If Xiaoming reads a storybook, he reads 38 pages in the first 2 days and 54 pages in the next 3 days. How many pages does Xiaoming read on average every day?Xiao Ming read a story book and read a total of 38 pages in the first two days and 54 pages in the next three days. We can use the total number of pages to deduct the number of pages in the first two days and the next three days to get the average number of pages that Xiaoming reads every day.
Total pages = 38 + 54 = 82
In the previous two days, he had read 38 pages, so the ratio of the number of pages read in the previous two days to the total number of pages was 38 pages/ 82 pages = 047875, which could be approximately expressed as 047875.
In the next three days, a total of 54 pages were read. The ratio of the number of pages read in the next three days to the total number of pages was 54 pages/ 82 pages = 06667, which could be approximately expressed as 06667.
Therefore, on average, Xiaoming reads 047875 × 2 + 06667 × 3 = 016533 × 2 + 023333 × 3 = 039167 × 2 + 050938 × 3 = 089715 × 2 + 010785 × 3 = 1575 × 2 + 0192 × 3 = 27533 every day, which is about 275.
Therefore, Xiao Ming read an average of 275 pages a day.
When Teacher Zhang reads a book, he reads an average of 20 pages a day for the first 4 days, and 63 pages in total for the next 7 days. He just finishes reading this book. How many pages does Teacher Zhang read on average every day?Assuming that the book has a total of n pages, then Teacher Zhang has read 20×4=80 pages in the past four days, leaving n-80 pages.
In the next 7 days, he read 63 pages, so the remaining pages were 63-80=-3 pages. This result is negative, which is not consistent with reality, so there is a contradiction in the hypothesis.
Therefore, this problem is not solved. Teacher Zhang reads an average of 80 pages a day, but he has read 20 pages in the past four days, so he still needs to read another 40 pages to finish the book.
If Xiaoming reads a novel and reads 35 pages a day, he will finish the book one day later than the stipulated date. If he reads 40 pages a day, he will read 5 pages less on the last day…Xiao Ming reads a novel. If he reads 35 pages a day, he will finish the whole book one day later than the stipulated date. If he reads 40 pages a day, he will read 5 pages less on the last day.
We can set the total number of pages of the novel as x and the specified date as d, then the total number of pages that Xiaoming needs to read is x/35 + x/40 - 1.
According to the question, Xiaoming needs to read d books, so there are:
x/35 + x/40 - 1 = d
Transferring the terms of the equation gave:
x/100 = d
Therefore, Xiao Ming needed to read 100 pages a day to finish the novel by the stipulated date. If you read 35 pages a day, you would need an extra two days to finish the novel. If you read 40 pages a day, you would need an extra three days to finish the novel.
After considering all, Xiaoming needed to read 37 pages a day to finish the novel according to the stipulated date. On the last day, he had to read 5 pages less.
Xiaoming read a book for the first four days and read an average of eight pages a day. After two days, he read a total of 48 pages. How many pages did he read per day?Xiaoming read a book for the first four days, on average, he read eight pages a day. In the first four days, he read a total of 8 × 4 = 32 pages.
In the next two days, he read a total of 48 pages, which means that in the remaining time, Xiaoming read an average of 48/7 = 8 pages per day.
Therefore, Xiao Ming spent the rest of his time reading an average of 8 - 8 = 0 pages a day. In other words, Xiao Ming had already finished reading the book, so he read an average of 0 pages a day.
The number of pages that Xiaoming reads on the first day is 20% of the whole book. The next day, he reads 20% of the remaining pages. The number of pages that he reads on the second day accounts for 100% of the total pages of the whole book.The number of pages that Xiaoming reads on the first day is 20% of the whole book. The number of pages that he reads on the second day is 20% of the remaining pages. The percentage of the number of pages that he reads on the second day can be calculated as follows:
The number of pages that Xiaoming read on the first day was 20% of the entire book. In other words, the total number of pages that Xiaoming read was:
Total pages = 20% × pages of the book = 02 × pages of the book
The number of pages that Xiao Ming read the next day was 20% of the remaining pages. In other words, the total number of pages that Xiao Ming read was:
Total pages = 20% x Remaining pages = 02 x Remaining pages
Then, the percentage of the number of pages that Xiao Ming read the next day in the total number of pages in the book can be calculated as:
The number of pages Xiao Ming read the next day divided by the total number of pages in the book × 100% = 02 divided by 08 × 100%= 25%
Therefore, the number of pages that Xiao Ming read the next day accounted for about 25% of the total number of pages in the entire book.