If an aldo group can be oxided to a Carboxyl group under the condition of acidic Permanganate, for example, using Formalide as an example, the reaction equation may be: 4MnO4-+5HCho+2H+→ 5CO32-+4Mn2++6H2O; It may also be: 5HCho +4KMnO4 + 6H2SO4 → 5CO2 → +2K2SO4 + 4MnSO4 + 11H2O; Using Alcohol as an example, the reaction equation is: 2CH3- Cho+O2== catalyst, heating == 2CH3COON; Using p-methylethene as an example, the reaction equation is: 5CH3 - C6H4 - CH3+12MnO4-+36H+→5HOOC - C6H4 - COOH+12Mn2++28H2O。 Read more exciting novels for free
1. ** The equation for the reaction of alcohol and acidic potassium Permanganate to form a Carboxyl Group (using alcohol as an example)** - The reaction equation is: [5CH3CH20H +4KMnO4 + 6H2SO4 → 5CH3COON +4MnSO4 + 2K2SO4 + 11H2O]. 2. ** Formula for the reaction of an aldo with acidic potassium Permanganate to form a Carboxyl Group (Taking Cyclohexyl-Aldol as an example)** - The reaction equation is: [5C6H5Hamster +2KMnO4 + 3H2SO4 → 5C6H5COH +2MnSO4 + K2SO4 + 3H2O]. 3. ** Formula for the reaction of alkyne and acidic potassium Permanganate to form a Carboxyl Group (Take ethyne as an example)** - The reaction was divided into two steps. The first step was: <<CH> equiv> CH+2KMn> O4> 3H2SO4><2HCOH>+2Mn> O4>+ K2SO4>+2H2O>. The second step was: <<2HCOH>+ O2><2CO2>+2H2O>>. 4. ** The equation for the reaction of alkene and acidic potassium Permanganate to form a Carboxyl Group (Take ethene as an example)** - The reaction was divided into two steps. The first step was: <<CH2 = CH2>+<2KMn> O4>+<3H2SO4>+<2HCOON>+<2Mn> O4>+<K2SO4>+<2H2O>>. The second step was the further decomposition of the formated acid. In fact, the reaction was related to the decomposition of ethene by the acidic Permanganate. 5. ** Formula for the reaction of aromatic compounds containing side chains with acidic potassium Permanganate to form a Carboxyl Group (Toluene as an example)** - The reaction equation is: [5C6H5CH3 + 6KMnO4 + 9H2SO4 → 5C6H5COH +6MnSO4 + 3K2SO4 + 14H2O]. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction equation of KManganate and Manganic Sulphate is: 2KManganate +3Manganic Sulphate +2H <2> O = 5Manganic Sulphate +2H <2> Sulphate or 3Manganic Sulphate +2KManganic Sulphate +2H <2> O = 5H <2> Manganic Sulphate + K <2> Sulphate +2H <2> Sulphate. From the reaction equation, it was a neutral reaction. In the reaction, the Mn element in the potassium Permanganate was +7, the Mn element in the Manganic Sulphate was +2, and the Mn element in the Manganic Dioxid formed after the reaction was +4. During the reaction process, the different valences of the Mn element underwent an oxidoreduction reaction, causing the valency to return to +4. In terms of phenomena, the reaction would produce Manganese Dioxid, and the color of the solution might change or solid matter might be formed (Manganese Dioxid was a black solid). The specific phenomenon might also be affected by the reaction conditions (such as solution concentration, temperature, etc.). <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There are several equations for the reaction of potassium iodate: 1. In the presence of oxygen and water: 4Ki + O 2 + 2H 2 O == 4Mum +2I 2; 2. In the presence of oxygen and carbon dioxide: 4Ki + O 2 + 2CO 2 == 2K 2 CO +2I 2; 3. When the reaction between the two reagents is carried out, the iodines are oxided by the copper ions: 2CuSO2 + 4Ki == 2CuI + I Ü + 2K Ü SO2. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Permanganate is a strong oxidiser, and 18K gold is an alloy containing 75% gold and other metals such as copper, silver, etc. Under normal circumstances, a reaction might occur if the solution of potassium Permanganate came into contact with 18K gold. Because metals such as copper in 18K gold were relatively active, they were easily oxided by strong oxidisers, which might cause the surface of 18K gold to change color or be corroded. However, this also depended on the specific reaction conditions, such as the concentration of potassium Permanganate, the temperature of the reaction, the length of contact, and other factors. Therefore, in daily life, it was necessary to avoid 18K gold from coming into contact with strong oxidisers such as potassium permanganate. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction of the two reagents was described as follows: KNH2 + HCl3 = KC1 + NH3. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between sulfur dioxide and potassium Permanganate was the fading of the solution. The chemical equation of the reaction is: 2KMNO2 + 5SO2 + 2H2O = 2MNO2 + 2H2SO2 + K2SO2. Because the reduction product of potassium Permanganate has almost no color, and the sulfuric acid of sulfur dioxide is colorless, it will cause the color of the solution to fade. The reaction was usually carried out under acidic conditions. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The initial reaction of burning the skin with potassium Permanganate was mainly local redness and pain, but there might also be a burning sensation, which might also be accompanied by local redness and swelling. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Phosphorous acid had strong reducing properties, while potassium Permanganate had strong oxidisation properties. The two would undergo an oxido-reduction reaction. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When the acidic potassium Permanganate solution was used to catalyze the reaction of the two reagents, the alcoholic group would become an alcoholic group, and the alcoholic group would become a alcoholic group. The complete product containing the alcoholic group would then be the esh acid. If the acidic potassium Permanganate solution was used in excess, the reaction of the two reagents would eventually turn into CO2 and Ho. The reaction of the two reagents would depend on the amount of the acidic potassium Permanganate solution. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
硼砂中的\(Na_{2}B_{4}O_{7}\)在酸溶液中反应的离子方程式为:\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。其书写思路如下: 1. 首先确定反应物和生成物,硼砂\(Na_{2}B_{4}O_{7}\)与酸反应生成硼酸\(H_{3}BO_{3}\)。 2. 然后根据物质的组成写出其离子形式,\(Na_{2}B_{4}O_{7}\)可拆分为\(B_{4}O_{7}^{2 -}\),酸中的氢离子\(H^{+}\)参与反应,反应后生成\(H_{3}BO_{3}\)(硼酸为弱酸,在离子方程式中写分子式)。 3. 根据电荷守恒和原子守恒配平离子方程式,得到\(B_{4}O_{7}^{2 -}+2H^{+}+5H_{2}O = 4H_{3}BO_{3}\)。 <a href="/?from=ask_words" style="color:red" target="_blank">点击前往免费阅读更多精彩小说</a>