Wang Qiang read a book for the first four days, eight pages a day, and then a total of 17 pages for the next three days. We can split this situation into two parts for analysis: Reading eight pages a day for the first four days meant that Wang Qiang had already read $4/times 8 = 32$pages in the first four days. Reading a total of 17 pages in the last 3 days meant that Wang Qiang had read another $3/17 = 54$page in the last 3 days. Therefore, Wang Qiang read a total of $32+54=86$pages. Next, we need to calculate how many pages he reads on average every day. Did he read all the books in the first four days and the last three days together? If that was the case, then the average number of pages he read every day was $86/4+17/3=265+5=315$pages. If not, then the average number of pages he read every day was $86/4-17/3=26-5=21$pages. Therefore, Wang Qiang read an average of 21 pages a day.
Xiaoming read a book for the first four days, on average, he read eight pages a day. In the first four days, he read a total of 8 × 4 = 32 pages. In the next two days, he read a total of 48 pages, which means that in the remaining time, Xiaoming read an average of 48/7 = 8 pages per day. Therefore, Xiao Ming spent the rest of his time reading an average of 8 - 8 = 0 pages a day. In other words, Xiao Ming had already finished reading the book, so he read an average of 0 pages a day.
According to the knowledge of online literature enthusiasts, it was difficult to come up with a conclusion as to who read faster because everyone's progress was different at different times. Xiao Hong only reads 170 pages a day while Xiao Ming only reads 240 pages a day, which means that Xiao Hong is reading faster than Xiao Ming. However, Little Red only had 12 days while Little Ming had 17 days. Therefore, Little Ming had a longer reading time and progress. In addition, Cockroach read 300 pages between the ages of 27 and 8, which means that his speed may be faster than Xiao Hong and Xiao Ming. Therefore, it was impossible to simply answer the question of who read faster.
Little Red reads a book 15 pages a day, and after 4 days, there is still 3/5 of the book left. We can assume that this book has x pages. According to the question, Little Red had read a total of $4/times 15 = 60$pages in 4 days. The remaining pages are 3/5 of the book, so there are: $$ 60\div 3/5=24 $$ Therefore, the book had 24 pages.
Assuming that the book has a total of $x$pages, then Little Red has read $x/times 15$pages in 4 days. The remaining pages are 3/5 of the book's worth, so there are: $$x <times 15><times 3/5>= Total pages $$ Solve this equation: $$x = \frac{total pages}{15} = \frac{1200}{15} = 80$$ Therefore, the book had a total of 80 pages.
Wang Xiaoming read 30 pages on the first day of reading a book. According to the plot of the novel, the first few pages would usually be read on the first day because curiosity and interest would motivate the reader to start reading as soon as possible. The 30 pages might be the beginning of the story or an important part of the plot, which was why Wang Xiaoming finished reading the 30 pages on the first day. Wang Xiaoming would probably continue to read as the story developed. If this book was a classic novel, Wang Xiaoming would probably continue reading until he finished the story.
Xiao Le read an average of 18 pages a day.
Assuming the book has a total of n pages, Lili read 78 pages in the first 3 days, then there are still n - 3 × 78 = n - 262 pages not read. In the next four days, she read an average of 40 pages a day. In these four days, Lili read a total of 40 × 4 = 160 pages. Therefore, Lili had read a total of n - 262 + 160 = 322 pages, just enough to finish the book. So this book had 322 pages.
Suppose the book has x pages: Little Cong read 15 pages a day for four days, a total of 4×15=60 pages. The total number of pages in the book is x, so: 60÷(1+3/5)=x÷5 The solution was:x=60×5 div3 =600 div3 =200 pages. Therefore, the book had a total of 200 pages.
Little Red reads 15 pages a day for 4 days and still has 3/5 of the book left. She can write the following equation: Remaining pages/pages per day = 3/5 of the book Solve the equation: Remaining pages = 3/5 x pages of the book Substituting the remaining pages into the original book's page count, he obtained: 3/5 x pages of the book = 15 pages Therefore, this book had: 15 pages × 3/5 = 15 pages/3/5 = 150 pages
The loan period for this book was 30 days.