When the iodine-containing solution came into contact with the starch, the iodine-containing solution would appear blue; when the iodine-containing solution came into contact with the starch, the iodine-containing solution would appear purple-red; when the iodine-containing solution came into contact with the starch, the iodine-containing solution would appear blue-purple, purple, orange and other colors. When the chain length of the starch-iodate complex was less than 6 glucose groups, it would not show color; when the average chain length was 20 glucose groups, it would show red; and when the chain length was greater than 60 glucose groups, it would show blue. Read more exciting novels for free
Amylose can be divided into starch and starch. When the iodine-containing solution came into contact with the starch, the starch had a long glycan chain that could bind more iodine-containing molecules, and the central hole of the starch could accommodate the iodine-containing molecules. The blue-black complex was formed through the van der Waals force, which was usually blue in color. And when the solution came into contact with the starch, it would form a complex due to the van der Waals force, but the color was purple-red. In addition, the color reaction was also related to the length of the sugar chain in the starch. When the length of the sugar chain was less than 6 sugar units, it could not form a spiral ring, so it could not be colored; when the length of the sugar chain was 20 sugar units, it was red; when the length of the sugar chain was greater than 60 sugar units, it was blue. In actual experiments, due to the type of starch, the complexity of the structure, and other factors, blue-purple, purple, orange, and ochre colors may also appear. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
Vitamin C (C H O) had extremely strong reducing properties, and the solution of iodination had an oxidisation property. When the two were mixed, a oxidoreduction reaction would occur. The reaction equation was: C H O (vitamins C and Ascorbic acid)+I 2 = C H O (dehydrated Ascorbic acid)+2Hi. In this reaction, the carbon dioxide reduced the iodine-like molecules, causing the color of the iodine-like solution to change from reddish-brown to colorless and transparent. This was because the iodine-like molecules were reduced to iodine-like ions, which were colorless. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between the acid and the acid was to form a sulfuric acid deposit. The reaction equation was Na 2 SiO2 +2HNO2 == H 2 SiO2 +2NaNO2. No colloid solution was formed, so the color of the colloid solution did not change. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When iron reacted with copper sulfuric acid, the solution first turned blue, then from blue to light green, and finally the solution turned brown. Red substances were separated from the surface of the iron. This was because iron was more mobile than copper. It could replace copper and react to form iron and copper. The solution itself was blue. As the reaction progressed, the copper ions were replaced, and the resulting FeSO4 gradually turned the solution into a light green color. However, the final brown color of the solution could be due to the complex chemical environment or further oxidization during the reaction process, but there was not enough information to determine the exact mechanism. Since no suitable illustration was found, the illustration of the color change pattern could not be provided. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction between acid and base solution may change color, which can be judged by the different colors of the acid, base, and neutral solutions. The principle of the color change of the alkali-base indicator was that the alkali-base indicator was some organic weak acid or organic weak base. In the solution, they could be partially dissociated into the indicator's ions and hydrogen ions (or hydrogen ions). Due to the change in structure, the molecules and ions had different colors, so they would display different colors in different alkali-base solutions. For example, when the sulfuric acid concentration in the solution was reduced, it would turn red when the sulfuric acid concentration increased. When acid and base react, the solution's pH-value will change, which will cause the acid and base indicator to gain a proton and transform from basic to the conjugated acid, or lose a proton and transform from acid to the conjugated base. Due to the change of its structure, the color will change. This color change is a chemical change, because the acid and base indicator is generally an organic weak acid or weak base. They are weakly ionised in water. The added acid or base will be ionised to produce H or Oh, which will cause the combination of the two to move to the equilibrium of ionisation and dehydration. It caused the ratio of ions to substances in the original solution to change and present different colors. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
When iron reacted with copper sulfuric acid, the copper ions in the solution were replaced by iron to form iron sulfuric acid. At the beginning of the reaction, the copper sulfuric acid solution was blue. As the reaction progressed, the color of the solution gradually changed from blue to light green, and finally to brown. This was because the copper sulfuric acid solution was blue and weakly acidic. At the beginning of the reaction, the iron was corroded and formed the secondary iron ions. The secondary iron ion solution was light green, so the solution changed from blue to light green. Since iron was more active than copper, a replacement reaction occurred. The copper ions in the solution were replaced and reduced to copper (red) attached to the iron surface. Subsequently, the iron ions in the solution were unstable and would continue to be oxided into iron ions. The iron ions in the solution were brown, so the solution turned from light green to brown. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
The reaction of acid and base solution itself would not change color, but if an acid and base indicator was added, the acid and base indicator would change color due to the reaction of acid and base solution. This was because the acid and base indicators were generally organic weak acid or organic weak base. In the solution, they could be partially ionised into the indicator's ions and hydrogen ions (or hydrogen ions). Due to structural changes, the molecules and ions had different colors. Therefore, in different acid and base solutions, they would display different colors. For example, methylethalin was colorless in an acidic solution, but when the concentration of H in the solution decreased and the concentration of Oh increased, it became red; litmus was red in an acidic solution, blue in an basic solution, and purple in a neutral solution. The reason why the acid and the base stopped reacting after the reaction was because the hydrogen ion (H) in the acid and the hydrogen ion (H) in the base combined to form water (H O). When the acid and the base completely reacted according to the chemical ratio, there was no excess hydrogen ion or hydrogen ion in the solution, and the reaction reached an equilibrium state, so the reaction stopped. For example, the reaction between sulfuric acid (HQ) and sulfuric acid (NaOx): HQ + NaOx = NaCl2 + H ^O. When the ratio of the substances of the two substances is 1:1, the reaction will be complete, and the reaction will stop when the production of NaCl2 and water is completed. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
During the synthesis of the hormone, there was a close relationship between the reaction between the two. After the oral intake of iodines was taken up by the thyreoids, it was oxided to "active iodines" under the catalyze of thyreobin (TPo). Then, the "active iodines" combined with the Tyr residue on the thyreobin (TL) to form one iodoTyr and two iodoTyr. Two molecules of diiodoTyr were condensed into T4, and one molecules of diiodoTyr and one molecules of one iodoTyr were condensed into T3. When there is an excess of iodination, the excess iodination will compete with the persimmon, which may inhibit the activity of the persimmon, resulting in a decrease in the synthesis of the hormone. At the same time, it may also inhibit the release of the hormone, resulting in hypoplasia. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>
There were different opinions on whether or not the reaction between the two substances occurred. One view was that silver chloride-soda would react to produce silver-white silver silver precipitations and NaCl2, and the silver-white precipitations could easily be converted to brown silver oxide-soda. The other view was that the reaction could not be carried out because the reaction between base and salt required the salt to be dissolved, while AgCl2 was difficult to dissolve. <a href="/?from=ask_words" style="color:red" target="_blank">Read more exciting novels for free</a>