The reaction between copper and copper was a typical replacement reaction. Because the copper sulfuric acid solution was slightly acidic, the reaction between copper and acid would release hydrogen gas, and copper would be separated in the form of copper trioxides, resulting in a settling phenomenon. Read more exciting novels for free
In junior high school chemistry, some white precipitations would react with sulfuric acid to produce gas, such as white precipitations such as CaCO2. When the reaction between calcium carbonite and sulfuric acid (HNO2) occurs, the chemical equation is CaCO2 + 2HNO2 = CaCO2 + HNO2 + CO2. The white deposit will gradually dissolve and bubbles will be produced. This is because the reaction produces carbon dioxide (CO2) gas. There was also the white deposit of calcium carbonate-Manganese dioxide, which reacted with sulfuric acid. Manganese carbonate-Manganese dioxide +2HNO-Manganese dioxide = Manganese dioxide (NO-Manganese dioxide)<anno data-annotation-id ="f1000000 - 4000 - 4000 - 4000 - 5000000000"> O </anno>+ O </anno></anno>. The white deposit also dissolved and bubbles emerged, which also produced carbon dioxide gas. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Anhydrous copper sulfuric acid can react with water to form copper sulfuric acid. After heating copper sulfuric acid to lose crystal water, it can be restored to blue crystal copper sulfuric acid if it is put into alcohol or water-containing organic matter. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between copper and sulfuric acid could be divided into two situations. If it was a reaction between copper and concentrated sulfuric acid, the phenomenon would be extremely obvious. The copper plate would quickly dissolve, and the solution would turn from colorless to blue-green. At the same time, a large amount of reddish-brown gas would be produced, which was nitrogen dioxide. What if copper reacted with dilute sulfuric acid? The copper would slowly dissolve, and the solution would turn blue, but the gas produced would be colorless nitrogen dioxide. However, the nitrogen dioxide would react with the oxygen in the air and turn into reddish-brown nitrogen dioxide. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The composition of the white deposit was different, and the phenomenon when it reacted with the sulfuric acid to form gas was also different. For example, when a white deposit such as CaCOreacted with sulfuric acid (HNO), the chemical equation was CaCO +2HNO = CaNO + CO2 ^+ CO2 ^H O. The reaction phenomenon was that the white deposit gradually dissolved and gas was produced at the same time. However, if the white deposit was silver chloride-silver (AgCl-silver), the silver chloride-silver deposit would not be dissolved in dilute sulfuric acid, so there would be no gas formation or other phenomena. Therefore, the reaction of the white deposit with the sulfuric acid to produce gas depended on the specific composition of the white deposit. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When a small amount of water was added, blue copper decahydrate crystals would be formed; when excessive water was added, the crystals would dissolve and form a blue solution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction of copper and copper sulfuric acid would not produce red copper. The reaction equation is 2Na +2H ^O + CuSO2 Na ^SO2 + CuOx ^+ H ^. Copper was a heavy metal element. Copper and its compounds were toxic when ingested in a certain amount. If excessive copper entered the human body, it would interfere with the normal physiological functions of the human body and cause damage to organs such as the liver and kidneys. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between copper dioxide and diluted sulfuric acid produced copper dioxide and water. The reaction equation was CuO + H2SO4 = CuSO4 + H2O. No gas was produced during this reaction, and no gas was produced when heated. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between iron (Iron) and copper (CuSO2) is a substitution reaction. Iron is more mobile than copper, and copper can be replaced. The reaction equation is: FeSO2 = FeSO2 + Cu2. The reaction phenomenon was: red substance (copper) was deposited on the surface of the iron layer, because copper was a red metal with metallic luster; the solution changed from blue (the color of copper sulfuric acid solution) to light green (the color of FeSO2 solution), and finally to brown. This was because the iron ions in the solution were unstable and would continue to be oxided into iron ions, and the iron ions in the solution would appear brown. From the reaction principle, the copper sulfuric acid solution was blue and weakly acidic, so the iron was corroded first, forming a pair of iron ions. At the same time, because the metal activity of iron was stronger than that of copper, a replacement reaction occurred, and the copper ions in the solution were replaced and reduced to copper. Because iron was a solid, after it was immersed in the copper sulfuric acid solution, the reaction occurred on the surface of the metallic iron, so the copper produced by the reaction would adhere to the surface of the metallic iron. If the immersion area was not large enough, and the concentration of the copper sulfuric acid solution was very high, the chemical reaction would stop when it reached a certain degree. The copper attached to the surface of the iron would protect the iron, so that it could not continue to react. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between copper dioxide and diluted sulfuric acid would cause such a phenomenon. Copper dioxide was a black solid. When it reacted with diluted sulfuric acid, the black copper dioxide would gradually dissolve, as if the small black particles were slowly disappearing. At the same time, the solution would slowly turn from colorless to blue. This was because the reaction between copper dioxide and diluted sulfuric acid produced copper sulfuric acid and water, and the copper sulfuric acid solution was blue. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
1. 首先分析镁和氧化铜反应: - 镁和氧化铜在加热条件下可能发生反应\(Mg + CuO=\!=\!=Cu + MgO\)。 2. 然后将反应后的固体加入足量硫酸中: - 如果镁过量,镁会和硫酸反应\(Mg + H_{2}SO_{4}=\!=\!=MgSO_{4}+H_{2}\uparrow\),会看到有气泡产生。 - 反应生成的氧化镁\(MgO\)也会和硫酸反应\(MgO + H_{2}SO_{4}=\!=\!=MgSO_{4}+H_{2}O\)。 - 若氧化铜有剩余,氧化铜与硫酸反应\(CuO + H_{2}SO_{4}=\!=\!=CuSO_{4}+H_{2}O\)。 - 如果之前反应生成了铜,铜与稀硫酸不反应。 综上,将足量硫酸加入镁和氧化铜反应后的固体中,可能会看到有气泡产生(镁过量时),反应后的溶液中会有硫酸镁、可能有硫酸铜等溶质,固体可能有铜(如果生成且未反应完)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>