If there was a 1000-page book and 40 pages were torn out, could the sum of all the page numbers of these 40 pages be 2021?

Answer 1

This question involves some calculations and logical reasoning. I can try to give a reasonable answer.

Assuming that each page of the 1000-page book has a page number, the sum of all the page numbers on the 40 pages can be expressed as:

40 sheets x total page number of 40 sheets = 40 x 1000 = 40000 page numbers

Now we add up the 40000 pages:

40000 pages + 1 page = 40101 pages

Please note that we are assuming that each page has a unique page number. If some of these 40 sheets of paper do not have corresponding page numbers, then these page numbers will appear on other sheets of paper, and their sum may be different.

So if we can't determine the exact order and number of these pages, we can't be sure if the sum of these pages will equal 2021. But if we assume that each page has a unique page number and that these page numbers are arranged in order, then we can calculate the sum of all the page numbers in these 40 pages:

40 sheets x total page number of 40 sheets = 40 x 1000 = 40000 page numbers

The sum of all page numbers = 40000 page numbers + 1 page = 40101 page numbers

Therefore, if every page has a unique page number and these page numbers are arranged in order, then the sum of all the page numbers in these 40 pages cannot be equal to 2021.