Why are there fewer female engineers than male engineers?There were fewer female engineers than male engineers mainly because of the following reasons:
1. ** Education and Major Choice **: There were far more boys than girls studying engineering related majors such as mechanical electronics. Many girls were unwilling to choose such majors, resulting in fewer female backup talents in the engineering field.
2. ** Obstacles in the workplace and differences in treatment **: When looking for a job, women tend to encounter more obstacles, and with the same academic qualifications, the salary of female engineers may be lower than that of men, which makes many women unwilling to work as engineers.
3. ** Social Concepts and Gender-based Stigmata **: The traditional view is that technical work is physical work and not suitable for women. It is believed that women's physical conditions are not compatible with technical work, and women are more engaged in lighter work. This concept limited the development of women in engineering.
4. ** Work intensity and physiological factors **: Some engineering jobs are intense, stressful, and require frequent overtime and staying up late. For example, software development work. From physical and physiological considerations, it is difficult for women to withstand such high-intensity workload. Long-term overtime and staying up late will also have a greater impact on women's health.
5. ** Ability Awareness and Professional Development **: There is a prejudice against women's technical ability in society. For example, women are thought to be poor in development and are easily eliminated. This concept affects the career development opportunities of women in the engineering field.
6. "** Different opportunities for industry exposure **: For example, in the field of construction costs, men are more likely to come into contact with engineering examples, so they have more understanding of processes and techniques. This also makes men more advantageous in related engineering fields.
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2 dice probabilityFor two dice, there were several possibilities:
1. ** Single number probability **:
- Each die had six sides, and the numbers were 1, 2, 3, 4, 5, and 6. When a die is rolled, the probability of each number appearing is 1/6. When two dice were thrown, for example, the probability of both dice rolling a 1 was 1/6. Therefore, the probability of both dice rolling a 1 (the combination of 1 and 1) was (1/6)×(1/6)=1/36. Similarly, any particular combination of numbers (such as 3 and 5) has a probability of 1/36.
2. ** Point sum probability **:
- The sum of the points was 2 (1 + 1), and there was only one possibility. The probability was (1/6)×(1/6)=1/36.
- The sum of the points is 3 (1+2 or 2 + 1). There are two possibilities, and the probability is 2/36.
- The sum of the points was 4 (1+3, 2+2, 3+1). There were 3 possibilities, and the probability was 3/36.
- The sum of the points is 5 (1+4, 2+3, 3+2, 4+1). There are 4 possibilities, and the probability is 4/36.
3. ** Dice size probability (1 - 6 is small, 7 - 12 is big)**:
- There were a total of 6x6 = 36 combinations of the two dice. Among them, there were 15 situations where the sum of points was 1 - 6 (small), and 21 situations where the sum of points was 7 - 12 (large). However, since it was impossible for two dice to have a point, the probability of a small point appearing was 5/11 (about 45.45%), and the probability of a big point appearing was 6/11 (about 54.55%).
4. ** The probability that the sum of the two dice numbers is odd (assuming the first die numbers are 1, 2, 3, 3, 5, 6, and the second die numbers are 1, 2, 4, 4, 5, 6)**:
- For the first die, the probability of an odd number appearing was 4/6 = 2/3, and the probability of an even number appearing was 1/3. For the second die, the probability of an odd number appearing was 2/6 = 1/3, and the probability of an even number appearing was 2/3. To get the odd sum, there are two situations: if the first die is odd and the second die is even, the probability is 2/3×2/3 = 4/9; if the first die is even and the second die is odd, the probability is 1/3×1/3 = 1/9. Therefore, the total probability was 4/9+1/9 = 5/9.
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Increases the probability of 10 to 11The probability of a normal non-safe buff was between 10% and 30%, depending on the equipment's quality, level, enchantment, and strengthening level. The probability of a safe buff was between 3% and 10%, but there was no separate probability of a 10 to 11 buff.
I just want to ask the author of his background in math particularly statistics. I am quite interested in PDF estimation using Kernel Functions, but I am not really familiar with Bayesian something. I am solving these equations for me to be able to approximate the PDF for a research study of mine for Social Science about the relationship of distance of dorm rooms and the probability of friendship. It will also serve as practice for me to be able to use the Kelly Criterion by plugging a PDF instead of just a constant. I will maximize the growth of investment that way even if the probability has some level of uncertainty. I am also delving into Beta Distributions. Actually, I rarely have an internet connection so I rediscovered it myself. Anyways, the point of my comment is not to flex, but to find a colleague that has the same interests. Namely earning money by analyzing probability distribution functions.