_{2}+H_{2}O = HCl + HClO\),生成的\(HCl\)与\(AgNO_{3}\)发生反应\(HCl+AgNO_{3}=AgCl\downarrow +HNO_{3}\),将两个反应合并为\(AgNO_{3}+Cl_{2}+H_{2}O = AgCl\downarrow +HNO_{3}+HClO\)。所以反应的结论是有白色沉淀\(AgCl\)生成,同时生成了\(HClO\)和\(HNO_{3}\)。并且由于反应使溶液中\(Cl^{-}\)浓度降低,会引起次氯酸的分解(平衡移动),反应\(2HClO\rightleftharpoons HCl + O_{2}\uparrow\)平衡向右移动,实际现象是一定会有气泡产生。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>
The production of chloride-based water was obtained by filling the water with Cl2 until it was saturated. When the chloride-based water was filled with Cl2, a part of the chloride-based water would react with the water. The chemical equation was Cl2 + H2O = HQ + HClO. This reaction was an oxido-reduction reaction. In this reaction, part of the Cl2 atom was reduced to the-1-valency Cl2 in the Cl2 solution, and part of it was oxided to the +1-valency Cl2 in the HClO solution. Water (H2O) was neither an oxidiser nor a reducing agent. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Most of the compounds with the structure of a hydrogen radical and an sp2 hybrid carbon atom (that is, the carbon atom on the carbon-carbon double bond) could undergo a color reaction with the water solution of FeCl3. The alcoholic group was directly connected to the aromatic ring, which was equivalent to a dilute alcohol structure, so there was also this reaction. The colors of different compounds were different. For example, the colors of the compounds of the two compounds were blue-purple, the colors of the compounds of the two compounds were green, and the colors of the compounds of the two compounds were blue. The reaction mechanism was generally believed to be the formation of a complex and color development. The iron chloride-like reaction was widely used to identify substances with enol structures. Sp2 hybrids were formed by one s orbital and two of the three p orbitals on the same layer. They were mostly used to form two single bonds and one double bond, which formed alkene, aldo, keto, and acyl in organic matter. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between red phosphorus and Cl2 would result in two reactions. The first reaction is the reaction of red phosphorus with Cl2 to form phosphorous tri-(2P +3Cl2) [2PCl3], and the phosphorus trichosphate was a colorless liquid; the phosphorus trichosphate then reacted with the Cl2 to form phosphorus pentachloride (<br><br>"<br>" 2PCl3 ", and the phosphorus trichosphate was a colorless liquid; the phosphorus trichosphate then reacted with the Cl2 to form phosphorus pentachloride (<br>" PCl3 + Cl2 "<br>" stacking " Phosphorous pentachlorides was a white solid. During the reaction process, the white solid particles of phosphorus pentachlorinate formed smoke, and the colorless liquid droplets of phosphorus tricolor formed fog, so the reaction phenomenon was white smoke. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the two substances would produce the compound, K [Fe(c o]], and the reaction would turn the solution green. This was because the complex formed by the formation of the iron and the iron were green in the solution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction conditions for the reaction of iron and Cl2 to form FeCl3 were as follows: - Under ignition, iron and Cl2 react to form FeCl3. The reaction equation is [2Fe3 + 3Cl2]{=[2Fe3 + 3Cl2]} 2FeCl_{3}\)。 - Under heating conditions, the dry iron combined with the Cl2 to form FeCl3. - Iron would undergo a passive reaction in the dry Cl2 at room temperature, and it would react in the humid Cl2. The reaction pathway and products would change with the conditions. When heated, the main reaction would be a chemical reaction to produce iron chloride-like iron. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The process of preparing a solution of iron chloride-based iron involves a reaction of water. Ferric acid is a strong acid and weak base salt. When it is dissolved in water, it will undergo a decomposition reaction: Fe3 ++3H2O == Fe3 (Ox)3+ 3H +. The solution will become turbid due to the formation of iron dioxide. In order to obtain a clear iron chloride-like solution, it was necessary to add sulfuric acid to suppress the decomposition reaction of iron chloride-like. The actual preparation method was to first dissolve the salt in diluted sulfuric acid, then add water to dilute it. This process was mainly based on the principle of the decomposition reaction, and the solution was prepared by adding sulfuric acid to suppress the decomposition. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The preparation method of the diallyl-ether of pentaerythrite includes adding into a reaction kettle, a dilute solution of the potassium ether and a three-phase phase transfer catalyst.(such as tbab/al2O3 three-phase phase transfer catalyst), stirring and raising the temperature under normal pressure, and then adding allylchlorideas a blocking agent to obtain the crude product of the diallylether. The subsequent operations such as filtering the mixture to recover the three-phase phase transfer catalyst, separating the water layer and the organic layer, removing the light boiling matter by normal pressure, and obtaining the product by reduced pressure, etc., still needed to be carried out. In the preparation of Pentaerythriol Allyl Ether, there was a method of reacting allyl-chloride-base-type catalyst and Pentaerythriol in a certain mole ratio under the effect of a phase transfer catalyst (such as, for example, the effect of the four groups of tributyl-amine). However, there were some shortcomings such as large equipment investment, low reaction conversion rate, large amount of waste water generated, high cost, and so on. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. * * Reaction equation and analysis of material properties ** - The composition of the water was complex. It contained Cl2, Cl2, and HClO. When the solution of Na2CO3 was mixed with water, the first reaction was: Cl2 + 2Na2CO3 + H2O = NaClO + NaClO +2NaHCO3. - Because of the participation of the Cl2 in the reaction, the yellowish-green color of the Cl2 water would gradually fade. - Gas was generated during the reaction because of the formation of CO2 (When the amount of Cl-water was excessive, the subsequent formation of Cl-and-NaHCO3 reacted with each other), so bubbles were observed. 2. * * Analysis of the change in the acidic and acidic properties of the solution ** - The solution of soda ash was basic. As the water was added, the reaction formed substances such as NaClO, NaHCO3, and so on. The basicity of the solution gradually weakened. - When there is an excess of Cl-water, the solution will eventually become acidic due to the large amount of Cl-water. 3. * * Impact analysis of hypochloric acid ** - Hypochloric acid has strong oxidisation and bleachability, but in this reaction system, the main reaction phenomenon is still determined by the reaction between Cl2 and Na2CO3 and the subsequent reaction between Cl2 and Na2HCO3. The effect of hypochloric acid is not obvious on the phenomenon, but mainly on the chemical properties of the solution. For example, it will produce an oxidisation effect on some reducing substances in the solution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There were components such as Cl2 and ClCl3 in the water. Metallic lithium is an active metal. When reacting with water, the first reaction of lithium with hydrogen is to form lithium chloride-based alloy (Mn + Cl2 = Mn). At the same time, the reaction of lithium with hydrogen is to form lithium chloride-based alloy (Mn + Cl2 = Mn + Cl2 + Mn). The reaction phenomenon was that the color of the chloride-water quickly faded, and tiny bubbles appeared on the surface of the strip. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>